英文:
Break down comma separated values into children nodes
问题
我有一个列表，格式如下：
[[2020,
'September',
9,
'12:00',
'1',
28,
'Breaking',
7.0,
'Request Body Type Changed,API Path Removed Without Deprecation,Request Property Removed,Response Property Became Optional,Response Success Status Removed']]
这是我用列表创建的层次结构：
```python
{
'name': '12:00',
'children': [
{
'name': '1',
'value': 28,
'children': [
{
'name': 'Breaking',
'value': 7.0,
'children': [],
'hidden_children': [
{
'name': 'Request Body Type Changed,API Path Removed Without Deprecation,Request Property Removed,Response Property Became Optional,Response Success Status Removed',
'value': 7.0,
'itemStyle': {'color': '#ad213e'},
'label': {'rotate': 0}
}
],
'itemStyle': {'color': '#ad213e'}
}
]
}
]
}
但正如你所看到的，我把所有的子节点放在了逗号分隔的格式中。我想把它们作为单独的子节点放在层次结构中。这意味着对于Breaking父节点，不是一个hidden_children节点，而是4个hidden_children节点。
期望的层次结构是：
{
'name': '12:00',
'children': [
{
'name': '1',
'value': 28,
'children': [
{
'name': 'Breaking',
'value': 7.0,
'children': [],
'hidden_children': [
{
'name': 'Request Body Type Changed',
'value': 7.0,
'itemStyle': {'color': '#ad213e'},
'label': {'rotate': 0}
},
{
'name': 'API Path Removed Without Deprecation',
'value': 7.0,
'itemStyle': {'color': '#ad213e'},
'label': {'rotate': 0}
},
{
'name': 'Request Property Removed',
'value': 7.0,
'itemStyle': {'color': '#ad213e'},
'label': {'rotate': 0}
},
{
'name': 'Response Property Became Optional',
'value': 7.0,
'itemStyle': {'color': '#ad213e'},
'label': {'rotate': 0}
},
{
'name': 'Response Success Status Removed',
'value': 7.0,
'itemStyle': {'color': '#ad213e'},
'label': {'rotate': 0}
}
],
'itemStyle': {'color': '#ad213e'}
}
]
}
]
}
我不确定如何将字符串拆分成不同的子节点来绘制它们。
这是我创建这个层次结构的代码：
def create_hierarchy(api1):
# ...
# （代码未变）
# ...
if content:
if "," in content:
# ...
# （代码未变）
# ...
else:
content_node = {'name': content, 'value': count}
if type1 == 'Breaking':
content_node['itemStyle'] = {'color': '#ad213e'}
content_node['label'] = {'rotate': 0}
type_node['hidden_children'].append(content_node)
else:
type_node['children'].append(content_node)
type_node['itemStyle'] = {'color': '#ad213e'}
return root['children']
# （代码未变）
# ...
hierarchy1 = create_hierarchy(api1)
这里的api1是我的列表的名称。
是否有人有建议或者想法，我该如何做到这一点？
<details>
<summary>英文:</summary>
I have a list which is of this format:
[[2020,
'September',
9,
'12:00',
'1',
28,
'Breaking',
7.0,
'Request Body Type Changed,API Path Removed Without Deprecation,Request Property Removed,Response Property Became Optional,Response Success Status Removed']]
This is the hierarchy I have created with the list:
{
'name': '12:00',
'children': [
{
'name': '1',
'value': 28,
'children': [
{
'name': 'Breaking',
'value': 7.0,
'children': [
],
'hidden_children': [
{
'name': 'Request Body Type Changed,API Path Removed Without Deprecation,Request Property Removed,Response Property Became Optional,Response Success Status Removed',
'value': 7.0,
'itemStyle': {
'color': '#ad213e'
},
'label': {
'rotate': 0
}
}
],
'itemStyle': {
'color': '#ad213e'
}
}
]
}
]
}
However as you can see I have all the children in a comma separated format. What I want to do this put them as separate children in the hierarchy. Which means instead of one `hidden_children` node for `Breaking` parent node, there will be `4 hidden_children`.
