英文:
compare the files based on the first column of file1 and print the row which are not in other files
问题
Xavier 12 30
Ram 34 57
Jancy 56 34
英文:
I have 7 files and would like to compare the first column of file1. I want to print the row if the first column's name from file1 does not appear in any other files.
file 1peter 10 300Xavier 12 30Jack 123 67Ram 34 57Jancy 56 34Thomson 56 67file2Jack 23 67peter 12 39file3Jack 123 67peter 15 45Thomson 35 430
I would like to get the following output
Xavier 12 30Ram 34 57Jancy 56 34
Your suggestions would be appreciated. Thank you.
答案1
得分: 1
这是我的建议：
grep -v $(printf '-e ^%s ' $(cut -d ' ' -f 1 file2 file3 | sort -u)) file1
希望有所帮助。
英文:
this is my suggestion:
grep -v $(printf '-e ^%s ' $(cut -d ' ' -f 1 file2 file3 | sort -u)) file1
Hope that helps.
答案2
得分: 0
$ awk 'FILENAME != "file1" {a[$1]; next} !($1 in a)' file[2-6] file1
Xavier 12 30
Ram 34 57
Jancy 56 34
英文:
$ awk 'FILENAME != "file1" {a[$1]; next} !($1 in a)' file[2-6] file1Xavier 12 30Ram 34 57Jancy 56 34
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