在C++中是否可以声明具有固定位宽的类型,而不使用结构体?

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英文:

Is it possible to declare a type with a set bit width in c++ without using a struct?

问题

C++中是否支持不使用struct、class或union位域来指定类型的位宽?使用它们会增加不必要且让人讨厌的间接性级别。

如果C++有类似C#的属性,你可以将Address设置为一个访问器,隐藏掉这种间接性。在Ada中,你可以这样声明Address

type Address is range 0..2**4 - 1 with Object_Size = 4;  -- 这不是很可爱吗!

我尝试了以下声明,理论上应该能工作:

typedef unsigned char Address:4;   // 如果我们有这么幸运的话!

C++是否支持这样的构造或解决方法?

英文:

It's been at least a decade since I last touched C++. Supposedly, C++ has had a minor overhaul. Is there a way to specify the bit width of a type without using struct, class, or union bitfields? The problem with them is that it adds an unnecessary and annoying level of indirection:

  struct Address
  {
        unsigned char val:4 = 0; // C++ in 2020?
  };

  struct Device
  {
        Address address;    // 4-bit address
        string name;
  };

  int main() 
  {
        Device device;
        device.address.val = 0x8;  // Yuckity yuck WTF!
        return 0;
  };

If C++ had properties like C#, you could make Address an accessor that hides away the indirection. In Ada, you would simply declare Address like so:

type Address is range 0..2**4 - 1 with Object_Size = 4;  -- Isn't this cute and sweet!

I tried the following declaration and there's no reason why it shouldn't work:

typedef unsigned char Address:4;   // if we were only so lucky!

Does C++ support such a construct or workaround?

答案1

得分: 1

以下是您提供的代码的翻译部分:

不是开箱即用的,但制作一个小的包装类来进行验证并不难。这里是这种类的草图,甚至可以在编译时进行检查。

演示链接:https://onlinegdb.com/RBVQfsAI5

#include <iostream>

// N是您想要使用的地址位数
template<std::size_t N>
struct address_t
{
public:
    explicit constexpr address_t(std::uintptr_t value) :
        address{ checked_value(value) }
    {
    }

    // 这是少数情况下隐式转换有用的地方
    operator std::uintptr_t() const noexcept
    {
        return address;
    }

    // 赋值运算符检查值。
    void operator=(std::uintptr_t value)
    {
        address = checked_value(value);
    }

private:
    constexpr std::uintptr_t checked_value(std::uintptr_t value)
    {
        if (value >= (1 << N)) throw std::invalid_argument("地址值过大");
        return value;
    }

    std::uintptr_t address;
};

int main()
{
    // addres_t<4> 表示最多有 4 位的地址
    static constexpr address_t<4> compile_time_address{15}; // 如果值过大,将无法编译通过
    std::cout << compile_time_address << "\n"; // 使用隐式转换到 std::uint_ptr_t

    address_t<4> runtime_address{15};
    std::cout << runtime_address << "\n";
    runtime_address = 12;
    std::cout << runtime_address << "\n";

    try
    {
        // 在运行时分配无效值会抛出异常。
        address_t<4> runtime_address_fail{16};
    }
    catch (const std::invalid_argument&)
    {
    }

    return 0;
}

请注意,翻译只包括代码部分,不包括问题或其他内容。如果您需要进一步的帮助,请随时提问。

英文:

Not out of the box, but it is not so hard to make a small wrapper class that does the validation. Sketch of such a class here, it can even check at compile time.

Demo here : https://onlinegdb.com/RBVQfsAI5

#include &lt;iostream&gt;

// N is the number of address bits you want to use
template&lt;std::size_t N&gt;
struct address_t
{
public:
    explicit constexpr address_t(std::uintptr_t value) :
        address{ checked_value(value) }
    {
    }

    // one of the rare cases implicit conversion is useful
    operator std::uintptr_t() const noexcept
    {
        return address;
    }

    // assigment operator checks the value.
    void operator=(std::uintptr_t value)
    {
        address = checked_value(value);
    }

private:
    constexpr std::uintptr_t checked_value(std::uintptr_t value)
    {
        if (value &gt;= (1 &lt;&lt; N)) throw std::invalid_argument(&quot;address value too large&quot;);
        return value;
    }

    std::uintptr_t address;
};

int main()
{
    //addres_t&lt;4&gt; means an address with max. 4 bits
    static constexpr address_t&lt;4&gt; compile_time_address{15}; // will not compile if value too big
    std::cout &lt;&lt; compile_time_address &lt;&lt; &quot;\n&quot;; // uses implicit conversion to std::uint_ptr_t

    address_t&lt;4&gt; runtime_address{15};
    std::cout &lt;&lt; runtime_address &lt;&lt; &quot;\n&quot;;
    runtime_address = 12;
    std::cout &lt;&lt; runtime_address &lt;&lt; &quot;\n&quot;;

    try
    {
        // at runtime assigning an invalid value will throw.
        address_t&lt;4&gt; runtime_address_fail{16};
    }
    catch (const std::invalid_argument&amp;)
    {
    }

    return 0;
}

huangapple
  • 本文由 发表于 2023年6月29日 14:43:18
  • 转载请务必保留本文链接:https://go.coder-hub.com/76578614.html
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