英文:
not giving output the way I’m expecting
问题
<blockquote>
打印以下模式。任何两个相邻数字之间都恰好有一个空格。任何一行末尾都没有空格。
```none
1 2 1
1 2 3 2 1
1 2 3 4 3 2 1
1 2 3 4 5 4 3 2 1
</blockquote>
this was the question
for i in range(1, 6):
# Print numbers in increasing order
for j in range(1, i + 1):
print(j, end=' ')
# Print numbers in decreasing order
for j in range(i - 1, 0, -1):
print(j, end=' ')
# Move to the next line
print()
when we print the above code I’m getting
1
1 2 1
1 2 3 2 1
1 2 3 4 3 2 1
1 2 3 4 5 4 3 2 1
英文:
<blockquote>
Print the following pattern. There is exactly one space between any two consecutive numbers on any line. There are no spaces at the end of any line.
1 2 1
1 2 3 2 1
1 2 3 4 3 2 1
1 2 3 4 5 4 3 2 1
</blockquote>
this was the question
for i in range(1, 6):
# Print numbers in increasing order
for j in range(1, i + 1):
print(j, end=' ')
# Print numbers in decreasing order
for j in range(i - 1, 0, -1):
print(j, end=' ')
# Move to the next line
print()
when we print the above code I’m getting
1
1 2 1
1 2 3 2 1
1 2 3 4 3 2 1
1 2 3 4 5 4 3 2 1
答案1
得分: 0
以下是翻译好的代码部分：
正确的代码应该是：
for i in range(2, 6):
for j in range(1, i + 1):
print(j, end=' ')
for j in range(i - 1, 0, -1):
print(j, end=' ')
print()
第一个循环将执行4次，每次应该从1开始，所以第二个循环的范围从1开始。
英文:
the correct code should be:
for i in range(2, 6):
for j in range(1, i + 1):
print(j, end=' ')
for j in range(i - 1, 0, -1):
print(j, end=' ')
print()
The first loop will be 4 times, every time should begin with 1, so the range of the second loop starts with 1.
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