英文:
Given a binary array nums, return the maximum number of consecutive 1's in the array
问题
在Code blocks中可以工作，但在LeetCode上不行。有任何想法为什么。
英文:
I do not know why my code gives me this error -> solution.c: In function ‘findMaxConsecutiveOnes’
Line 32: Char 1: error: control reaches end of non-void function [-Werror=return-type] [solution.c]
}
^
cc1: some warnings being treated as errors.
int findMaxConsecutiveOnes(int* nums, int numsSize){int counter = 0;int max = 0;for(int i =0; i < numsSize; i++){if(nums[i] == 1){counter++;}else{counter = 0;}if(counter > max){max = counter;}}printf("%d", max);}
This works in Code blocks but not leet code. Any idea why.
答案1
得分: 2
你的函数承诺返回一个 int，但从未返回任何类型的值。这就是为什么你收到这个警告/错误的原因。你可能是想在函数末尾返回 counter。
英文:
Your function promises to return an int but never returns a value of any type. This is why you are getting this warning/error. Presumably you meant to return counter at the end of your function.
答案2
得分: 0
你的函数返回类型是 int 而不是 void，所以你必须返回一些整数值，这就是为什么你得到错误的原因。你的代码应该是：
int findMaxConsecutiveOnes(int* nums, int numsSize) {int counter = 0;int max = 0;for (int i = 0; i < numsSize; i++) {if (nums[i] == 1) {counter++;} else {counter = 0;}if (counter > max) {max = counter;}}printf("%d", max); // 你可以选择显示，如果你想显示// 将返回类型更改为 void，并且不要添加下一个返回语句，如果你想要这样做return max;}我认为这应该解决你的错误。<details><summary>英文:</summary>Your function return type is **int** not **void** so you have to return some int value that's why you are getting the error. Your code should be:int findMaxConsecutiveOnes(int* nums, int numsSize){int counter = 0;int max = 0;for(int i =0; i < numsSize; i++){if(nums[i] == 1){counter++;}else{counter = 0;}if(counter > max){max = counter;}}printf("%d", max); // it's upto you to show, if you want to show//change return type to void and don't add next return statementreturn max;}I think this should resolve your error</details>
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