英文:
Slice two datetime objects with Python
问题
我有两个 Python 2.7 中的日期时间对象。
第一个看起来像这样：
2018-09-22 00:00:00
而第二个看起来像这样：
1899-12-30 17:20:59
我想要的是从第一个日期时间对象获取日期，从第二个日期时间对象获取时间。
2018-09-22 17:20:59
不幸的是，我在编写一些古老的 GIS 软件，被迫使用 2.7 版本。感谢任何帮助。
英文:
I have two date time objects in Python 2.7.
The first looks like this:
2018-09-22 00:00:00
and the second looks like this:
1899-12-30 17:20:59
I would like to end up with the dates from the first datetime object and the time from the second datetime object.
2018-09-22 17:20:59
Unfortunately I am coding for some old GIS software and compelled to use 2.7
Any help is appreciated.
答案1
得分: 1
请看datetime.datetime.replace()和datetime.datetime.combine()方法：
>>> from datetime import datetime
>>> dt1 = datetime.strptime('2018-09-22 00:00:00', '%Y-%m-%d %H:%M:%S')
>>> dt2 = datetime.strptime('1899-12-30 17:20:59', '%Y-%m-%d %H:%M:%S')
>>> dt3 = dt1.replace(hour=dt2.hour, minute=dt2.minute, second=dt2.second)
>>> dt3
datetime.datetime(2018, 9, 22, 17, 20, 59)
# 或者更好的方法
>>> dt4 = datetime.combine(dt1.date(), dt2.time())
>>> dt4
datetime.datetime(2018, 9, 22, 17, 20, 59)
英文:
Have a look at datetime.datetime.replace() and datetime.datetime.combine() methods:
>>> from datetime import datetime
>>> dt1 = datetime.strptime('2018-09-22 00:00:00', '%Y-%m-%d %H:%M:%S')
>>> dt2 = datetime.strptime('1899-12-30 17:20:59', '%Y-%m-%d %H:%M:%S')
>>> dt3 = dt1.replace(hour=dt2.hour, minute=dt2.minute, second=dt2.second)
>>> dt3
datetime.datetime(2018, 9, 22, 17, 20, 59)
# or even better
>>> dt4=datetime.combine(dt1.date(), dt2.time())
>>> dt4
datetime.datetime(2018, 9, 22, 17, 20, 59)
答案2
得分: 0
如果这两个时间戳都是datetime对象，您可以像这样解析它们的部分：
import datetime as dt
fmt = '%Y-%d-%m %H:%M:%S'
one = dt.datetime.strptime('2018-09-22 00:00:00', fmt)
two = dt.datetime.strptime('1899-12-30 17:20:59', fmt)
# 从第一个时间戳获取日期
# 从第二个时间戳获取时间
# 使用这些信息创建一个新的datetime对象
new_timestamp = dt.datetime.combine(one.date(), two.time())
print(new_timestamp)
# => 2018-09-22 17:20:59
英文:
If both of these timestamps are datetime objects, you should be able to parse out portions of them like so
import datetime as dt
fmt = '%Y-%d-%m %H:%M:%S'
one = dt.datetime.strptime('2018-09-22 00:00:00', fmt)
two = dt.datetime.strptime('1899-12-30 17:20:59', fmt)
# get the 'date' from the first timestamp
# get the 'time' from the second timestamp
# create a new datetime object with this info
new_timestamp = dt.datetime.combine(one.date(), two.time())
print(new_timestamp)
# => 2018-09-22 17:20:59
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