SQL函数,返回有效数字作为varchar。

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英文:

SQL function that returns significant figures as varchar

问题

I'm trying to modify a SQL function posted back in 2009. The function returns a float, but I need the trailing zeros as well. For example with 2 significant figures:

2153.012 -> "2200"
123.361 -> "120"
12.331 -> "12"
1.014 -> "1.0"
0.804 -> "0.80"
0.0011 -> "0.0011"
0.001 -> "0.0010"

EDIT: I should not have assumed people were familiar with significant figures (apologies). It's a simple way of distinguishing when 0s are place holders or values.

For numbers less than 1, the 0s immediately after the decimal are place holders, but trailing 0s are values. So, 0.0010 indicates that the zero after the 1 is a real value. With 3 sig figs, the number would need to be written as 0.00100.

For numbers larger than 1, it’s not always obvious without knowing the number of sig figs. For example, are the zeros in 2000 place holders or values?

EDIT2: Some more examples (upon request).

Large numbers

Measured 1 Sig Fig 2 Sig Figs 3 Sig Figs 4 Sig Figs 5 Sig Figs
80125.01255 80000 80000 80100 80130 80125
8012.01255 8000 8000 8010 8012 8012.0
801.012555 800 800 8.01 801.0 801.01
80.01255 80 80 80.0 80.01 80.013
8.01255 8 8.0 8.01 8.013 8.0126

Small numbers

Measured 1 Sig Fig 2 Sig Figs 3 Sig Figs 4 Sig Figs 5 Sig Figs
0.100362 0.1 0.10 0.100 0.1004 0.10036
0.010362 0.01 0.010 0.0104 0.01036 0.010362
0.001036 0.001 0.0010 0.00104 0.001036 0.0010360
0.000103 0.0001 0.00010 0.000103 0.0001030 0.00010300
0.000010 0.00001 0.000010 0.0000100 0.00001000 0.000010000
0.000001 0.000001 0.0000010 0.00000100 0.000001000 0.0000010000

The function I'm modifying is:

CREATE FUNCTION RoundSigFig(@Number float, @Figures int)
RETURNS float
AS
BEGIN

DECLARE @Answer float;

SET @Answer = (
SELECT
    CASE WHEN intPower IS NULL THEN 0
    ELSE FLOOR(fltNumber * POWER(CAST(10 AS float), intPower) +0.5) 
        *POWER(CAST(10 AS float), -intPower)
    END AS ans
FROM (
    SELECT
        @Number AS fltNumber,
        CASE WHEN @Number > 0
            THEN -((CEILING(LOG10(@Number)) -@Figures))
        WHEN @Number< 0
            THEN -((FLOOR(LOG10(@Number)) -@Figures))
        ELSE NULL END AS intPower       
    ) t
);

RETURN @Answer;

END

It works as advertised. To get the output as varchar, I've attempted the use the FORMAT function and a bunch of CASE expressions to pad out the needed zeros, but never managed to get it to work.

英文:

I'm trying to modify a SQL function posted back in 2009. The function returns a float, but I need the trailing zeros as well. For example with 2 significant figures:

2153.012 -> "2200"
123.361 -> "120"
12.331 -> "12"
1.014 -> "1.0"
0.804 -> "0.80"
0.0011 -> "0.0011"
0.001 -> "0.0010"

EDIT: I should not have assumed people were familiar with significant figures (apologies). It's a simple way of distinguishing when 0s are place holders or values.

For numbers less than 1, the 0s immediately after the decimal are place holders, but trailing 0s are values. So, 0.0010 indicates that the zero after the 1 is a real value. With 3 sig figs, the number would need to be written as 0.00100.

For numbers larger than 1, it’s not always obvious without knowing the number of sig figs. For example, are the zeros in 2000 place holders or values?

EDIT2: Some more examples (upon request).

