如何通过不同的列比较和筛选SQL中的行

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英文:

How to compare and filter rows in SQL by various columns

问题

我有一个具有以下结构和内容的表格:
如何通过不同的列比较和筛选SQL中的行

正如您所见,FQDN和NAME可以相同,但TIMESTAMP始终不同。我一直在尝试删除旧记录,以仅保留最新的记录:
如何通过不同的列比较和筛选SQL中的行

您能否请教是否有办法实现我的目标?
这是我迄今为止获得的SQL查询:

SELECT devices.fqdn, ports.pid, ports.name, ports.`status`, `subStatus`.`substatus`, updateLog.previousValue, updateLog.newValue, `updateLog`.`user`, `updateLog`.`timestamp`, `user`.`email`
FROM `updateLog`
LEFT JOIN `user` ON user.id = updateLog.user 
LEFT JOIN ports ON updateLog.rowId=ports.pid
LEFT JOIN subStatus ON ports.subStatus=subStatus.id
LEFT JOIN slots ON ports.slot=slots.sid
LEFT JOIN devices ON slots.device=devices.did 
WHERE (updateLog.rowId IN (select pid from ports where status=2)) 
AND (updateLog.columnName = 'status' AND updateLog.tableName = 'ports' and updateLog.newValue=2) 
ORDER BY ports.pid asc LIMIT 1000;
英文:

I have a table with the following structure and content:
如何通过不同的列比较和筛选SQL中的行

As you can see, there can be the same FQDN and NAME, however, TIMESTAMP is always different.
I have been trying to get rid of the old records in order to leave only the newest ones:
如何通过不同的列比较和筛选SQL中的行
Could you please advise if there is a way for we to reach my goal?
Here is the SQL query I have got so far:

SELECT devices.fqdn, ports.pid, ports.name, ports.`status`, `subStatus`.`substatus`, updateLog.previousValue, updateLog.newValue, `updateLog`.`user`, `updateLog`.`timestamp`, `user`.`email`
FROM `updateLog`
LEFT JOIN `user` ON user.id = updateLog.user 
LEFT JOIN ports ON updateLog.rowId=ports.pid
LEFT JOIN subStatus ON ports.subStatus=subStatus.id
LEFT JOIN slots ON ports.slot=slots.sid
LEFT JOIN devices ON slots.device=devices.did 
WHERE (updateLog.rowId IN (select pid from ports where status=2)) 
AND (updateLog.columnName = 'status' AND updateLog.tableName = 'ports' and updateLog.newValue=2) 
ORDER BY ports.pid asc LIMIT 1000;

答案1

得分: 1

要获取每个组的顶部行通常使用窗口函数来解决(这里可以使用MAX OVERROW_NUMBERRANKDENSE_RANK)。

以下是使用ROW_NUMBER的查询:

SELECT *
FROM
(
  SELECT
    d.fqdn,
    p.pid, p.name, p.status,
    ss.substatus,
    ul.previousvalue, ul.newvalue, ul.user, ul.timestamp,
    user.email,
    ROW_NUMBER() OVER (PARTITION BY d.fqdn, p.name ORDER BY ul.timestamp DESC) AS rn
  FROM updatelog ul
  LEFT JOIN ports p ON ul.rowId = p.pid
  LEFT JOIN substatus ss ON p.ss = ss.id
  LEFT JOIN slots s ON p.slot = s.sid
  LEFT JOIN devices d ON s.device = d.did 
  WHERE ul.rowId IN (SELECT pid FROM ports WHERE status = 2)
  AND ul.columnname = 'status'
  AND ul.tablename = 'p'
  AND ul.newvalue = 2 
) ranked
WHERE rn = 1;
英文:

To get the top row(s) per group is usually solved with window functions (either MAX OVER here, ROW_NUMBER, RANK or DENSE_RANK).

Here is the query with ROW_NUMBER:

SELECT *
FROM
(
  SELECT
    d.fqdn,
    p.pid, p.name, p.status,
    ss.substatus,
    ul.previousvalue, ul.newvalue, ul.user, ul.timestamp,
    user.email,
    ROW_NUMBER() OVER (PARTITION BY d.fqdn, p.name ORDER BY ul.timestamp DESC) AS rn
  FROM updatelog ul
  LEFT JOIN ports p ON ul.rowId = p.pid
  LEFT JOIN substatus ss ON p.ss = ss.id
  LEFT JOIN slots s ON p.slot = s.sid
  LEFT JOIN devices d ON s.device = d.did 
  WHERE ul.rowId IN (SELECT pid FROM ports WHERE status = 2)
  AND ul.columnname = 'status'
  AND ul.tablename = 'p'
  AND ul.newvalue = 2 
) ranked
WHERE rn = 1;

答案2

得分: 0

SELECT DISTINCT timestamp FROM table
LEFT JOIN SELECT other rows

英文:

SELECT DISTINCT timestamp FROM table
LEFT JOIN SELECT other rows

答案3

得分: 0

获取每个(fqdn和name)的最新时间戳:

SELECT fqdn, name, MAX(Timestamp)
FROM tableName
GROUP BY fqdn, name

如果您需要返回其他字段:

SELECT t1.fqdn, t1.name, t1.user, t1.Timestamp
FROM tableName t1
WHERE timestamp = (
    SELECT MAX(timestamp)
    FROM tableName t2 WHERE t1.fqdn = t2.fqdn AND t1.name = t2.name
)
英文:

To get the latest timestamp from each (fqdn and name):

SELECT fqdn, name, MAX(Timestamp)
FROM tableName
GROUP BY fqdn, name

If you need to return other fields:

SELECT t1.fqdn, t1.name, t1.user, t1.Timestamp
FROM tableName t1
WHERE timestamp = (
	SELECT MAX(timestamp)
	FROM tableName t2 WHERE t1.fqdn = s2.fqdn AND t1.name = t2.name
)

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  • 本文由 发表于 2023年6月16日 14:18:02
  • 转载请务必保留本文链接:https://go.coder-hub.com/76487404.html
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