JavaScript检查元音字母的函数

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英文:

JavaScript function to check for vowels

问题

这是我目前拥有的代码:

const myString = "Testing for vowels";

const vowels = ["a", "e", "i", "o", "u", "y"];

function countVowels(myString) {
  let count = 0;

  if (vowels.includes(myString)) {
    count++;
  }

  return count
}

const result = countVowels(myString);

console.log(result);

这段代码的问题在于你尝试检查整个字符串是否包含在 vowels 数组中,而不是检查字符串中的每个字符是否在 vowels 中出现。要修复这个问题,你需要使用一个循环来遍历字符串中的每个字符,然后检查该字符是否在 vowels 数组中。

以下是修复后的代码:

const myString = "Testing for vowels";

const vowels = ["a", "e", "i", "o", "u", "y"];

function countVowels(myString) {
  let count = 0;

  for (let i = 0; i < myString.length; i++) {
    if (vowels.includes(myString[i])) {
      count++;
    }
  }

  return count;
}

const result = countVowels(myString);

console.log(result);

这个修复后的代码将遍历字符串 myString 中的每个字符,然后检查它是否是元音字母,并适当地增加计数器。

英文:

I know this is a basic questions, but I'm trying to work through a beginner's coding problem and I'm stuck on why this code doesn't work.

This is what I have so far:

<!-- begin snippet: js hide: false console: true babel: false -->

<!-- language: lang-js -->

const myString = &quot;Testing for vowels&quot;;

const vowels = [&quot;a&quot;, &quot;e&quot;, &quot;i&quot;, &quot;o&quot;, &quot;u&quot;, &quot;y&quot;];

function countVowels(myString) {
  let count = 0;


  if (vowels.includes(myString)) {
    count++;
  }

  return count
}

const result = countVowels(myString);

console.log(result);

<!-- end snippet -->

When it logs out, it just stays 0. Clearly I'm missing something, but I'm not sure what it is at this point. I've set up what vowels are, I think I'm asking that, if the vowels I set in the array are in my string, increase the count, but it's just giving me 0. I know it must be obvious, but I'm stuck.

I've tried a for loop, then I thought it may need to be an if statement, now I have that in a function. I haven't been able to get the answer either way, so I don't think I'm properly telling the code what the vowels are, but I'm not sure how to do that.

答案1

得分: 2

你需要使用一个for循环来检查每个字符是否包含在元音字母数组中,代码如下:

const myString = "Testing for vowels";

const vowels = ["a", "e", "i", "o", "u", "y"];

function countVowels(myString) {
  let count = 0;

  for(let i = 0; i < myString.length; i++) {
    if(vowels.includes(myString[i])) {
      count++;
    }
  }

  return count;
}

const result = countVowels(myString);

console.log(result);

这段代码会计算在myString中有多少个元音字母,并将结果输出到控制台。

英文:

you have to use a for loop in order to check if each character is included in the vowels array like this :

const myString = &quot;Testing for vowels&quot;;

const vowels = [&quot;a&quot;, &quot;e&quot;, &quot;i&quot;, &quot;o&quot;, &quot;u&quot;, &quot;y&quot;];


function countVowels(myString) {
  let count = 0;

  for(let i = 0 ;  i &lt; myString.length ; i++) {
    if(vowels.includes(myString[i])) {
      count++ ; 
    }
  }

  return count
}

const result = countVowels(myString);

console.log(result);

答案2

得分: 1

以下是您要翻译的内容:

在不区分大小写并全局标记的正则表达式中,像 /[aeiou]/gi 这样的表达式在字符集中列出了所有元音字母,并通过 match 应用,已经完成了任务。后一操作要么返回一个数组,要么返回 null 值。因此,像下面这样的表达式...

'Testing for vowels'.match(/[aeiou]/gi)?.length ?? 0

...就是所需的全部内容。

为了防止在匹配为 null 的情况下出现 TypeError,其中无法访问 length 属性,但仍希望得到有意义的结果,可以同时使用Optional Chaining Operator / ?.Nullish Coalescing Operator / ??

示例代码...

console.log(
  "'Testing for vowels'.match(/[aeiou]/gi) ...",
  'Testing for vowels'.match(/[aeiou]/gi)
);
console.log(
  "'' .match(/[aeiou]/gi) ...",
  ''.match(/[aeiou]/gi)
);
console.log('\n');

console.log(
  "'Testing for vowels'.match(/[aeiou]/gi)?.length ?? 0 ...",
  'Testing for vowels'.match(/[aeiou]/gi)?.length ?? 0
);
console.log(
  "'' .match(/[aeiou]/gi)?.length ?? 0 ...",
  ''.match(/[aeiou]/gi)?.length ?? 0
);

然后,countVowels 的实现就像这样简单...

function countVowels(value) {
  return String(value).match(/[aeiou]/gi)?.length ?? 0;
}

...或者像这样...

function countVowels(value) {
  return String(value ?? '').match(/[aeiou]/gi)?.length ?? 0;
}