Large numbers

Measured 1 Sig Fig 2 Sig Figs 3 Sig Figs 4 Sig Figs 5 Sig Figs
80125.01255 80000 80000 80100 80130 80125
8012.01255 8000 8000 8010 8012 8012.0
801.012555 800 800 8.01 801.0 801.01
80.01255 80 80 80.0 80.01 80.013
8.01255 8 8.0 8.01 8.013 8.0126

Small numbers

Measured 1 Sig Fig 2 Sig Figs 3 Sig Figs 4 Sig Figs 5 Sig Figs
0.100362 0.1 0.10 0.100 0.1004 0.10036
0.010362 0.01 0.010 0.0104 0.01036 0.010362
0.001036 0.001 0.0010 0.00104 0.001036 0.0010360
0.000103 0.0001 0.00010 0.000103 0.0001030 0.00010300
0.000010 0.00001 0.000010 0.0000100 0.00001000 0.000010000
0.000001 0.000001 0.0000010 0.00000100 0.000001000 0.0000010000

The function I'm modifying is:

CREATE FUNCTION RoundSigFig(@Number float, @Figures int)
RETURNS float
AS
BEGIN

    DECLARE @Answer float;

    SET @Answer = (
    SELECT
        CASE WHEN intPower IS NULL THEN 0
        ELSE FLOOR(fltNumber * POWER(CAST(10 AS float), intPower) +0.5) 
            *POWER(CAST(10 AS float), -intPower)
        END AS ans
    FROM (
        SELECT
            @Number AS fltNumber,
            CASE WHEN @Number > 0
                THEN -((CEILING(LOG10(@Number)) -@Figures))
            WHEN @Number< 0
                THEN -((FLOOR(LOG10(@Number)) -@Figures))
            ELSE NULL END AS intPower       
        ) t
    );

    RETURN @Answer;
END

It works as advertised. To get the output as varchar, I've attempted the use the FORMAT function and a bunch of CASE expressions to pad out the needed zeros, but never managed to get it to work.

答案1

得分: 0

这是要翻译的内容:

"这个问题需要非常特定的数字格式,参考资料为 columbia.edu 1columbia.edu 2

回答的第一部分是验证问题中提到的现有函数 (LimitSigFigs),该函数来自 2009 年 (链接在问题中)。这个函数确实有效,但我认为有一个更简单的等价函数 (LimitSigFigsv1)。我也认为保留一个返回浮点数的函数是有益的(例如,用于排序结果),因此可以在后续格式化中使用其中任何一个函数。

事实证明,这两个数字函数都已经完成了大部分的"繁重工作",实际上只需将输出强制转换为字符串,这可以通过 format 函数来完成(注意:我尝试使用 str(),但它的效果不如 format 好)。但是,指定的特殊格式需要对某些需要特殊处理的小数字添加一些额外的零。这是通过检查字符串的长度以及小数点后第一个非零数字的位置来完成的。这决定了是否需要额外的零,需要多少个零,然后在需要时附加它们。

最终,在经过多次迭代后,格式化函数非常简单(这很好!),希望性能表现合理。请注意,我选择准备了一个第二个函数,它将参数“传递”到现有的数字函数中,以简化操作。还要注意,用户定义的标量函数以性能而闻名,但它们非常方便。

以下是一个简化的四舍五入至显著数字的函数,您可以使用这个函数或原始函数,但请注意,我对其中任何一个都没有进行非常广泛的测试。

CREATE FUNCTION [dbo].[LimitSigFigsV1](@value FLOAT, @sigFigs INT) RETURNS FLOAT AS
BEGIN
  DECLARE @result FLOAT
  IF (@sigFigs < 1)
    SET @result = NULL
  ELSE
    SET @result = CASE WHEN @value = 0 THEN 0 
                       ELSE ROUND(@value, @sigFigs - 1 - FLOOR(LOG10(ABS(@value)))) 
                  END
  RETURN @result
END

然后,最终的格式化通过以下函数进行:

CREATE FUNCTION FormatSigFigsV2(@Number FLOAT, @Figures INT) RETURNS VARCHAR(200) AS 
BEGIN 
  DECLARE @Result VARCHAR(200); 
  SET @Result = FORMAT(dbo.LimitSigFigsv1(@Number, @Figures),'0.################'); 

