在相同表格中求前一行数值之和

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英文:

Sum previous row values in same table

问题

| ItemID   |    Qty   |  库存余量(更新为此列的结果)
| -------- | -------- |---------------
| 1000     |     1    |      1
| 1000     |     5    |      6(前一行的数量之和加上当前行的数量)
| 1000     |     2    |      8(前一行的数量之和加上当前行的数量)
| 1000     |     1    |      9(前一行的数量之和加上当前行的数量)
英文:

I try to sum value in pervious rows, I want to sum the pervious quantity "Stock on hand" and put the result in each row, example

ItemID Qty Stockon Hand ( the result updated in this column)
1000 1 1
1000 5 6 ( sum qty previous in pervious row plus the qty in the current row)
1000 2 8 ( sum qty previous in pervious row plus the qty in the current row)
1000 1 9 ( sum qty previous in pervious row plus the qty in the current row)

How can I update the column "Stock on hand" by summing the qty in the current row and previous rows?

select ItemID, Qty
    , sum(qty) over (order by itemid rows between 1 preceding and 1 preceding) as previous_Qty
from #Stock
order by itemid 

答案1

得分: 1

这是一个可行的示例。请注意,我在列名中添加了一个适当的序列ID,但您也可以使用日期列。

您还可以注意到我添加了 partition by ItemID

Declare @YourTable Table ([ID] int,[ItemID] int,[Qty] int)
Insert Into @YourTable Values 
 (1,1000,1)
,(2,1000,5)
,(3,1000,2)
,(4,1000,1)
 
Select * 
      ,OnHand = sum(Qty) over (partition by ItemID order by ID ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW)
from @YourTable

结果

ID	ItemID	Qty	OnHand
1	1000	1	1
2	1000	5	6
3	1000	2	8
4	1000	1	9
英文:

Here is a working example. Note, I took the liberty of adding an column for a proper sequence... ID, but you could use a date column as well

You may also notice that I added partition by ItemID

Declare @YourTable Table ([ID] int,[ItemID] int,[Qty] int)
Insert Into @YourTable Values 
 (1,1000,1)
,(2,1000,5)
,(3,1000,2)
,(4,1000,1)
 
Select * 
      ,OnHand = sum(Qty) over (partition by ItemID order by ID ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW)
from @YourTable

Results

ID	ItemID	Qty	OnHand
1	1000	1	1
2	1000	5	6
3	1000	2	8
4	1000	1	9

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  • 本文由 发表于 2023年1月6日 10:33:26
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