英文:
Concurrent routines in Go
问题
package main
import "rand"
func Routine1(commands chan int, responses chan int, command chan int, response chan int ) {
for i := 0; i < 10; i++ {
i := rand.Intn(100)
commands <- i
command <- i
print(<-responses, " 12st\n");
print(<-response, " 13st\n");
}
close(commands)
}
func Routine2(commands chan int, responses chan int) {
for i := 0; i < 1000; i++ {
x, open := <-commands
if !open {
return;
}
print(x , " 2nd\n");
y := rand.Intn(100)
responses <- y
}
}
func Routine3(command chan int, response chan int) {
for i := 0; i < 1000; i++ {
x, open := <-command
if !open {
return;
}
print(x , " 3nd\n");
y := rand.Intn(100)
response <- y
}
}
func main() {
commands := make(chan int)
responses := make(chan int)
command := make(chan int)
response := make(chan int)
go Routine1(commands, responses,command, response )
Routine2(commands, responses)
Routine3(command, response)
}
英文:
I want to write three concurrent routines that sends integer to each other. Now, I have implemented two concurrent routines which sends integers to each other.
package main
import "rand"
func Routine1(commands chan int, responses chan int) {
for i := 0; i < 10; i++ {
i := rand.Intn(100)
commands <- i
print(<-responses, " 1st\n");
}
close(commands)
}
func Routine2(commands chan int, responses chan int) {
for i := 0; i < 1000; i++ {
x, open := <-commands
if !open {
return;
}
print(x , " 2nd\n");
y := rand.Intn(100)
responses <- y
}
}
func main()
{
commands := make(chan int)
responses := make(chan int)
go Routine1(commands, responses)
Routine2(commands, responses)
}
However, when I want to add another routine which wants to send and receive integers to/from the above routines, it gives errors like "throw: all goroutines are asleep - deadlock!". Below is my code:
package main
import "rand"
func Routine1(commands chan int, responses chan int, command chan int, response chan int ) {
for i := 0; i < 10; i++ {
i := rand.Intn(100)
commands <- i
command <- i
print(<-responses, " 12st\n");
print(<-response, " 13st\n");
}
close(commands)
}
func Routine2(commands chan int, responses chan int) {
for i := 0; i < 1000; i++ {
x, open := <-commands
if !open {
return;
}
print(x , " 2nd\n");
y := rand.Intn(100)
responses <- y
}
}
func Routine3(command chan int, response chan int) {
for i := 0; i < 1000; i++ {
x, open := <-command
if !open {
return;
}
print(x , " 3nd\n");
y := rand.Intn(100)
response <- y
}
}
func main() {
commands := make(chan int)
responses := make(chan int)
command := make(chan int)
response := make(chan int)
go Routine1(commands, responses,command, response )
Routine2(commands, responses)
Routine3(command, response)
}
Can anybody help me, where is my mistake ? And can anybody help me, is it possible to create bidirectional channel or is it possible to create a common channel for int, string etc ?
答案1
得分: 2
你没有在main函数中声明command和response变量。
func main() {
commands := make(chan int)
responses := make(chan int)
go Routine1(commands, responses, command, response)
Routine2(commands, responses)
Routine3(command, response)
}
英文:
You haven't declared the command and response variables in the main function.
func main() {
commands := make(chan int)
responses := make(chan int)
go Routine1(commands, responses, command, response)
Routine2(commands, responses)
Routine3(command, response)
}
通过集体智慧和协作来改善编程学习和解决问题的方式。致力于成为全球开发者共同参与的知识库，让每个人都能够通过互相帮助和分享经验来进步。
评论