python How to iterate over two files and grep only one line before the match

This is names.txt:

David
Mary
Rose
Saeed

This is emails.txt:

  - address1@gmail.com
  - Mary
  - address2@gmail.com
  - Rose
  - address3@hotmail.com
  - David
  - address4@yahoo.com
  - Saeed
  - address5@gmail.com
  - Jones

In emails.txt there are more emails than names.txt.

I want to grep each name in names.txt and grep that name but only one line before that.

For example, to grep the name David and find its email address3@hotmail.com.

This is my python code up to now (which only prints the first line of names.txt:

import re

with open('names.txt', 'r') as file:
    with open('emails.txt', 'r') as emails:
        for name in file:
            for email in emails:
                if re.search(name, email):
                    print(email)

I'll update the question when I find something new to get closer to the answer.

Is this what you want?

import re

with open('names.txt', 'r') as names_file:
    with open('emails.txt', 'r') as emails_file:
        names = names_file.readlines()
        emails = emails_file.readlines()

        for name in names:
            name = name.strip()
            for i, email in enumerate(emails):
                email = re.sub('-', '', email)
                if re.search(name, email):
                    prev_email = emails[i-1].strip()
                    prev_email = re.sub('-', '', prev_email)
                    print(f"Name: {name}, Email: {prev_email}")
                    break

Result

Name: David, Email:  address3@hotmail.com
Name: Mary, Email:  address1@gmail.com
Name: Rose, Email:  address2@gmail.com
Name: Saeed, Email:  address4@yahoo.com