  /* 计算有效数字的数量 */
  DECLARE @SigFigs INT = 0;
  DECLARE @i INT = 1;
  WHILE @i <= LEN(@Result) AND @SigFigs < @Figures
  BEGIN
    IF SUBSTRING(@Result, @i, 1) BETWEEN '1' AND '9'
      SET @SigFigs = @SigFigs + 1;
    SET @i = @i + 1;
  END

  /* 如果需要,添加尾随零 */
  IF CHARINDEX('.', @Result) > 0 AND @SigFigs < @Figures
    SET @Result = @Result + REPLICATE('0', @Figures - @SigFigs);
  ELSE IF CHARINDEX('.', @Result) = 0 AND @SigFigs < @Figures
    SET @Result = @Result + '.' + REPLICATE('0', @Figures - @SigFigs);

  RETURN @Result; 
END

它首先调用另一个名为 dbo.LimitSigFigsv1 的函数来限制输入数字的有效数字数量为指定的数字位数,然后通过迭代字符串中的每个字符并检查是否为非零数字来计算结果中的有效数字数量。如果结果包含小数点并且有效数字的数量小于指定的数字位数,则在小数点后添加尾随零,或者如果结果不包含小数点并且有效数字的数量小于指定的数字位数,则添加小数点后跟随尾随零。

请注意,我进行了有限的测试,使用了有效数字范围在 1 到 5 之间的表格(注:我将初始测试集从 80125.01255 更改为 87125.112550,以减少零的数量和位置,以避免混淆)。

这个答案的其余部分复制了一个 Fiddle 网站的详细信息,希望这可以让您了解进行的测试以及如何使用这些函数。"

这是您要求的翻译内容。如果有其他问题,请随时提出。

英文:

The question calls for a very specific style of numeric formatting, references for this are columbia.edu 1 and columbia.edu 2

The first part of answering was to verify the existing function (LimitSigFigs) from 2009 (link in the question). This does work but I believe there is a simpler equivalent (LimitSigFigsv1). I also believe that it is beneficial to retain a function that will return a float (e.g. for use in ordering results) so either of these functions may be used in the subsequent formating.

As it turns out both of the numeric functions do most of the "heavy lifting" and in the main all one needs to do is force that output into a string, which can be done via the format function (nb: I tried str() and it simply did not work as well as format does). However the special formatting specified requires some additional zeros to small numbers that require some special handling. This is done by inspecing the length of the string and the position of the first non-zero digit after the decimal point. This determines if additional zeros are required, how many are reqired, and then appends those if needed.

In the end (after many iterations) the formatting function is quite simple (which is nice!) and hopefully will perform reasnably well. Note, I opted to prepare a second function that "passes thru" the parameters into the existing numeric function for simplicity. Also note user defined scalar functions are not known for their performance - but they are convenient.

The following is a simplified function to round to a significant number, you may use this or the original, but note I haven't done very extensive testing with either.

CREATE FUNCTION [dbo].[LimitSigFigsV1](@value FLOAT, @sigFigs INT) RETURNS FLOAT AS
BEGIN
  DECLARE @result FLOAT
  IF (@sigFigs &lt; 1)
    SET @result = NULL
  ELSE
    SET @result = CASE WHEN @value = 0 THEN 0 
                       ELSE ROUND(@value, @sigFigs - 1 - FLOOR(LOG10(ABS(@value)))) 
                  END
  RETURN @result
END
  • takes a floating point number value and an integer sigFigs as inputs.
  • returns a floating point number rounded to the specified number of significant figures.
  • If the sigFigs input is less than 1, return NULL.
  • If the value input is 0, return 0.
  • Otherwise, round the value to the specified number of significant figures using the ROUND function
  • then returns the rounded value.

