如何在使用golang的goroutine时实现计数器?

huangapple go评论76阅读模式
英文:

How to implement a counter when using golang's goroutine?

问题

我正在尝试创建一个具有push和pop函数的队列结构。

我需要使用10个线程push数据,并使用另外10个线程pop数据,就像我在下面的代码中所做的那样。

问题:

  1. 我需要打印出我已经pushed/popped了多少次,但我不知道如何做到这一点。
  2. 有没有办法加快我的代码速度?我的代码对我来说太慢了。
package main

import (
	"runtime"
	"time"
)

const (
	DATA_SIZE_PER_THREAD = 10000000
)

type Queue struct {
	records string
}


func (self Queue) push(record chan interface{}) {
	// 需要push计数器
	record <- time.Now()
}

func (self Queue) pop(record chan interface{}) {
	// 需要pop计数器
	<- record
}

func main() {
	runtime.GOMAXPROCS(runtime.NumCPU())
	// 记录通道
	record := make(chan interface{},1000000)
	// 完成标志通道
	finish := make(chan bool)
	queue := new(Queue)
	for i:=0; i<10; i++ {
		go func() {
			for j:=0; j<DATA_SIZE_PER_THREAD; j++ {
				queue.push(record)
			}
			finish<-true
		}()
	}
	for i:=0; i<10; i++ {
		go func() {
			for j:=0; j<DATA_SIZE_PER_THREAD; j++ {
				queue.pop(record)
			}
			finish<-true
		}()
	}
	for i:=0; i<20; i++ {
		<-finish
	}
}
英文:

I'm trying to make a queue struct that have push and pop functions.

I need to use 10 threads push and another 10 threads pop data, just like I did in the code below.

Questions:

  1. I need to print out how much I have pushed/popped, but I don't know how to do that.
  2. Is there anyway to speed up my code? The code is too slow for me.
package main

import (
	&quot;runtime&quot;
	&quot;time&quot;
)

const (
	DATA_SIZE_PER_THREAD = 10000000
)

type Queue struct {
	records string
}


func (self Queue) push(record chan interface{}) {
	// need push counter
	record &lt;- time.Now()
}

func (self Queue) pop(record chan interface{}) {
	// need pop counter
	&lt;- record
}

func main() {
	runtime.GOMAXPROCS(runtime.NumCPU())
	//record chan
	record := make(chan interface{},1000000)
	//finish flag chan
	finish := make(chan bool)
	queue := new(Queue)
	for i:=0; i&lt;10; i++ {
		go func() {
			for j:=0; j&lt;DATA_SIZE_PER_THREAD; j++ {
				queue.push(record)
			}
			finish&lt;-true
		}()
	}
	for i:=0; i&lt;10; i++ {
		go func() {
			for j:=0; j&lt;DATA_SIZE_PER_THREAD; j++ {
				queue.pop(record)
			}
			finish&lt;-true
		}()
	}
	for i:=0; i&lt;20; i++ {
		&lt;-finish
	}
}

答案1

得分: 16

有几件事情你应该修复。

  • 队列类型的方法应该有指针接收器。否则,每次方法调用都会创建当前队列类型的副本,对队列字段的任何更改都不会在方法调用之后持续存在。

  • 等待所有协程完成可以使用sync.WaitGroup来完成。这是它专门设计的目的。

  • 在队列类型内部维护一个线程安全的推入/弹出计数器可以使用sync/atomic包来完成。

就速度而言,从你的示例中,我不太确定你想要实现什么。如果你详细说明一下,可能会有一些优化方法。

这是我从你的代码中修改的一个示例:

