英文:
not giving output the way I’m expecting
问题
<blockquote>打印以下模式。任何两个相邻数字之间都恰好有一个空格。任何一行末尾都没有空格。```none1 2 11 2 3 2 11 2 3 4 3 2 11 2 3 4 5 4 3 2 1
</blockquote>
this was the question
for i in range(1, 6):# Print numbers in increasing orderfor j in range(1, i + 1):print(j, end=' ')# Print numbers in decreasing orderfor j in range(i - 1, 0, -1):print(j, end=' ')# Move to the next lineprint()
when we print the above code I’m getting
11 2 11 2 3 2 11 2 3 4 3 2 11 2 3 4 5 4 3 2 1
英文:
<blockquote>
Print the following pattern. There is exactly one space between any two consecutive numbers on any line. There are no spaces at the end of any line.
1 2 11 2 3 2 11 2 3 4 3 2 11 2 3 4 5 4 3 2 1
</blockquote>
this was the question
for i in range(1, 6):# Print numbers in increasing orderfor j in range(1, i + 1):print(j, end=' ')# Print numbers in decreasing orderfor j in range(i - 1, 0, -1):print(j, end=' ')# Move to the next lineprint()
when we print the above code I’m getting
11 2 11 2 3 2 11 2 3 4 3 2 11 2 3 4 5 4 3 2 1
答案1
得分: 0
以下是翻译好的代码部分：
正确的代码应该是：for i in range(2, 6):for j in range(1, i + 1):print(j, end=' ')for j in range(i - 1, 0, -1):print(j, end=' ')print()第一个循环将执行4次，每次应该从1开始，所以第二个循环的范围从1开始。
英文:
the correct code should be:
for i in range(2, 6):for j in range(1, i + 1):print(j, end=' ')for j in range(i - 1, 0, -1):print(j, end=' ')print()
The first loop will be 4 times, every time should begin with 1, so the range of the second loop starts with 1.
通过集体智慧和协作来改善编程学习和解决问题的方式。致力于成为全球开发者共同参与的知识库，让每个人都能够通过互相帮助和分享经验来进步。
评论