问题

以下是您提供的代码的翻译部分：

我目前正在为大学的作业而工作。

任务是在一个单独的函数中反转一个字符串。函数名如下所示：

> `void string_rev(unsigned char *str);`

我的解决方案如下：

```c
void string_rev(unsigned char *str){

	int length = 0;
	int counter = 0;
	unsigned char *endptr = str;   

	for (int i = 0; str[i] != '
我目前正在为大学的作业而工作。

任务是在一个单独的函数中反转一个字符串。函数名如下所示：

> `void string_rev(unsigned char *str);`

我的解决方案如下：

```c
void string_rev(unsigned char *str){

	int length = 0;
	int counter = 0;
	unsigned char *endptr = str;   

	for (int i = 0; str[i] != '\0'; i++)  //获取字符串的长度
		length++;

	for (int i = 0; i < length; i++)     //将endptr放到字符串的末尾
		endptr++;

	while (counter < length/2){      //交换从开头到末尾的值，直到字符串的一半
		char temp = *str;
		*str = *endptr;
		*endptr = temp;
		str++;
		endptr--;
		counter++;
	}

	for (int i = 0; i<length; i++){
		printf("%c", *str);
		str++;
	}

}

int main (void){

	char *array = "Hello";
	unsigned char *ptr = (unsigned char*)array;

	string_rev(ptr);

	return 0;
}
'; i++)  //获取字符串的长度
		length++;

	for (int i = 0; i < length; i++)     //将endptr放到字符串的末尾
		endptr++;

	while (counter < length/2){      //交换从开头到末尾的值，直到字符串的一半
		char temp = *str;
		*str = *endptr;
		*endptr = temp;
		str++;
		endptr--;
		counter++;
	}

	for (int i = 0; i<length; i++){
		printf("%c", *str);
		str++;
	}

}

int main (void){

	char *array = "Hello";
	unsigned char *ptr = (unsigned char*)array;

	string_rev(ptr);

	return 0;
}

我收到的错误是“总线错误10！但我找不到错误。

这可能与unsigned char*有关，但我无法让它工作。有人可以帮忙吗？

FYI -> 我们必须使用unsigned char*！当然要使用指针！

谢谢

<details>
<summary>英文:</summary>

I am currently working on an assignment for Uni.

The task is to reverse a string in a separate function. The function-name is given like that:

&gt; `void string_rev(unsigned char *str);`

My Solution looks like this:

void string_rev(unsigned char *str){

int length = 0;
int counter = 0;
unsigned char *endptr = str;   

for (int i = 0; str[i] != '
int length = 0;
int counter = 0;
unsigned char *endptr = str;   
for (int i = 0; str[i] != '\0'; i++)  //getting length of string
length++;
for (int i = 0; i < length; i++)     //putting endptr to end of string
endptr++;
while (counter < length/2){      //switch values from start to end until half of string
char temp = *str;
*str = *endptr;
*endptr = temp;
str++;
endptr--;
counter++;
}
for (int i = 0; i<length; i++){
printf("%c", *str);
str++;
}
'; i++)  //getting length of string
	length++;

for (int i = 0; i < length; i++)     //putting endptr to end of string
	endptr++;

while (counter < length/2){      //switch values from start to end until half of string
	char temp = *str;
	*str = *endptr;
	*endptr = temp;
	str++;
	endptr--;
	counter++;
}


for (int i = 0; i<length; i++){
	printf("%c", *str);
	str++;
}

}

int main (void){

char *array = "Hello";
unsigned char *ptr = (unsigned char*)array;


string_rev(ptr);


return 0;

}

The Error I get is Bus Error 10! But I can't find the mistake.

It may has to do with the unsigned char* but I don't get it to work. Can someone please help?

FYI -> We have to use unsigned char*! And of course pointers!

Thank you :)




</details>


# 答案1
**得分**: 5

请用以下方式替换：

```cpp
char array[] = "Hello";

char *array = "Hello";   // Not an array.

char array[] = "Hello";