英文:
Draw a line to connect points between subfigures
问题
使用matplotlib的新subfigure - 不是subplot - 而是subfigure功能。我想要在两个子图之间绘制一条线。根据我的实验，我不认为连接补丁（对于子图(subplots)有效）适用于这种情况。有人知道是否可能吗？
英文:
With matplotlib's new subfigure - not subplot - but subfigure feature. I would like to draw a line between two subfigures. From my experimentation, I don't believe connection patch (which works for subplots) works with this. Does anyone know if it possible?
答案1
得分: 1
ConnectionPatch可以与子图一起使用，但正如@JodyKlymak指出的，应该通过set_in_layout(False)将该图形从布局计算中移除。
这里有一个示例，连接第一个子图的ax1a上的点(4, 8)与第二个子图的ax2上的点(2, 5)：
import matplotlib.pyplot as plt
from matplotlib.patches import ConnectionPatch
fig = plt.figure(layout='constrained')
sf1, sf2 = fig.subfigures(1, 2, wspace=0.07)
ax1a, ax1b = sf1.subplots(2, 1)
ax1a.scatter(4, 8)
ax1b.scatter(10, 15)
ax2 = sf2.subplots()
ax2.scatter(2, 5)
conn = ConnectionPatch(
xyA=(4, 8), coordsA='data', axesA=ax1a,
xyB=(2, 5), coordsB='data', axesB=ax2,
color='red',
)
ax2.add_artist(conn)
conn.set_in_layout(False) # 从布局计算中移除
plt.show()
英文:
ConnectionPatch works fine with subfigures, but as @JodyKlymak points out, the patch should be removed from layout calculations via set_in_layout(False).
Here is an example connecting (4, 8) on the first subfigure's ax1a with (2, 5) on the second subfigure's ax2:
import matplotlib.pyplot as plt
from matplotlib.patches import ConnectionPatch
fig = plt.figure(layout='constrained')
sf1, sf2 = fig.subfigures(1, 2, wspace=0.07)
ax1a, ax1b = sf1.subplots(2, 1)
ax1a.scatter(4, 8)
ax1b.scatter(10, 15)
ax2 = sf2.subplots()
ax2.scatter(2, 5)
conn = ConnectionPatch(
xyA=(4, 8), coordsA='data', axesA=ax1a,
xyB=(2, 5), coordsB='data', axesB=ax2,
color='red',
)
ax2.add_artist(conn)
conn.set_in_layout(False) # remove from layout calculations
plt.show()
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