Then the final formating is conducted through this function:

CREATE FUNCTION FormatSigFigsV2(@Number FLOAT, @Figures INT) RETURNS VARCHAR(200) AS 
BEGIN 
  DECLARE @Result VARCHAR(200); 
  SET @Result = FORMAT(dbo.LimitSigFigsv1(@Number, @Figures),&#39;0.################&#39;); 

  /* Count the number of significant digits */
  DECLARE @SigFigs INT = 0;
  DECLARE @i INT = 1;
  WHILE @i &lt;= LEN(@Result) AND @SigFigs &lt; @Figures
  BEGIN
    IF SUBSTRING(@Result, @i, 1) BETWEEN &#39;1&#39; AND &#39;9&#39;
      SET @SigFigs = @SigFigs + 1;
    SET @i = @i + 1;
  END

  /* Add trailing zeros if necessary */
  IF CHARINDEX(&#39;.&#39;, @Result) &gt; 0 AND @SigFigs &lt; @Figures
    SET @Result = @Result + REPLICATE(&#39;0&#39;, @Figures - @SigFigs);
  ELSE IF CHARINDEX(&#39;.&#39;, @Result) = 0 AND @SigFigs &lt; @Figures
    SET @Result = @Result + &#39;.&#39; + REPLICATE(&#39;0&#39;, @Figures - @SigFigs);

  RETURN @Result; 
END
  • first calls another function called dbo.LimitSigFigsv1 to limit the number of significant figures in the input number to the specified number of figures
  • then counts the number of significant digits in the result by iterating over each character in the string and checking if it is a non-zero digit
  • If the result contains a decimal point and the number of significant digits is less than the specified number of figures, adds trailing zeros after the decimal point
  • Or, if the result does not contain a decimal point and the number of significant digits is less than the specified number of figures, adds a decimal point followed by trailing zeros

Note limited testing has been undertaken, using the following table within the range of 1 to 5 for the significant number. (ps: I changed the inital test set from (say) 80125.01255 to 87125.112550 to reduce confusion with the number and placement of zeros).

The remainder of this answer replicates the details of a fiddle site, hopefully this will allow you to follow the tests conducted and how the functions are used.

CREATE TABLE measurements (
  value decimal(24,8)
);

INSERT INTO measurements (value)
VALUES
  (87125.112550),  (8712.112550),  (871.112550),  (87.112550),  (8.112550),
  (0.111362),  (0.011362),  (0.001136),  (0.000113),  (0.000011),  (0.000001)
  , (1.2), (1.4), (1.8564), (1.98765)
  ,(100000),(9000),(100),(90),(10),(9), (0);
22 rows affected
CREATE FUNCTION [dbo].[LimitSigFigsV1](@value FLOAT, @sigFigs INT) RETURNS FLOAT AS
BEGIN
  DECLARE @result FLOAT
  IF (@sigFigs &lt; 1)
    SET @result = NULL
  ELSE
    SET @result = CASE WHEN @value = 0 THEN 0 
                       ELSE ROUND(@value, @sigFigs - 1 - FLOOR(LOG10(ABS(@value)))) 
                  END
  RETURN @result
END
/* while loop logic */
CREATE FUNCTION FormatSigFigsV2(@Number FLOAT, @Figures INT) RETURNS VARCHAR(200) AS 
BEGIN 
  DECLARE @Result VARCHAR(200); 
  SET @Result = FORMAT(dbo.LimitSigFigsv1(@Number, @Figures),&#39;0.################&#39;); 

  /* Count the number of significant digits */
  DECLARE @SigFigs INT = 0;
  DECLARE @i INT = 1;
  WHILE @i &lt;= LEN(@Result) AND @SigFigs &lt; @Figures
  BEGIN
    IF SUBSTRING(@Result, @i, 1) BETWEEN &#39;1&#39; AND &#39;9&#39;
      SET @SigFigs = @SigFigs + 1;
    SET @i = @i + 1;
  END

