英文:
How to iterate over each bit of a byte in Python?
问题
让我们假设 a=0xF0，b=[a的位列表]。我如何迭代遍历a的每个位，以便我可以执行位运算，将该位与列表b中的位进行位运算？
我已尝试使用bin()方法将a转换为其二进制形式，然后循环遍历它，但由于a的每个位现在都是字符串数据类型，因此无法再执行位运算。
任何帮助都将不胜感激！
英文:
Let's say a=0xF0 and b=[a list of bits]. How do I iterate over each bit of a so that i can perform a bitwise operation between that bit and a bit in list b?
I have tried converting a to its binary form using the bin() method before looping through it, however, i can no longer perform a bitwise operation as each bit of a is now of the string datatype.
Any help is appreciated!
答案1
得分: 0
你可以使用位移操作：
a = 0xF0b = [1, 0, 1, 0, 1, 0, 1, 0]print(bin(a))# 0b11110000for idx, bit_in_b in enumerate(b):bit_in_a = (a >> idx) & 1binary_and_operation = bit_in_a & bit_in_bprint(bit_in_a, binary_and_operation)# 0 0# 0 0# 0 0# 0 0# 1 1# 1 0# 1 1# 1 0
注意两点：
a从右到左迭代，b从左到右迭代，但根据需要可以更改。- 如果
len(b)不等于a中的比特数，行为可能不是你想要的。
英文:
You can use bitshift:
a = 0xF0b = [1, 0, 1, 0, 1, 0, 1, 0]print(bin(a))# 0b11110000for idx, bit_in_b in enumerate(b):bit_in_a = (a >> idx) & 1binary_and_operation = bit_in_a & bit_in_bprint(bit_in_a, binary_and_operation)# 0 0# 0 0# 0 0# 0 0# 1 1# 1 0# 1 1# 1 0
Careful to 2 points:
awill be iterated from right to left and b from left to right, but you can change that as needed.- if
len(b)!= number of bits ina, behavior might not be what you want.
答案2
得分: 0
一种简短的表达方式如下：```pythonbin(int("".join([str(bit) for bit in b]), 2) ^ a)[2:].zfill(max(len(b), (len(bin(a)) - 2)))
它的工作原理如下：
"".join([str(bit) for bit in b])将您的列表转换为字符串int(..., 2)转换为二进制数字^是按位异或运算（或者任何其他您想要的操作）bin(...)将其转换回二进制表示[2:]去除字符串的0b部分.zfil(...)填充结果的零，直到结果具有与两个输入中较大者相同数量的位数，以防位运算结果以零开头。
示例：
a = 0xF0b = [0, 1, 1, 1, 0, 0, 1, 0]result = bin(int("".join([str(bit) for bit in b]), 2) ^ a)[2:].zfill(max(len(b), (len(bin(a)) - 2)))print(result)
输出：
10000010
<details><summary>英文:</summary>A one-liner would be this:
bin(int("".join([str(bit) for bit in b]), 2) ^ a)[2:].zfill(max(len(b), (len(bin(a))-2)))
It works like so:- `"".join([str(bit) for bit in b]` converts your list to a string- `int(..., 2)` converts to a number in base 2- `^` is the bitwise `xor` (or any other operation you want)- `bin(...)` converts it back to a binary representation- `[2:]` drops the `0b` part of the string- `.zfil(...)` pads the result with zeroes until the result has the same number of bits as the largest of the two inputs, in case the bitwise result starts with zeroes.Example:
a = 0xF0
b = [0, 1, 1, 1, 0, 0, 1, 0]
result = bin(int("".join([str(bit) for bit in b]), 2) ^ a)[2:].zfill(max(len(b), (len(bin(a))-2)))
print(result)
Output:
10000010
</details>
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