英文:
Python Unit Testing a mocked function calls the original function and fails
问题
notification.py:
def get_notification(some_data):
data = details["type"]
notification = {"config1": data, "config2": some_data}
return notification
test_notification.py:
from notification import get_notification
import pytest
def test_get_notifications(mocker):
mocker.patch('notification.get_notification', return_value="SUCCESS")
result = get_notification(some_data)
assert result == "SUCCESS"
Instead of returning "SUCCESS" by the mocked function, the original function is getting called.
I tried using @patch.object which also resulted in calling of the original function.
@patch.object(notification, 'get_notification')
def test_get_notifications(get_notification_mock):
get_notification_mock.return_value = "SUCCESS"
result = get_notification(some_data)
assert result == "SUCCESS"
英文:
I have the following scripts:
notification.py:
def get_notification(some_data):
data = details["type"]
notification = {"config1":data, "config2":some_data}
return notification
test_notification.py:
from notification import get_notification
import pytest
def test_get_notifications(mocker):
mocker.patch('notification.get_notification',return_value="SUCCESS")
result = get_notification(some_data)
assert result == "SUCCESS"
Instead of returning "SUCCESS" by the mocked function, the original function is getting called.
I tried using @patch.object which also resulted in calling of the original function.
@patch.object(notification, 'get_notification')
def test_get_notifications(get_notification_mock):
get_notification_mock.return_value="SUCCESS"
result = get_notification(some_data)
assert result == "SUCCESS"
答案1
得分: 2
这是因为一旦你导入了get_notification，它不再"属于" notification 模块，而是属于 test_notification 模块。
你需要修改你的补丁来指向 test_notification：
mocker.patch("test_notification.get_notification", return_value="SUCCESS")
# 或者
mocker.patch(__name__ + ".get_notification", return_value="SUCCESS")
英文:
This is because once you have imported get_notification, it does not "belong" to the notification module but to the test_notification module.
You have to modify your patch to point to the test_notification:
mocker.patch("test_notification.get_notification", return_value="SUCCESS")
# or
mocker.patch(__name__ + ".get_notification", return_value="SUCCESS")
答案2
得分: 0
以下是示例(debug.py)的翻译：
from unittest.mock import patch
def get_notification():
return 'failed'
def test_get_notifications():
with patch(
# change 'debug' to your module name('notification')...
'debug.get_notification',
return_value='SUCCESS'
):
assert get_notification() == "SUCCESS"
运行 pytest debug.py：
===================================================================== 测试会话开始 ======================================================================
平台：Linux -- Python 3.10.6，pytest-7.4.0，pluggy-1.2.0
根目录：项目路径...
收集到 1 个项目
debug.py . [100%]
====================================================================== 1 个测试通过，用时 0.01 秒 ======================================================================
英文:
Here is an example(debug.py):
from unittest.mock import patch
def get_notification():
return 'failed'
def test_get_notifications():
with patch(
# change 'debug' to your module name('notification')...
'debug.get_notification',
return_value='SUCCESS'
):
assert get_notification() == "SUCCESS"
Run pytest debug.py:
===================================================================== test session starts ======================================================================
platform linux -- Python 3.10.6, pytest-7.4.0, pluggy-1.2.0
rootdir: PATH TO PROJECT...
collected 1 item
debug.py . [100%]
====================================================================== 1 passed in 0.01s =======================================================================
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