  /* Add trailing zeros if necessary */
  IF CHARINDEX(&#39;.&#39;, @Result) &gt; 0 AND @SigFigs &lt; @Figures
    SET @Result = @Result + REPLICATE(&#39;0&#39;, @Figures - @SigFigs);
  ELSE IF CHARINDEX(&#39;.&#39;, @Result) = 0 AND @SigFigs &lt; @Figures
    SET @Result = @Result + &#39;.&#39; + REPLICATE(&#39;0&#39;, @Figures - @SigFigs);

  RETURN @Result; 
END
SELECT 
    value AS Measured,
    dbo.FormatSigFigsV2(value, 1) AS Sig_1a,
    dbo.FormatSigFigsV2(value, 2) AS Sig_2a,
    dbo.FormatSigFigsV2(value, 3) AS Sig_3a,
    dbo.FormatSigFigsV2(value, 4) AS Sig_4a,
    dbo.FormatSigFigsV2(value, 5) AS Sig_5a
FROM measurements;

Measured Sig_1a Sig_2a Sig_3a Sig_4a Sig_5a
87125.11255000 90000 87000 87100 87130 87125
8712.11255000 9000 8700 8710 8712 8712.1
871.11255000 900 870 871 871.1 871.11
87.11255000 90 87 87.1 87.11 87.113
8.11255000 8 8.1 8.11 8.113 8.1126
0.11136200 0.1 0.11 0.111 0.1114 0.11136
0.01136200 0.01 0.011 0.0114 0.01136 0.011362
0.00113600 0.001 0.0011 0.00114 0.001136 0.0011360
0.00011300 0.0001 0.00011 0.000113 0.0001130 0.00011300
0.00001100 0.00001 0.000011 0.0000110 0.00001100 0.000011000
0.00000100 0.000001 0.0000010 0.00000100 0.000001000 0.0000010000
1.20000000 1 1.2 1.20 1.200 1.2000
1.40000000 1 1.4 1.40 1.400 1.4000
1.85640000 2 1.9 1.86 1.856 1.8564
1.98765000 2 2.0 1.99 1.988 1.9876
100000.00000000 100000 100000.0 100000.00 100000.000 100000.0000
9000.00000000 9000 9000.0 9000.00 9000.000 9000.0000
100.00000000 100 100.0 100.00 100.000 100.0000
90.00000000 90 90.0 90.00 90.000 90.0000
10.00000000 10 10.0 10.00 10.000 10.0000
9.00000000 9 9.0 9.00 9.000 9.0000
0.00000000 0.0 0.00 0.000 0.0000 0.00000
/*
+---------------+-----------+------------+------------+-------------+--------------+
|   Measured    | 1 Sig Fig | 2 Sig Figs | 3 Sig Figs | 4 Sig Figs  |  5 Sig Figs  |
+---------------+-----------+------------+------------+-------------+--------------+
| 87125.01255   | 90000     | 87000      | 87100      | 87130       | 87125        |
| 8712.01255    | 9000      | 8700       | 8710       | 8712        | 8712.0       |
| 871.012555    | 900       | 870        | 871        | 871.0       | 871.01       |
| 87.01255      | 90        | 87         | 87.0       | 87.01       | 87.013       |
| 8.01255       | 8         | 8.0        | 8.01       | 8.013       | 8.0126       |
| 0.100362      | 0.1       | 0.10       | 0.100      | 0.1004      | 0.10036      |
| 0.010362      | 0.01      | 0.010      | 0.0103     | 0.01036     | 0.010362     |
| 0.001036      | 0.001     | 0.0010     | 0.00104    | 0.001036    | 0.0010360    |
| 0.000103      | 0.0001    | 0.00010    | 0.000103   | 0.0001030   | 0.00010300   |
| 0.000010      | 0.00001   | 0.000010   | 0.0000100  | 0.00001000  | 0.000010000  |
| 0.000001      | 0.000001  | 0.0000010  | 0.00000100 | 0.000001000 | 0.0000010000 |
+---------------+-----------+------------+------------+-------------+--------------+
*/

fiddle

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  • 本文由 发表于 2023年5月21日 22:21:09
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