英文:
Remove dictionary in list Python
问题
以下是翻译好的部分：
我有两个字典：output 包含一个主数据集，其中包括一列相关项目，而 output_historical 包含了 output 列表中项目的一个子集。
我想将 output_historical 键的值添加到 output 的值中，但如果 output_historical 中没有值，就删除整个列表项。在下面的过度简化示例中，{'test2': {'info': '1'}} 应该从 output 中删除。
output_historical = [
{'test1': {'result': 0},
'test3': {'result': 3}
}
]
output = [
{'tests':
[
{'test1': {'info': '0'}},
{'test2': {'info': '1'}},
{'test3': {'info': '2'}}
]
}
]
for item in output:
for testobject in item["tests"]:
for test in testobject.copy():
if test in output_historical[0]:
print("add", test)
testobject[test]["result"] = output_historical[0][test]["result"]
else:
print("del", test)
# del ??
print(output)
# 期望输出：[{'tests': [{'test1': {'info': '0', 'result': 0}}, {'test2': {'info': '1'}}, {'test3': {'info': '2', 'result': 3}}]}]
请注意，代码部分没有进行翻译。
英文:
I have two dictionaries: output contains a main dataset including a list of relevant items and output_historical contains a subset of the items in the list of output.
I would like to add the value of the output_historical keys to the output values, but delete the whole list-item if there is no value in output_historical. In the over-simplified example below, {'test2': {'info': '1'}} should be deleted from output.
output_historical = [
{
'test1': {'result': 0},
'test3': {'result': 3}
}
]
output = [
{'tests':
[
{'test1': {'info': '0'}},
{'test2': {'info': '1'}},
{'test3': {'info': '2'}}
]
}
]
for item in output:
for testobject in item["tests"]:
for test in testobject.copy():
if test in output_historical[0]:
print("add", test)
testobject[test]["result"] = output_historical[0][test]["result"]
else:
print("del", test)
# del ??
print(output)
# Expected output: [{'tests': [{'test1': {'info': '0', 'result': 0}}, {'test2': {'info': '1'}}, {'test3': {'info': '2', 'result': 3}}]}]
答案1
得分: 1
使用 remove() 方法。
由于不应从正在迭代的列表中删除元素，您应该在列表的副本上进行迭代。我认为您不需要复制 testobject，因为您在该字典中从未添加或删除任何内容。
for item in output:
for testobject in item["tests"].copy():
for test in testobject:
if test in output_historical[0]:
print("add", test)
testobject[test]["result"] = output_historical[0][test]["result"]
else:
print("del", test)
item["tests"].remove(testobject)
break
英文:
Use the remove() method.
Since you shouldn't remove from a list that you're iterating over, you should iterate over a copy of the list. I don't think you need to make a copy of testobject, since you're never adding or removing anything in that dictionary.
for item in output:
for testobject in item["tests"].copy():
for test in testobject:
if test in output_historical[0]:
print("add", test)
testobject[test]["result"] = output_historical[0][test]["result"]
else:
print("del", test)
item["tests"].remove(testobject)
break
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