英文:
Replacing backslashes in golang
问题
我们可以如何在Golang中替换反斜杠，类似于Python中的操作：
// Golang implementation
package main
import (
"fmt"
"strings"
)
func main() {
regexp := `\\\\`
cleanedRegexp := strings.ReplaceAll(regexp, `\\`, `%temp%`)
cleanedRegexp = strings.ReplaceAll(cleanedRegexp, `%temp%`, `\`)
fmt.Println(cleanedRegexp)
}
在Golang中，我们可以使用strings.ReplaceAll函数来替换字符串中的子字符串。在上面的示例中，我们首先将两个反斜杠替换为%temp%，然后再将%temp%替换为单个反斜杠。最后，我们打印出替换后的字符串cleanedRegexp。
希望对你有所帮助！
英文:
How can we replace back slashes in golang something similar to we do in python:
# python implementation
cleaned_regexp = regexp.replace('\\\\', '%temp%').replace('\\\\', '\\')
Transitioning from python to golang and very recently started with development in go so any help will be really great.
Thanks
答案1
得分: 1
根据评论者的指示，由于包含两个反斜杠字符的字符串不需要特殊匹配，因此无需使用正则表达式。更简单的方法是使用strings.ReplaceAll()。
还要注意，使用原始字符串字面值（用反引号括起来）可以使代码更容易理解，因为它避免了对反斜杠的解释。
s := `foo\\bar`
oldstr := `\\`
newstr := "%temp%"
strings.ReplaceAll(s, oldstr, newstr) // => "foo%temp%bar"
在Go Playground上试一试。
英文:
As noted by commenters, there is no need to use a regular expression since the string containing two backslash characters requires no special matching. A simpler approach would be to use strings.ReplaceAll().
Note also that using a raw string literal (between back quotes) makes the code a bit easier to understand since it avoids interpreting the backslash.
<!-- language: lang-go -->
s := `foo\\bar`
oldstr := `\\`
newstr := "%temp%"
strings.ReplaceAll(s, oldstr, newstr) // => "foo%temp%bar"
Try it on the Go Playground.
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