英文:
How to find occurrences of non-fraction values in a column in R?
问题
以下是翻译好的部分：
这应该很简单，但我找不到任何方法来实现这一点。我只想找到y列中包含非分数值的行。我的数据如下：
> df <- data.frame(id = c("a", "a", "a", "a", "a", "b", "b", "b", "b"),
y = c(1.000, 2.000, 3.000, 4.000, 5.345, 1.000, 2.000, 3.000, 4.670))
> df
id y
a 1.000
a 2.000
a 3.000
a 4.000
a 5.345
b 1.000
b 2.000
b 3.000
b 4.670
所需输出：
id y
a 5.345
b 4.670
最好使用tidyverse方法。谢谢！
英文:
This should be easy, but I couldn't find any way to do this. All I want to do is find the rows with non-fraction values in y. I have data like so:
> df <- data.frame(id = c("a", "a", "a", "a", "a", "b", "b", "b", "b"),
y = c(1.000, 2.000, 3.000, 4.000, 5.345, 1.000, 2.000, 3.000, 4.670))
> df
id y
a 1.000
a 2.000
a 3.000
a 4.000
a 5.345
b 1.000
b 2.000
b 3.000
b 4.670
Output required:
id y
a 5.345
b 4.670
A tidyverse method would be preferred. Thanks!
答案1
得分: 3
筛选与取模：
filter(df, !near(y %% 1, 0))
英文:
Filter with modulo:
filter(df, !near(y %% 1, 0))
答案2
得分: 1
可能 `as.character` 在这里起到了一个技巧
> subset(df, grepl(".", as.character(y), fixed = TRUE))
id y
5 a 5.345
9 b 4.670
<details>
<summary>英文:</summary>
Probably `as.character` could play a trick here
> subset(df, grepl(".", as.character(y), fixed = TRUE))
id y
5 a 5.345
9 b 4.670
</details>
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