Cobra指挥官：如何从另一个命令调用一个命令？

huangapple
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英文:

Cobra Commander: How to call a command from another command?

问题

在 cobra 中，我创建了一个命令的命令：

  1. myapp zip -directory "xzy" -output="zipname"
  2. myapp upload -filename="abc"

我想创建一个 zipAndUpload 命令，并重用现有的命令，即：

  1. myapp zipup -directory "xzy" -output="zipname"

在这里，zipup 首先调用 "zip" 命令，然后使用 "zip" 命令的输出名称作为 "upload" 命令的 "filename" 标志。

如何在不重复大量代码的情况下执行这个操作？

英文:

In cobra I've create a command of commands:

  1. myapp zip -directory "xzy" -output="zipname"
  2. myapp upload -filename="abc"

I want to make a zipAndUpload command and reuse the existing commands, i.e.,

  1. myapp zipup -directory "xzy" -outout="zipname"

Here the zipup would first call the "zip" command and then use the output name from the "zip" command as the "filename" flag for the "upload" command.

How can I execute this without a lot of code duplication?

答案1

得分: 4

"shared"开关变为全局。

子命令的"run"部分转换为函数。

为此，您必须手动定义命令：

  1. var (
  2.     cfgDirectory string
  3.     cfgFilename  string
  4.     cfgOutput    string
  5. )
  7. var rootCmd = &cobra.Command{
  8.     Use:   "root",
  9.     Short: "root",
  10.     Long:  "root",
  11.     Run: func(cmd *cobra.Command, args []string) {
  12.         // something
  13.     },
  14. }
  16. var uploadCmd = &cobra.Command{
  17.     Use:   "upload",
  18.     Short: "upload",
  19.     Long:  "upload",
  20.     Run: func(cmd *cobra.Command, args []string) {
  21.         Upload()
  22.     },
  23. }
  25. var zipCmd = &cobra.Command{
  26.     Use:   "zip",
  27.     Short: "zip",
  28.     Long:  "zip",
  29.     Run: func(cmd *cobra.Command, args []string) {
  30.         Zip()
  31.     },
  32. }
  34. var zipupCmd = &cobra.Command{
  35.     Use:   "zipup",
  36.     Short: "zipup",
  37.     Long:  "zipup",
  38.     Run: func(cmd *cobra.Command, args []string) {
  39.         Zip()
  40.         Upload()
  41.     },
  42. }
  44. func setFlags() {
  45.     rootCmd.PersistentFlags().StringVar(&cfgDirectory, "directory", "", "explanation")
  46.     rootCmd.PersistentFlags().StringVar(&cfgFilename, "filename", "", "explanation")
  47.     rootCmd.PersistentFlags().StringVar(&cfgOutput, "output", "", "explanation")
  48. }
  50. func Upload() {
  51.     // you know what to do
  52. }
  54. func Zip() {
  55.     // you know what to do
  56. }
  57. ...
  59. // 添加子命令
  60. rootCmd.AddCommand(zipCmd)
  61. rootCmd.AddCommand(uploadCmd)
  62. rootCmd.AddCommand(zipupCmd)

希望这可以帮到您，这是我在没有任何示例代码的情况下能做到的最好的翻译。

英文:

The "shared" switches make as global.

The "run" sections of the sub-commands, convert to functions.

To do this you must define the commands manually:

  1. var (
  2. cfgDirectory  string
  3. cfgFilename  string
  4. cfgOutput string
  5. )
  6. var rootCmd = &cobra.Command{
  7. Use:   "root",
  8. Short: "root",
  9. Long:  "root",
  10. Run: func(cmd *cobra.Command, args []string) {
  11. // something
  12. },
  13. }
  14. var uploadCmd = &cobra.Command{
  15. Use:   'upload',
  16. Short: 'upload',
  17. Long:  `upload`,
  18. Run: func(cmd *cobra.Command, args []string) {
  19. Upload()
  20. },
  21. }
  22. var zipCmd = &cobra.Command{
  23. Use:   "zip",
  24. Short: "zip",
  25. Long:  "zip",
  26. Run: func(cmd *cobra.Command, args []string) {
  27. Zip()
  28. },
  29. }
  30. var zipupCmd = &cobra.Command{
  31. Use:   "zipup",
  32. Short: "zipup",
  33. Long:  "zipup",
  34. Run: func(cmd *cobra.Command, args []string) {
  35. Zip()
  36. Upload()
  37. },
  38. }
  39. func setFlags() {
  40. rootCmd.PersistentFlags().StringVar(&cfgDirectory, "directory", "", "explanation")
  41. rootCmd.PersistentFlags().StringVar(&cfgFilename, "filename", "", "explanation")
  42. rootCmd.PersistentFlags().StringVar(&cfgOutput, "output", "", "explanation")
  43. }
  44. func Upload() {
  45. // you know what to do
  46. }
  47. func Zip() {
  48. // you know what to do
  49. }
  50. ...
  51. // Add subcommands
  52. rootCmd.AddCommand(zipCmd)
  53. rootCmd.AddCommand(uploadCmd)
  54. rootCmd.AddCommand(zipupCmd)

Hope this helps, this is the best I could do without any example code.

答案2

得分: 2

当您从cobra CLI创建新命令时，通常会将它们放入单独的文件中。如果您想从不同的命令文件中运行命令，代码会类似于这样：

  1. package cmd
  3. import "github.com/spf13/cobra"
  5. // DirectoryFlag 指定目录
  6. var DirectoryFlag string
  8. // OutputFlag 指定输出
  9. var OutputFlag string
  11. // zipupCmd 表示"zipup"命令
  12. var zipupCmd = &cobra.Command{
  13. 	Use:   "zipup",
  14. 	Short: "Zip & Upload",
  15. 	Long:  `Zip & Upload`,
  16. 	Run: func(cmd *cobra.Command, args []string) {
  17. 		anyArgs := "whatever"
  18. 		zipCmd.Run(cmd, []string{anyArgs})
  19. 		uploadCmd.Run(cmd, []string{anyArgs})
  20. 	},
  21. }
  23. func init() {
  24. 	rootCmd.AddCommand(zipupCmd)
  25. 	zipupCmd.Flags().StringVarP(&DirectoryFlag, "directory", "d", "", "设置目录")
  26. 	zipupCmd.Flags().StringVarP(&OutputFlag, "output", "o", "", "设置输出")
  27. }
英文:

When you create new commands from the cobra CLI, it usually puts them into separate files. If you want to run a command from a different command file, it would look something like this:

  1. package cmd
  2. import "github.com/spf13/cobra"
  3. // DirectoryFlag specifies the directory
  4. var DirectoryFlag string
  5. // OutputFlag specifies the output
  6. var OutputFlag string
  7. // zipupCmd represents the "zipup" command
  8. var zipupCmd = &cobra.Command{
  9. Use:   "zipup",
  10. Short: "Zip & Upload",
  11. Long: `Zip & Upload`,
  12. Run: func(cmd *cobra.Command, args []string) {
  13. anyArgs := "whatever"
  14. zipCmd.Run(cmd, []string{anyArgs})
  15. uploadCmd.Run(cmd, []string{anyArgs})
  16. },
  17. }
  18. func init() {
  19. rootCmd.AddCommand(zipupCmd)
  20. zipupCmd.Flags().StringVarP(&DirectoryFlag, "directory", "d", "", "set the directory")
  21. zipupCmd.Flags().StringVarP(&OutputFlag, "output", "o", "", "set the output")
  22. }

huangapple
  • 本文由 发表于 2017年5月3日 04:55:45
  • 转载请务必保留本文链接：https://go.coder-hub.com/43747075.html
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