将行转换为列并在Postgres中筛选出值

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英文:

Transform rows to column and filter out the values in postgres

问题

我有两个表格,表格1中的数据是按行排列的。表格1中的关键列现在作为行,我想要将其转换为列。以下是我现在的表格内容。

我在表格1中的数据如下:

表格1

ticket_ID	Key	    Value	  Created_at
1	        123	    Free	  2023-06-01
1	        type	task	  2023-06-01
1	        status	open	  2023-06-01
1	        channel	email	  2023-06-01
1	        456	    fruit	  2023-06-01
2	        123	    paid	  2023-06-01
2	        type	incident  2023-06-01
2	        status	closed	  2023-06-01
2	        channel	voice	  2023-06-01
2	        456	    vegetable 2023-06-01

表格2具有我需要与表格1连接的创建日期,还需要连接主题和类型。

表格2

ID	Created_at	type	    subject
1	2023-06-01	task	    XXX
2	2023-06-01	incident	abc
3	2023-06-01	task	    def

我尝试了以下查询代码:

select t.ticket_id,t.created_at,t.value
    min(case when t.key = 123 then t.value end) as plan,
    min(case when t.key = 456 then t.value end) as category
from t1 t
join t2 te on t.ticket_id = te.id
where t.created_at >= '2023-06-01' and t.created_at <= '2023-06-21' 
GROUP by t.id,t.created_at

当我尝试这样做时,ID会再次重复,因为关键字具有多个值,我无法按ID分组。

期望的输出:

ID.     123(重命名为plan)     status.       456(重命名为category).   type.      created at
1         Free                   open             Fruit                  task        2023-06-01
2         Paid                   closed           vege                   incident    2023-06-01
英文:

I have two tables and the data in table 1 is in rows. Key column in table 1 has the columns that are as rows now and want to trasnform to column Below is how i have the table now.

The data i have in table 1 is as below

Table 1

tickedt_ID	Key	    Value	  Created_at
1	123	    Free	  2023-06-01
1	type	task	  2023-06-01
1	status	open	  2023-06-01
1	channel	email	  2023-06-01
1	456	    fruit	  2023-06-01
2	123	    paid	  2023-06-01
2	type	incident  2023-06-01
2	status	closed	  2023-06-01
2	channel	voice	  2023-06-01
2	456	    vegetable 2023-06-01

Table 2 has the created at date which i need to join with table 1 and also need to join subject and type.

Table 2

ID	Created_at	type	    subject
1	2023-06-01	task	    XXX
2	2023-06-01	incident	abc
3	2023-06-01	task	    def

Code i tried quering

select t.ticket_id,t.created_at,t.value
    min(case when t.key = 123 then t.value end) as plan,
    min(case when t.key = 456 then t.value end) as category
from t1 t
join t2 te on t.ticket_id = te.id
where t.created_at &gt; &#39;2023-06-01&#39; and t.created_at &lt;= &#39;2023-06-21&#39; 
GROUP by t.id,t.created_at

when i try this the id is getting repeated again because they key has got multiple values and i am not able to group by the id

Expected output

ID.     123(rename as plan)     status.       456(rename as category).   type.      created at
1         Free                   open             Fruit                  task        2023-06-01
2         Paid                   closed           vege                   incident    2023-06-01

