英文:
What is wrong with my if else statements for my rock paper scissor game?
问题
I have translated the code for you. Here it is:
function getComputerChoice() {
const randomNumber = Math.floor(Math.random()*3);
switch(randomNumber) {
case 0:
return "rock";
case 1:
return "paper";
case 2:
return "scissors";
};
}
function getPlayerChoice() {
return prompt("rock, paper, or scissors?").toLowerCase();
}
function playRound(playerSelection, computerSelection) {
computerSelection = getComputerChoice();
playerSelection = getPlayerChoice();
if (computerSelection === playerSelection) {
console.log("Tie");
} else if (computerSelection === "rock" && playerSelection === "scissors") {
console.log("You lose! Rock beats Scissors");
} else if (computerSelection === "paper" && playerSelection === "rock") {
console.log("You lose! Paper beats Rock");
} else if (computerSelection === "scissors" && playerSelection === "paper") {
console.log("You lose! Scissors beats Paper");
} else if (playerSelection === "rock" && computerSelection === "scissors") {
console.log("You win! Rock beats Scissors");
} else if (playerSelection === "paper" && computerSelection === "rock") {
console.log("You win! Paper beats Rock");
} else if (playerSelection === "scissors" && computerSelection === "paper") {
console.log("You win! Scissors beats Paper");
}
}
I've removed the HTML entities (e.g., ") and provided a cleaner version of your JavaScript code.
英文:
I am attempting to make a Rock Paper Scissors game in JavaScript, however, every time I run it the console logs the last option "You win! Scissors beats Paper" even if my selection was something other than scissors. I believe I made an error with my if else statements but maybe the problem comes from some other part.
function getComputerChoice() {
const randomNumber = Math.floor(Math.random()*3);
switch(randomNumber) {
case 0:
return "rock";
case 1:
return "paper";
case 2:
return "scissors";
};
}
function getPlayerChoice() {
prompt("rock paper or scissors?").toLowerCase();
}
function playRound (playerSelection,computerSelection) {
computerSelection = getComputerChoice()
playerSelection = getPlayerChoice()
if (computerSelection === playerSelection) {
console.log ("Tie");
}
else if (computerSelection === "rock" && playerSelection === "scissors") {
console.log ("You lose! Rock beats Scissors");
}
else if (computerSelection === "paper" && playerSelection === "rock") {
console.log ("You lose! Paper beats Rock");
}
else if (computerSelection === "scissors" && playerSelection === "paper") {
console.log ("You lose! Scissors beats Paper");
}
else if (playerSelection === "rock" && computerSelection === "scissors") {
console.log ("You win! Rock beats Scissors");
}
else if (playerSelection === "paper" && computerSelection === "rock") {
console.log ("You win! Paper beats Rock");
}
else (playerSelection === "scissors" && computerSelection === "paper") ;{
console.log ("You win! Scissors beats Paper");
}
}
答案1
得分: 1
有两个问题导致代码无法正常运行。首先，你的函数 getPlayerChoice() 没有返回任何值。结果，playerSelection === undefined 而不是你预期的值。由于你的 if 语句没有考虑到这一点，它们最终都变为 false。这导致了执行你的 else 语句。
应该是：
function getPlayerChoice() {
return prompt("rock paper or scissors?").toLowerCase();
}
第二个问题是 else 语句内部不应该有条件。
解决方案：
else {
console.log("You win! Scissors beats Paper");
}
请注意，在你的第一个函数的 switch 语句后面不需要分号，但似乎它并不导致代码故障。
英文:
There are two issues that makes the code not run as it should. The first is that your function getPlayerChoice() does not return any values. As a result, playerSelection === undefined instead of your intended values. Since your if statements don't account for that, they all end up false. This leads to your else statement being executed.
It should be:
function getPlayerChoice() {
return prompt("rock paper or scissors?").toLowerCase();
}
The second is that else should not have a condition inside it.
Solution:
else {
console.log ("You win! Scissors beats Paper");
}
Note that you don't need the semicolon after your switch statement in your first function, but it doesn't seem to cause the code to malfunction.
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