The expected hierarchy is:
{
'name': '12:00',
'children': [
{
'name': '1',
'value': 28,
'children': [
{
'name': 'Breaking',
'value': 7.0,
'children': [],
'hidden_children': [
{
'name': 'Request Body Type Changed',
'value': 7.0,
'itemStyle': {'color': '#ad213e'},
'label': {'rotate': 0}
},
{
'name': 'API Path Removed Without Deprecation',
'value': 7.0,
'itemStyle': {'color': '#ad213e'},
'label': {'rotate': 0}
},
{
'name': 'Request Property Removed',
'value': 7.0,
'itemStyle': {'color': '#ad213e'},
'label': {'rotate': 0}
},
{
'name': 'Response Property Became Optional',
'value': 7.0,
'itemStyle': {'color': '#ad213e'},
'label': {'rotate': 0}
},
{
'name': 'Response Success Status Removed',
'value': 7.0,
'itemStyle': {'color': '#ad213e'},
'label': {'rotate': 0}
}
],
'itemStyle': {'color': '#ad213e'}
}
]
}
]
}
I am not sure how can I split the string to graph them out as different children nodes.
This is my code for creating this hierarchy:
def create_hierarchy(api1):
root = {"name": "root", "children": []}
for row in api1:
year, month, day, time, info_version, api_changes, type1, count, content = row + [None] * (9 - len(row))
year_node = None
for node in root["children"]:
if node["name"] == year:
year_node = node
break
if not year_node:
year_node = {"name": year, "children": []}
root["children"].append(year_node)
month_node = None
for node in year_node["children"]:
if node["name"] == month:
month_node = node
break
if not month_node:
month_node = {"name": month, "children": []}
year_node["children"].append(month_node)
day_node = None
for node in month_node["children"]:
if node["name"] == str(day):
day_node = node
break
if not day_node:
day_node = {"name": str(day), "children": []}
month_node["children"].append(day_node)
hour_node = {"name": str(time), "children": []}
day_node["children"].append(hour_node)
info_node = {"name": info_version, "value": api_changes, "children": []}
hour_node["children"].append(info_node)
if type1:
type_node = None
for node in info_node["children"]:
if node["name"] == type1:
type_node = node
break
if not type_node:
type_node = {"name": type1, "value": count, "children": []}
info_node["children"].append(type_node)
if type1 == "Breaking":
type_node["hidden_children"] = []
type_node["itemStyle"] = {"color": "#ad213e"}
if content:
if "," in content:
content_list = content.split(", ")
for content in content_list:
content_node = {"name": content, "value": count}
if type1 == "Breaking":
content_node["itemStyle"] = {"color": "#ad213e"}
content_node["label"] = {"rotate": 0}
type_node["hidden_children"].append(content_node)
else:
type_node["children"].append(content_node)
type_node["itemStyle"] = {"color": "#ad213e"}
else:
content_node = {"name": content, "value": count}
if type1 == "Breaking":
content_node["itemStyle"] = {"color": "#ad213e"}
content_node["label"] = {"rotate": 0}
type_node["hidden_children"].append(content_node)
else:
type_node["children"].append(content_node)
type_node["itemStyle"] = {"color": "#ad213e"}
return root["children"]
hierarchy1 = create_hierarchy(api1)
`api1` here is the name of my list.
Does anyone have suggestions or ideas how I could do this?
</details>
# 答案1
**得分**: 1
使用列表推导来创建包含逗号分隔字符串中每个元素的字典列表。
通过使用一个变量来保存键（要么是`children`要么是`hidden_children`）来避免所有重复的`if`语句中的重复代码。
```python
if content:
children_key = "hidden_children" if type1 == "Breaking" else "children"
content_list = content.split(",")
type_node[children_key] = [
{"name": c, "value": count, "itemStyle": {"color": "#ad213e"}, "label": {"rotate": 0}}
for c in content_list]
无需测试content中是否存在逗号，因为split()会返回一个包含一个字符串的列表，如果逗号不存在，遍历它将返回一个包含一个子项的列表。
英文:
Use a list comprehension to create the list of dictionaries for each element of the comma-separated string.
Avoid all the duplicate code in if statements by using a variable to hold the key, either children or hidden_children.
if content:
children_key = "hidden_children" if type1 == "Breaking" else "children"
content_list = content.split(",")
type_node[children_key] = [
{"name": c, "value": count, "itemStyle": {"color": "#ad213e"}, "label": {"rotate": 0}}
for c in content_list]
There's no need for testing whether comma is in content, because split() will return a list of one string if it doesn't exist, and looping over that will return a list of one child.
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