英文:
remove duplicate coordinates from X and Y column
问题
根据以下数据，如何删除具有重复的 X 和 Y coordinates 的行？在下面的示例中，您将注意到 X 坐标之一是 -1.52，它重复了 两次，但它不是重复的，因为它对应的 Y 坐标是不同的。
我不知道这是否重要，但请注意，原始数据集的X和Y值有 2 位以上的小数位。
样本数据：
structure(list(id = c(1, 2, 3, 4, 5, 6, 7, 8, 9, 10), X = c(-1.01,-1.11, -1.11, -2.13, -2.13, -1.52, -1.52, -1.98, -3.69, -4.79),Y = c(2.11, 3.33, 3.33, 6.66, 6.66, 7.77, 8.88, 9.99, 1.11,6.68)), class = "data.frame", row.names = c(NA, -10L))
期望的数据：
id X Y1 -1.01 2.112 -1.11 3.334 -2.13 6.666 -1.52 7.777 -1.52 8.888 -1.98 9.999 -3.69 1.1119 -4.79 6.68
英文:
Based on the data below how can I remove the rows with duplicate X and Y coordinates? In the example below, you will notice that one of X coordinate is -1.52 which is repeated twice but it's not a duplicate since it's corresponding Y coordiantes are different.
I don't know if it matters but please note that the orginal dataset has more than 2 decimal places for the X and Y values.
Sample data:
structure(list(id = c(1, 2, 3, 4, 5, 6, 7, 8, 9, 10), X = c(-1.01,-1.11, -1.11, -2.13, -2.13, -1.52, -1.52, -1.98, -3.69, -4.79),Y = c(2.11, 3.33, 3.33, 6.66, 6.66, 7.77, 8.88, 9.99, 1.11,6.68)), class = "data.frame", row.names = c(NA, -10L))
Desired data:
id X Y1 -1.01 2.112 -1.11 3.334 -2.13 6.666 -1.52 7.777 -1.52 8.888 -1.98 9.999 -3.69 1.1119 -4.79 6.68
答案1
得分: 1
使用 duplicated 函数：
subset(df1, !duplicated(df1[-1]))
输出结果：
id X Y1 1 -1.01 2.112 2 -1.11 3.334 4 -2.13 6.666 6 -1.52 7.777 7 -1.52 8.888 8 -1.98 9.999 9 -3.69 1.1110 10 -4.79 6.68
或者使用 distinct 函数：
library(dplyr)df1 %>%distinct(X, Y, .keep_all = TRUE)
英文:
Use duplicated
subset(df1, !duplicated(df1[-1]))
-output
id X Y1 1 -1.01 2.112 2 -1.11 3.334 4 -2.13 6.666 6 -1.52 7.777 7 -1.52 8.888 8 -1.98 9.999 9 -3.69 1.1110 10 -4.79 6.68
Or with distinct
library(dplyr)df1 %>%distinct(X, Y, .keep_all = TRUE)</details>
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