ValueError: 无法将字符串转换为浮点数: ‘ ‘ python

huangapple
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英文:

ValueError: could not convert string to float: ' ' python

问题

以下是您的翻译内容：

  1. 我有这个文件
  3. 1
  4. 1
  5. GALAXY S10
  6. 1000
  7. MOVIL
  8. 1
  9. 1
  10. 2
  11. 2
  12. IPHONE
  13. 1200
  14. MOVIL
  15. 2
  16. 2
  17. 3
  18. 3
  19. MAC
  20. 1400
  21. ORDENADOR
  22. 2
  23. 3
  25. 我的代码：
  27. listProducto1 = [1,"GALAXY S10", 1000, "MOVIL",1,1]
  28. listProducto2 = [2,"IPHONE", 1200, "MOVIL",2,2]
  29. listProducto3 = [3,"MAC", 1400, "ORDENADOR",2,3]
  31. diccProductos = {1:listProducto1,2:listProducto2,3:listProducto3}
  32. diccAuxiliar ={}
  34. f=open(fichero,"w")
  35. for clave in diccProductos.keys():
  36.     f.write(str(clave)+"\n")
  37.     for valor in diccProductos.keys():
  38.         f.write(str(diccProductos[clave][valor-1])+"\n")
  39. f.close()
  41. f=open(fichero,"r")
  42. lineas=f.read().split("\n")
  43. contador=0
  45. for linea in lineas:
  46.     if (contador==0):
  47.         varAux=str(linea)
  48.         #varAux=linea
  49.         #varKey = int(float(varAux))
  50.         #varKey = int(varAux)
  51.         print(contador,varAux)
  52.         diccAuxiliar[varAux]=[]
  53.     else:
  54.         varValor=linea
  55.         print("contador: ",contador," |valor :",varValor)
  56.         diccAuxiliar[varAux].append(varValor)
  57.     contador+=1
  59.     if (contador==7):
  60.         contador=0
  62. print(diccAuxiliar["1"][3])
  64. 要找到键，我必须使用字符串，但我想要使用整数，当我使用var = int(line)时出错，我尝试使用float
  66. 我的想法是将包含列表的字典传递给文件，然后将文件读取出来，使其可视化，以继续使用该字典而不使用pickle、csv、json等。

请注意，您的代码中包含了HTML实体（如"），我已将其还原为正常的双引号。如果您需要更多帮助或有其他问题，请随时提出。

英文:

i have this in file

  1. 1
  2. 1
  3. GALAXY S10
  4. 1000
  5. MOVIL
  6. 1
  7. 1
  8. 2
  9. 2
  10. IPHONE
  11. 1200
  12. MOVIL
  13. 2
  14. 2
  15. 3
  16. 3
  17. MAC
  18. 1400
  19. ORDENADOR
  20. 2
  21. 3

my code:

  1. listProducto1 = [1,"GALAXY S10", 1000, "MOVIL",1,1]
  2. listProducto2 = [2,"IPHONE", 1200, "MOVIL",2,2]
  3. listProducto3 = [3,"MAC", 1400, "ORDENADOR",2,3]
  5. diccProductos = {1:listProducto1,2:listProducto2,3:listProducto3}
  6. diccAuxiliar ={}
  8. f=open(fichero,"w")
  9. for clave in diccProductos.keys():
  10.     f.write(str(clave)+"\n")
  11.     for valor in diccProductos.keys():
  12.         f.write(str(diccProductos[clave][valor-1])+"\n")
  13. f.close()
  15. f=open(fichero,"r")
  16. lineas=f.read().split("\n")
  17. contador=0
  19. for linea in lineas:
  20.     if (contador==0):
  21.         varAux=str(linea)
  22.         #varAux=linea
  23.         #varKey = int(float(varAux))
  24.         #varKey = int(varAux)
  25.         print(contador,varAux)
  26.         diccAuxiliar[varAux]=[]
  27.     else:
  28.         varValor=linea
  29.         print("contador: ",contador," |valor :",varValor)
  30.         diccAuxiliar[varAux].append(varValor)
  31.     contador+=1
  33.     if (contador==7):
  34.         contador=0
  36. print(diccAuxiliar["1"][3])

to find the key I have to use string and I want to use an integer, when I do var = int (line) it is my mistake, I tried to use float

My idea is to pass a dictionary that contains a list to a file and then take the file and make it visceverous to continue working with that dictionary without using pickle, csv, json, etc.

答案1

得分: 0

你的代码可以更加简洁，如果你只使用一个列表的列表。采用这种方法，你的第一个产品将从0开始，而不是1，并且输出文件中每个产品将有6行，而不是7，就像你发布的代码中那样。

以下是使用Python 3.6+（因为使用了f-strings）实现我描述的概念的解决方案：

  1. from pathlib import Path
  3. products = [
  4.     [1, "GALAXY S10", 1000, "MOVIL", 1, 1],
  5.     [2, "IPHONE", 1200, "MOVIL", 2, 2],
  6.     [3, "MAC", 1400, "ORDENADOR", 2, 3]
  7. ]
  9. filename = Path('outputfile.txt')
  10. lines_per_product = len(products[0])
  12. with filename.open('w') as f:
  13.     for product in products:
  14.         for value in product:
  15.             f.write(f'{value}\n')
  17. products_aux = []
  19. with filename.open() as f:
  20.     lines = [_.strip() for _ in f.readlines()]
  21.     for i in range(0, len(lines), lines_per_product):
  22.         products_aux.append([
  23.             int(_) if _.isdigit() else _
  24.             for _ in lines[i:i + lines_per_product]
  25.         ])
  27. print(products_aux[0][3])
英文:

You code can be much cleaner if you use just a list of lists. With this approach your first product will start at 0 instead of 1 and you are going every product will have 6 lines on the output file, instead of 7, as you have in the code you posted.

Here is a solution that implements the concept I described using Python 3.6+ (because of f-strings):

  1. from pathlib import Path
  3. products = [
  4.     [1, "GALAXY S10", 1000, "MOVIL", 1, 1],
  5.     [2, "IPHONE", 1200, "MOVIL", 2, 2],
  6.     [3, "MAC", 1400, "ORDENADOR", 2, 3]
  7. ]
  9. filename = Path('outputfile.txt')
  10. lines_per_product = len(products[0])
  12. with filename.open('w') as f:
  13.     for product in products:
  14.         for value in product:
  15.             f.write(f'{value}\n')
  17. products_aux = []
  19. with filename.open() as f:
  20.     lines = [_.strip() for _ in f.readlines()]
  21.     for i in range(0, len(lines), lines_per_product):
  22.         products_aux.append([
  23.             int(_) if _.isdigit() else _
  24.             for _ in lines[i:i + lines_per_product]
  25.         ])
  27. print(products_aux[0][3])

huangapple
  • 本文由 发表于 2020年1月6日 20:48:41
  • 转载请务必保留本文链接：https://go.coder-hub.com/59612419.html
  • python
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