答案1

得分: 0

您的数据不会返回任何内容,因为没有日期在2023年06月01日之后。假设这是一个打字错误:

```sql
CREATE TABLE t1 (
  ticket_ID INTEGER,
  Key VARCHAR(13),
  Value VARCHAR(20),
  Created_at TIMESTAMP
);

INSERT INTO t1
  (ticket_ID, Key, Value, Created_at)
VALUES
  ('1', '123', 'Free', '2023-06-01'),
  ('1', 'type', 'task', '2023-06-01'),
  ('1', 'status', 'open', '2023-06-01'),
  ('1', 'channel', 'email', '2023-06-01'),
  ('1', '456', 'fruit', '2023-06-01'),
  ('2', '123', 'paid', '2023-06-01'),
  ('2', 'type', 'incident', '2023-06-01'),
  ('2', 'status', 'closed', '2023-06-01'),
  ('2', 'channel', 'voice', '2023-06-01'),
  ('2', '456', 'vegetable', '2023-06-01');

CREATE TABLE t2 (
  ID INTEGER,
  Created_at TIMESTAMP,
  type VARCHAR(8),
  subject VARCHAR(3)
);

INSERT INTO t2
  (ID, Created_at, type, subject)
VALUES
  ('1', '2023-06-01', 'task', 'XXX'),
  ('2', '2023-06-01', 'incident', 'abc'),
  ('3', '2023-06-01', 'task', 'def');

SELECT ticket_id,
    MIN(CASE WHEN t1.key = '123' THEN t1.value END) AS plan,
    MIN(CASE WHEN t1.key = 'status' THEN t1.value END) AS status,
    MIN(CASE WHEN t1.key = '456' THEN t1.value END) AS category,
    MIN(CASE WHEN t1.key = 'type' THEN t1.value END) AS "type",
    created_at
FROM t1
WHERE t1.created_at >= '2023-06-01' AND t1.created_at <= '2023-06-21'
GROUP BY ticket_id, created_at;
ticket_id plan status category type created_at
1 Free open fruit task 2023-06-01 00:00:00
2 paid closed vegetable incident 2023-06-01 00:00:00

DBFiddle演示链接


<details>
<summary>英文:</summary>

Your data wouldn&#39;t return anything with that where criteria (no date is after 2023-06-01). Assuming that was a typo:

CREATE TABLE t1 (
ticket_ID INTEGER,
Key VARCHAR(13),
Value VARCHAR(20),
Created_at TIMESTAMP
);

INSERT INTO t1
(ticket_ID,Key,Value,Created_at)
VALUES
('1', '123', 'Free', '2023-06-01'),
('1', 'type', 'task', '2023-06-01'),
('1', 'status', 'open', '2023-06-01'),
('1', 'channel', 'email', '2023-06-01'),
('1', '456', 'fruit', '2023-06-01'),
('2', '123', 'paid', '2023-06-01'),
('2', 'type', 'incident', '2023-06-01'),
('2', 'status', 'closed', '2023-06-01'),
('2', 'channel', 'voice', '2023-06-01'),
('2', '456', 'vegetable', '2023-06-01');

CREATE TABLE t2 (
ID INTEGER,
Created_at TIMESTAMP,
type VARCHAR(8),
subject VARCHAR(3)
);

INSERT INTO t2
(ID,Created_at,type,subject)
VALUES
('1', '2023-06-01', 'task', 'XXX'),
('2', '2023-06-01', 'incident', 'abc'),
('3', '2023-06-01', 'task', 'def');

select ticket_id,
min(case when t1.key = '123' then t1.value end) as plan,
min(case when t1.key = 'status' then t1.value end) as status,
min(case when t1.key = '456' then t1.value end) as category,
min(case when t1.key = 'type' then t1.value end) as "type",
created_at
from t1
where t1.created_at >= '2023-06-01' and t1.created_at <= '2023-06-21'
GROUP by ticket_id, created_at;


| ticket\_id | plan | status | category | type | created\_at |
|----------:|:-----|:-------|:---------|:-----|:-----------|
| 1 | Free | open | fruit | task | 2023-06-01 00:00:00 |
| 2 | paid | closed | vegetable | incident | 2023-06-01 00:00:00 |


[DBFiddle demo](https://dbfiddle.uk/NEAVDAem)



</details>



# 答案2
**得分**: 0

假设表t1对于每个id只有一个不同键的出现,我认为您可以使用子查询来获取所需的列。尝试像这样,根据需要使用JOIN/WHERE/GROUP BY子句进行扩展。

```sql
SELECT t.id, 
       (SELECT value FROM t1 AS tplan WHERE tplan.id = t.id AND tplan.key = 123) as plan,
       (SELECT value FROM t1 AS tstat WHERE tstat.id = t.id AND tstat.key = 'status') as status,
       (SELECT value FROM t1 AS tcat WHERE tcat.id = t.id AND tcat.key = 456) as category
FROM t1 AS t
GROUP BY t.id
英文:

Assuming that the table t1 has just one occurrence of distinct keys for each id, I believe you could use subselects to get the columns you want. Try like something this, and extend it with JOIN/WHERE/GROUP BY clauses as needed.

SELECT t.id, 
       (SELECT value FROM t1 AS tplan WHERE tplan.id = t.id AND tplan.key = 123) as plan,
       (SELECT value FROM t1 AS tstat WHERE tstat.id = t.id AND tstat.key = &#39;status&#39;) as status,
       (SELECT value FROM t1 AS tcat WHERE tcat.id = t.id AND tcat.key = 456) as category,
FROM t1 AS t
GROUP BY t.id

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  • 本文由 发表于 2023年6月22日 03:49:50
  • 转载请务必保留本文链接:https://go.coder-hub.com/76526688.html
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