Python sorting()

huangapple
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英文:

Python sorting()

问题

如何对这种嵌套列表进行排序，而不将列表拆分为单独的部分？

  1. class Car:
  3.     def __init__(self, carid, carname):
  4.         self.carid = id
  5.         self.carname = name
  7.     def __str__(self):
  8.         return str(self.__dict__)
  10. def cars():
  11.     car_car = [Car(3, "toyota"),
  12.                 Car(4, "BMW"),
  13.                 Car(2, "Chevrolet"),
  14.                 Car(1, "Ford")]
  15.     car_car.sort(key=lambda v: (v.carid, v.carname))  ### 这里
  16.     
  17.     return car_car
  19. 我想使用 .sort 选项按字母顺序对数据进行排序，而不拆分列表
  21. 我得到了
  22. > TypeError: 'Car' object is not subscriptable error
  24. 使用 sorted() 和 .sort() 也会出现此错误。
  26. <details>
  27. <summary>英文:</summary>
  29. How to sort this type of nested list without splitting the list into separate? 
  31.     class Car:
  32.     
  33.         def __init__(self, carid, carname):
  34.             self.carid = id
  35.             self.carname = name
  36.     
  37.         def __str__(self):
  38.             return str(self.__dict__)
  39.     
  40.     def cars():
  41.         car_car = [ Car(3, &quot;toyota&quot;),
  42.                     Car(4, &quot;BMW&quot;),
  43.                     Car(2, &quot;Chevloret&quot;),
  44.                     Car(1,&quot;Ford&quot;)]
  45.         cars.sort(key=lambda v: (v[0], v[1])) ### here
  46.     
  47.         return car_car
  49. I want to sort the data alphabetically using the .sort option without splitting that list
  51. I got 
  52. &gt; TypeError: &#39;Car&#39; object is not subscriptable error 
  54.  with  sorted() and .sort()
  57. </details>
  60. # 答案1
  61. **得分**: 1
  63. ```python
  64. class Car:
  65.     def __init__(self, carid, carname):
  66.         self.carid = carid
  67.         self.carname = carname
  69.     def __str__(self):
  70.         return str(self.__dict__)
  72. def cars():
  73.     car_car = [Car(3, "toyota"), Car(4, "BMW"), Car(2, "Chevrolet"), Car(1, "Ford")]
  74.     car_car.sort(key=lambda car: car.carname)  # 根据carname属性对列表进行排序
  75.     return car_car
  77. sorted_cars = cars()
  78. for car in sorted_cars:
  79.     print(car)

要对Car对象的列表进行排序，而不将其拆分为单独的元素，可以使用sorted()函数和自定义的键函数。该代码根据每个Car对象的carname属性按字母顺序对car_car列表进行排序。

英文: 
  1. class Car:
  2. def __init__(self, carid, carname):
  3. self.carid = carid
  4. self.carname = carname
  5. def __str__(self):
  6. return str(self.__dict__)
  7. def cars():
  8. car_car = [Car(3, &quot;toyota&quot;), Car(4, &quot;BMW&quot;), Car(2, &quot;Chevloret&quot;), Car(1, &quot;Ford&quot;)]
  9. car_car.sort(key=lambda car: car.carname)  # Sort by carname attribute
  10. return car_car
  11. sorted_cars = cars()
  12. for car in sorted_cars:
  13. print(car)

To sort the list of Car objects without splitting it into separate elements, you can use the sorted() function with a custom key function. The code sorts the car_car list alphabetically by the carname attribute of each Car object

huangapple
  • 本文由 发表于 2023年7月12日 23:37:34
  • 转载请务必保留本文链接：https://go.coder-hub.com/76672293.html
  • python
  • sorting
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