循环遍历Python中的嵌套字典/列表并保存键值对。

huangapple
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英文:

loop through nested dictionary/list in Python and save key-value pairs

问题

I can help you with the translations:

Original Content:

  1. I'd like to loop through this nested dict/list and return all occurrences of input key-value pairs. The length and the depth of each level may vary.
  3. For example I'd like to have all the `{'dd': 22}`.
  5. Here's my attempt:
  7. d = {'a': 'foo',
  8.     'b': [{'cc': 11},
  9.          {'dd': 22}],
  10.     'c': [{'dd': 22},
  11.          {'ff': 33}]}
  13. def navigate_html(d, key='', value='', ll=[]):
  14.     if isinstance(d, list):
  15.         for v in d:
  16.             yield from navigate_html(v, key, value, ll)
  17.     if isinstance(d, dict):
  18.         for k, v in d.items():
  19.             if k == key and v == value:
  20.                 ll.append({k: v})
  21.             else:
  22.                 yield from navigate_html(v, key, value, ll)
  23.     return ll
  25. for i in navigate_html(d, 'dd', 22):
  26.     print('---', i)

Desired Output:
[{'dd': 22}, {'dd': 22}]

Edited Content:

  1. d1={'doctype': ['html'],
  2.  'html': [{'@lang': 'en-EN',
  3.    '#text': "ttt",
  4.    'head': [{'#text': 'abc',
  5.      'meta': [{'@charset': 'utf-8', '#text': ''},
  6.       {'@name': 'viewport',
  7.        '@content': 'width=device-width, initial-scale=1.0, maximum-scale=1.0, user-scalable=no',
  8.        '#text': ''},
  9.       {'@name': 'description',
  10.        '@content': 'cccc',
  11.        '#text': '',
  12.        'meta': [{'@name': 'keywords',
  13.          '@content': 'cccc',
  14.          '#text': ''}]
  15.       }]
  16.             }]}
  17.    }

Expected Output:
[{'@content': 'cccc'}, {'@content': 'cccc'}]

英文:

I'd like to loop through this nested dict/list and return all occurrences of input key-value pairs. The length and the depth of each level may vary.

For example I'd like to have all the {'dd': 22}.

Here's my attempt:

  1. d = {'a': 'foo',
  2.     'b': [{'cc': 11},
  3.          {'dd': 22}],
  4.     'c': [{'dd': 22},
  5.          {'ff': 33}]}
  7. def navigate_html(d, key='', value='', ll=[]):
  8.     if isinstance(d, list):
  9.         for v in d:
  10.             yield from navigate_html(v, key, value, ll)
  11.     if isinstance(d, dict):
  12.         for k, v in d.items():
  13.             if k == key and v == value:
  14.                 ll.append({k: v})
  15.             else:
  16.                 yield from navigate_html(v, key, value, ll)
  17.     return ll
  19. for i in navigate_html(d, 'dd', 22):
  20.     print('---', i)

desired output
[{'dd': 22}, {'dd': 22}]

EDIT
better, try to retrieve '@content': 'cccc'

  1. d1={'doctype': ['html'],
  2.  'html': [{'@lang': 'en-EN',
  3.    '#text': "ttt",
  4.    'head': [{'#text': 'abc',
  5.      'meta': [{'@charset': 'utf-8', '#text': ''},
  6.       {'@name': 'viewport',
  7.        '@content': 'width=device-width, initial-scale=1.0, maximum-scale=1.0, user-scalable=no',
  8.        '#text': ''},
  9.       {'@name': 'description',
  10.        '@content': 'cccc',
  11.        '#text': '',
  12.        'meta': [{'@name': 'keywords',
  13.          '@content': 'cccc',
  14.          '#text': ''}]
  15.       }]
  16.             }]
  17.           }]
  18.    }

expected output:
[{'@content': 'cccc'}, {'@content': 'cccc'}]

答案1

得分: 2

  1. def navigate_html(nested: dict, key, value):
  2.     for k, v in nested.items():
  3.         if k == key and v == value:
  4.             yield {k: v}
  5.         elif isinstance(v, list):
  6.             for d in v:
  7.                 if isinstance(d, dict):
  8.                     yield from navigate_html(d, key, value)
英文: 
  1. def navigate_html(nested: dict, key, value):
  2.     for k, v in nested.items():
  3.         if k == key and v == value:
  4.             yield {k: v}
  5.         elif isinstance(v, list):
  6.             for d in v:
  7.                 if isinstance(d, dict):
  8.                     yield from navigate_html(d, key, value)
  10. >>> list(navigate_html(d, 'dd', 22))
  11. # => [{'dd': 22}, {'dd': 22}]
  13. >>> list(navigate_html(d1, '@content', 'cccc'))
  14. # => [{'@content': 'cccc'}, {'@content': 'cccc'}]

huangapple
  • 本文由 发表于 2023年6月1日 00:28:42
  • 转载请务必保留本文链接：https://go.coder-hub.com/76375593.html
  • dictionary
  • python
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