自动化无聊的事情使用Python – 逗号代码练习

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英文:

Automate the boring stuff with Python - Comma Code exercise

问题

PS：这本书还没有涉及到使用join函数，所以你必须使用if、elif和else。之前问过这个问题，但这只是第2-3章，我们还没有用到join函数。

所以在《自动化繁琐的事情中的逗号代码练习》中，你需要创建一个列表，并在每个项目之间使用逗号打印它们，并在最后一个项目之前添加“和”。

示例：

  1. spam = ['apples', 'bana', 'apple']
  2. def commacode(passedlist):
  3.     stringy = ''
  4.     if len(passedlist) == 1:
  5.         stringy += str(passedlist[0])
  6.         return stringy
  7.     for i in range(len(passedlist) - 1):
  8.         stringy += str(passedlist[i]) + ', '
  9.         # 添加除最后一个项目外的所有项目到字符串中
  10.     stringy += 'and ' + str(passedlist[len(passedlist) - 1])
  11.     # 在“and”之后添加最后一个项目到字符串中
  12.     return stringy
  14. print(commacode(spam))

输出结果是：apples, bana, and apple。

然而，如果只有两个项目，它将打印出“apples, and bana”，这在语法上是不正确的。所以我的问题是，我该如何使它正确？我尝试添加elif和else语句，但它破坏了我的代码，我没有保存它来展示给你们（抱歉）。

英文:

PS The book doesn't reach the join function yet so you have to use if,elif and else. Asked the question before but this is only like chapter 2-3 guys, We haven't gotten to use join yet

So in the comma code exercise in automate the boring stuff you have to create a list and print it out using commas between each item and add 'and' before the last item.

Example

  1. spam = ['apples','bana', 'apple']
  2. def commacode(passedlist):
  3.     stringy = ''
  4.     if len(passedlist) == 1:
  5.         stringy += str(passedlist[0])
  6.         return stringy
  7.     for i in range(len(passedlist)-1):
  8.         stringy += str(passedlist[i]) + ', '
  9.         # adds all except last item to str
  10.     stringy += 'and ' + str(passedlist[len(passedlist)-1])
  11.     # adds last item to string, after 'and'
  12.     return stringy
  13. print(commacode(spam))

outputs apples , bana, and apple.

However if it is only two items it would print out apples, and bana which isnt grammatically correct. So my question is how would I make it correct I tried adding a elif and else statement but it broke my code and I didn't save it to show you guys(sorry)

答案1

得分: 2

以下是翻译好的代码部分：

  1. def commacode(words):
  2.     if len(words) == 1:
  3.         return words[0]
  4.     if len(words) == 2:
  5.         return f"{words[0]} and {words[1]}"
  6.     ret = ""
  7.     for word in words[:-1]:
  8.         ret += f"{word}, "
  9.     return ret + f"and {words[-1]}"
  11. print(commacode(["spam"]))  # spam
  12. print(commacode(["spam", "eggs"]))  # spam and eggs
  13. print(commacode(["spam", "eggs", "spam", "spam"]))
  14. # spam, eggs, spam, and spam

请注意，代码部分已翻译，其余部分未翻译。

英文:

It's easiest to handle 1- and 2-length lists as special cases. They're both simple enough that you can take care of them in a single line of code (with no looping involved), and then loop to handle all the remaining cases (which are all done in the same way):

  1. def commacode(words):
  2.     if len(words) == 1:
  3.         return words[0]
  4.     if len(words) == 2:
  5.         return f"{words[0]} and {words[1]}"
  6.     ret = ""
  7.     for word in words[:-1]:
  8.         ret += f"{word}, "
  9.     return ret + f"and {words[-1]}"
  11. print(commacode(["spam"]))  # spam
  12. print(commacode(["spam", "eggs"]))  # spam and eggs
  13. print(commacode(["spam", "eggs", "spam", "spam"]))
  14. # spam, eggs, spam, and spam

答案2

得分: 1

  1. 一个elif和else语句是你需要的，你的想法是正确的。
英文:

An elif, and else statement is what you need, you were on the right track.

  1. spam = ['apples','banana','apple']
  2. def commacode(passedlist):
  3.     stringy = ''
  4.     if len(passedlist) == 1:
  5.         stringy += str(passedlist[0])
  6.         return stringy
  7.     # added the elif here to check if list is only 2 objects
  8.     elif len(passedlist) == 2:
  9.         # this adds the strings together 
  10.         stringy = passedlist[0] + ' and ' + passedlist[1]
  11.     # else statement is required so this code only runs
  12.     # if the list is not of length 1 or 2
  13.     else:
  14.         for i in range(len(passedlist)-1):
  15.             stringy += str(passedlist[i]) + ', '
  16.             # adds all except last item to str
  17.         stringy += 'and ' + str(passedlist[len(passedlist)-1])
  18.         # adds last item to string, after 'and'
  19.     return stringy
  20. print(commacode(spam))

You had the right idea with the elif and else statement, I would just imagine that you might have had indentations wrong or something.

答案3

得分: 0

  1. spam = ['apples', 'bana', 'apple']
  3. def commacode(passedlist):
  4.     stringy = ''
  5.     for i in range(len(passedlist)):
  6.         if i == len(passedlist) - 1 and i > 0:
  7.             stringy += " and "
  8.         stringy += passedlist[i]
  9.         if i < len(passedlist) - 2:
  10.             stringy += ", "
  11.     return stringy
  13. print(commacode(spam))
英文: 
  1. spam = [&#39;apples&#39;, &#39;bana&#39;, &#39;apple&#39;]
  3. def commacode(passedlist):
  4.     stringy = &#39;&#39;
  5.     for i in range(len(passedlist)):
  6.         if i==len(passedlist)-1 and i&gt;0:
  7.             stringy += &quot; and &quot;
  8.         stringy += passedlist[i]
  9.         if i&lt;len(passedlist)-2:
  10.             stringy+= &quot;, &quot;
  11.     return stringy
  13. print(commacode(spam))

huangapple
  • 本文由 发表于 2023年6月16日 02:50:06
  • 转载请务必保留本文链接：https://go.coder-hub.com/76484679.html
  • arrays
  • if-statement
  • list
  • python
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