Ctk.Entry 的验证命令函数,如果第一个字符是数字则不接受输入。

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英文:

Validate command function for Ctk.Entry that does not accept input if the first character is a number?

问题

我正在尝试为我的 Ctk.Entry 小部件创建一个验证命令函数,该函数不允许用户输入以数字开头的内容。

例如,可以是:

  • abcd ef
  • abcd123 ab1
  • a1b2c3 1c

但不能是:

  • 1bcd
  • 1 abc
  • 123abc
  • 123 abc

我已成功为另一个小部件创建了一个允许仅输入数字的“回调”函数,它运行良好,但我在上述函数中遇到了问题。以下是代码:

def callback1(P):
    '''执行输入验证。

    仅允许不以数字开头的输入
    '''
    if P.strip() == "":
        return True
    elif P[0].isdigit() == False:
        return True

在这里,它被注册到小部件中(以防万一):

vcmd1 = (dashboard.register(callback1), "%P")

提前谢谢。

英文:

I am trying to create a validate command function for my Ctk.Entry widget, that does not allow the user to enter an input if the input starts with a number.

For example, can be:

  • abcd ef
  • abcd123 ab1
  • a1b2c3 1c

but can NOT be:

  • 1bcd
  • 1 abc
  • 123abc
  • 123 abc

I have succesfully created a 'callback' function for another widget that allows the input to be a number only, works fine, but i am having issues with the function mentioned above. See for code

def callback1(P):
'''Perform input validation.

Allow only if does not start with number
'''
    if P.strip() == "":
        return True

    elif P[0].isdigit() ==False:
        return True

Here it is registered to the widget(just in case):

vcmd1 = (dashboard.register(callback1),"%P")

Thank you in advance

答案1

得分: 1

通过@Bryan Oakley的帮助,我找到了解决方法。

首先,在elif语句内部不需要进行索引,因为该函数会检查完整的输入(如果输入是数字)。显然,如果以字母开头,输入就不会是数字。

其次,为了解决擦除输入并重新输入的问题,我在函数末尾留下了return True,以便它继续运行并检查输入是否为isdigit()。代码如下:

def callback1(P):
    '''执行输入验证。

    只允许不以数字开头的输入
    '''
    if P.strip() == "":
        return True

    elif P.isdigit():
        dashboard.bell()
        return False
    return True # 使函数始终运行
英文:

With @Bryan Oakley 's help. I figured it out.

First, no need for the indexing inside the elif statement, since the function checks for the full input (if the input is a number). And clearly the input will not be a number if started with a letter.

Second, to solve the issue of errasing the input and entering it again, I leave a return True at the end of the function so that it keeps running and cheking if input isdigit(). It looks like this.

def callback1(P):
'''Perform input validation.

Allow only if does not start with number
'''
    if P.strip() == "":
        return True

    elif P.isdigit():
        dashboard.bell()
        return False
    return True #so that the function always runs

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  • 本文由 发表于 2023年7月13日 00:48:26
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