问题

为什么如果我从字符串"s"和保存在指针"p"中的字符串的第一个字符打印出来，地址会不同？它们不应该是相同的吗？我得到了相同的字符，但地址不同。

#include <stdio.h>
#include

int main()
{
std::string s = "hello";
char *p = &s[0];
printf("%p\n", s);
printf("%p\n", p);

printf("%c\n", s[0]);
printf("%c\n", *p);

}

<details>
<summary>英文:</summary>

Why is the address different if i print it from string &quot;s&quot; and from the first char of the string, saved in the pointer &quot;p&quot;? Should it not be the same? I get the same char but the address is different.

#include <stdio.h>
#include <string>

int main()
{
std::string s = "hello";
char *p = &s[0];
printf("%p\n", s);
printf("%p\n", p);

printf("%c\n", s[0]);
printf("%c\n", *p);

}

</details>


# 答案1
**得分**: 1

在C++中，std::string是一个包含数据的对象（或更可能是一个指向数据的指针），因此对象和它包含的数据位于不同的位置。

<details>
<summary>英文:</summary>

You might be thinking of plain C strings, where your pointers would match.  

In a C++, the std::string is an object that contains the data (or more likely a pointer to it), so the object and the data it contains will be located in different places.

</details>