...其中后者可以如下进行测试...

function countVowels(value) {
  return String(value ?? '').match(/[aeiou]/gi)?.length ?? 0;
}

console.log(
  "countVowels('Testing for vowels') ...",
  countVowels('Testing for vowels')
);
console.log(
  "countVowels('') ...",
  countVowels('')
);
console.log('\n');

console.log(
  "countVowels() ...",
  countVowels()
);
console.log(
  "countVowels(null) ...",
  countVowels(null)
);
console.log('\n');

console.log(
  "countVowels('NULL') ...",
  countVowels('NULL')
);
console.log(
  "countVowels('UNDEFINED') ...",
  countVowels('UNDEFINED')
);
英文:

A simple case-insensitive and globally flagged regex like ... /[aeiou]/gi ... which within a character set does list all vowels, applied via match, already does the job. The latter operation either returns an array or the null value. Thus, an expression like ...

&#39;Testing for vowels&#39;.match(/[aeiou]/gi)?.length ?? 0

... is all what's needed.

And in order to prevent a TypeError in case of a null match, where one can not access a length property, but still wants to come up with a meaningful result, one might utilize both the Optional Chaining Operator / ?. and the Nullish Coalescing Operator / ??.

Example code ...

<!-- begin snippet: js hide: false console: true babel: false -->

<!-- language: lang-js -->

console.log(
  &quot;&#39;Testing for vowels&#39;.match(/[aeiou]/gi) ...&quot;,
  &#39;Testing for vowels&#39;.match(/[aeiou]/gi)
);
console.log(
  &quot;&#39;&#39;.match(/[aeiou]/gi) ...&quot;,
  &#39;&#39;.match(/[aeiou]/gi)
);
console.log(&#39;\n&#39;);

console.log(
  &quot;&#39;Testing for vowels&#39;.match(/[aeiou]/gi)?.length ?? 0 ...&quot;,
  &#39;Testing for vowels&#39;.match(/[aeiou]/gi)?.length ?? 0
);
console.log(
  &quot;&#39;&#39;.match(/[aeiou]/gi)?.length ?? 0 ...&quot;,
  &#39;&#39;.match(/[aeiou]/gi)?.length ?? 0
);

<!-- language: lang-css -->

.as-console-wrapper { min-height: 100%!important; top: 0; }

<!-- end snippet -->

The implementation of countVowels then is as easy as this ...

function countVowels(value) {
  return String(value).match(/[aeiou]/gi)?.length ?? 0;
}

... or that ...

function countVowels(value) {
  return String(value ?? &#39;&#39;).match(/[aeiou]/gi)?.length ?? 0;
}

... where the latter could be tested like follows ...

<!-- begin snippet: js hide: false console: true babel: false -->

<!-- language: lang-js -->

function countVowels(value) {
  return String(value ?? &#39;&#39;).match(/[aeiou]/gi)?.length ?? 0;
}

console.log(
  &quot;countVowels(&#39;Testing for vowels&#39;) ...&quot;,
  countVowels(&#39;Testing for vowels&#39;)
);
console.log(
  &quot;countVowels(&#39;&#39;) ...&quot;,
  countVowels(&#39;&#39;)
);
console.log(&#39;\n&#39;);

console.log(
  &quot;countVowels() ...&quot;,
  countVowels()
);
console.log(
  &quot;countVowels(null) ...&quot;,
  countVowels(null)
);
console.log(&#39;\n&#39;);

console.log(
  &quot;countVowels(&#39;NULL&#39;) ...&quot;,
  countVowels(&#39;NULL&#39;)
);
console.log(
  &quot;countVowels(&#39;UNDEFINED&#39;) ...&quot;,
  countVowels(&#39;UNDEFINED&#39;)
);

<!-- language: lang-css -->

.as-console-wrapper { min-height: 100%!important; top: 0; }

<!-- end snippet -->

答案3

得分: -1

const myString = "测试元音字母";

const vowels = ["a", "e", "i", "o", "u", "y"];

function countVowels(myString) {
  let count = 0;

  for(i = 0; i < myString.length; i++){
    if (vowels.includes(myString.substring(i,i+1))) {
      count++;
    }
  }
  return count
}

const result = countVowels(myString);

console.log(result);
英文:

<!-- begin snippet: js hide: false console: true babel: false -->

<!-- language: lang-js -->

const myString = &quot;Testing for vowels&quot;;

const vowels = [&quot;a&quot;, &quot;e&quot;, &quot;i&quot;, &quot;o&quot;, &quot;u&quot;, &quot;y&quot;];

function countVowels(myString) {
  let count = 0;

  for(i = 0; i &lt; myString.length; i++){
    if (vowels.includes(myString.substring(i,i+1))) {
      count++;
    }
   }
  return count
}

const result = countVowels(myString);

console.log(result);

<!-- end snippet -->

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  • 本文由 发表于 2023年5月30日 01:36:46
  • 转载请务必保留本文链接:https://go.coder-hub.com/76359315.html
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