package main
import (
"log"
"runtime"
"sync"
"sync/atomic"
"time"
)
const SizePerThread = 10000000
type Queue struct {
records string
count   int64
}
func (q *Queue) push(record chan interface{}) {
record <- time.Now()
newcount := atomic.AddInt64(&q.count, 1)
log.Printf("Push: %d", newcount)
}
func (q *Queue) pop(record chan interface{}) {
<-record
newcount := atomic.AddInt64(&q.count, -1)
log.Printf("Pop: %d", newcount)
}
func main() {
var wg sync.WaitGroup
runtime.GOMAXPROCS(runtime.NumCPU())
record := make(chan interface{}, 1000000)
queue := new(Queue)
// 我们启动了20个协程。
// 让等待组知道它应该等待这些协程中的多少个完成。
wg.Add(20)
for i := 0; i < 10; i++ {
go func() {
defer wg.Done()
for j := 0; j < SizePerThread; j++ {
queue.push(record)
}
}()
go func() {
defer wg.Done()
for j := 0; j < SizePerThread; j++ {
queue.pop(record)
}
}()
}
// 等待所有协程完成。
wg.Wait()
}
英文:

There are a few things you should fix.

  • The methods on the Queue type should have pointer receivers. Otherwise, every method
    call will create a copy of the current queue type and any changes to queue fields will
    not persist beyond the method call itself.

  • Waiting for all routines to finish, can be done using a sync.WaitGroup. This
    is specifically what it was designed for.

  • Maintaining a thread-safe push/pop counter inside the queue type can be done by
    using the sync/atomic package.

As far as speed goes, from your example, I am not quite sure what you are trying to achieve. Any optimizations might come up if you elaborate on that a little.

Here is an example I modified from your code:

package main
import (
&quot;log&quot;
&quot;runtime&quot;
&quot;sync&quot;
&quot;sync/atomic&quot;
&quot;time&quot;
)
const SizePerThread = 10000000
type Queue struct {
records string
count   int64
}
func (q *Queue) push(record chan interface{}) {
record &lt;- time.Now()
newcount := atomic.AddInt64(&amp;q.count, 1)
log.Printf(&quot;Push: %d&quot;, newcount)
}
func (q *Queue) pop(record chan interface{}) {
&lt;-record
newcount := atomic.AddInt64(&amp;q.count, -1)
log.Printf(&quot;Pop: %d&quot;, newcount)
}
func main() {
var wg sync.WaitGroup
runtime.GOMAXPROCS(runtime.NumCPU())
record := make(chan interface{}, 1000000)
queue := new(Queue)
// We are launching 20 goroutines.
// Let the waitgroup know it should wait for as many
// of them to finish.
wg.Add(20)
for i := 0; i &lt; 10; i++ {
go func() {
defer wg.Done()
for j := 0; j &lt; SizePerThread; j++ {
queue.push(record)
}
}()
go func() {
defer wg.Done()
for j := 0; j &lt; SizePerThread; j++ {
queue.pop(record)
}
}()
}
// Wait for all goroutines to finish.
wg.Wait()
}

答案2

得分: -5

问题1的答案:正如jimt建议的那样,sync/atomic有一些用于原子更新计数器的函数,这对你可能很有用。

问题2的答案:减小DATA_SIZE_PER_THREAD的值,或者更好的方法是使用以下程序:

package main
func main() {}

它以更高效的方式产生与你的程序相同的输出。

但是,说真的,我理解你写了一个小程序来探索一些概念。然而,你的程序存在一些问题。现在不是担心速度的时候,而是学习一些基本概念的时候。

英文:

Answer to question 1: As jimt suggested, sync/atomic has functions for atomically updating a counter, which may be useful to you.

Answer to question 2: Reduce the value of DATA_SIZE_PER_THREAD, or better yet, use the program

package main
func main() {}

which produces the same output as your program in a more efficent way.

Seriously though, I understand you have written a small program to explore some concepts. Your program contains a number of issues however. This is not the time to worry about speed, it is the time to learn some fundamental concepts.

huangapple
  • 本文由 发表于 2012年9月4日 22:37:20
  • 转载请务必保留本文链接:https://go.coder-hub.com/12265813.html
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