英文:
awk to separate rows from bed files depending on character
问题
我想将一列中的行使用逗号分隔符分开，并保留行的其他信息。我有一个包含4列和大量行的制表符分隔文件...
从这里：
1 13445 rs558318514 C G,T 1_13445
1 13453 rs568927457 T C 1_13455
1 13483 rs554760071 G A,C 1_13483
1 13550 rs554008981 G A 1_13550
到这里：
1 13445 rs558318514 C G 1_13445
1 13445 rs558318514 C T 1_13445
1 13453 rs568927457 T C 1_13453
1 13483 rs554760071 G A 1_13483
1 13483 rs554760071 G C 1_13483
1 13550 rs554008981 G A 1_13550
英文:
I want to separate rows by comma delimiter in one filed and keep the other information of the row. I have tab delimited files with 4 columns and a lot of rows...
Frome here:
1 13445 rs558318514 C G,T 1_13445
1 13453 rs568927457 T C 1_13455
1 13483 rs554760071 G A,C 1_13483
1 13550 rs554008981 G A 1_13550
To here:
1 13445 rs558318514 C G 1_13445
1 13445 rs558318514 C T 1_13445
1 13453 rs568927457 T C 1_13453
1 13483 rs554760071 G A 1_13483
1 13483 rs554760071 G C 1_13483
1 13550 rs554008981 G A 1_13550
答案1
得分: 1
Sure, here is the translated code portion:
$ awk '{n=split($5,a,","); for(i=1; i<=n; i++){$5=a[i]; print}}' file
1 13445 rs558318514 C G 1_13445
1 13445 rs558318514 C T 1_13445
1 13453 rs568927457 T C 1_13455
1 13483 rs554760071 G A 1_13483
1 13483 rs554760071 G C 1_13483
1 13550 rs554008981 G A 1_13550
英文:
$ awk '{n=split($5,a,","); for(i=1; i<=n; i++){$5=a[i]; print}}' file
1 13445 rs558318514 C G 1_13445
1 13445 rs558318514 C T 1_13445
1 13453 rs568927457 T C 1_13455
1 13483 rs554760071 G A 1_13483
1 13483 rs554760071 G C 1_13483
1 13550 rs554008981 G A 1_13550
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