使用指针（必须使用unsigned *char）在C中反转一个字符串。

huangapple
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英文:

reverse a string using pointers (have to use unsigned *char) in C

问题

以下是您提供的代码的翻译部分：

  1. 我目前正在为大学的作业而工作。
  3. 任务是在一个单独的函数中反转一个字符串。函数名如下所示：
  5. > `void string_rev(unsigned char *str);`
  7. 我的解决方案如下：
  9. ```c
  10. void string_rev(unsigned char *str){
  12. 	int length = 0;
  13. 	int counter = 0;
  14. 	unsigned char *endptr = str;   
  16. 	for (int i = 0; str[i] != '
    我目前正在为大学的作业而工作。
  18. 任务是在一个单独的函数中反转一个字符串。函数名如下所示：
  20. > `void string_rev(unsigned char *str);`
  22. 我的解决方案如下：
  24. ```c
  25. void string_rev(unsigned char *str){
  27. 	int length = 0;
  28. 	int counter = 0;
  29. 	unsigned char *endptr = str;   
  31. 	for (int i = 0; str[i] != '\0'; i++)  //获取字符串的长度
  32. 		length++;
  34. 	for (int i = 0; i < length; i++)     //将endptr放到字符串的末尾
  35. 		endptr++;
  37. 	while (counter < length/2){      //交换从开头到末尾的值，直到字符串的一半
  38. 		char temp = *str;
  39. 		*str = *endptr;
  40. 		*endptr = temp;
  41. 		str++;
  42. 		endptr--;
  43. 		counter++;
  44. 	}
  46. 	for (int i = 0; i<length; i++){
  47. 		printf("%c", *str);
  48. 		str++;
  49. 	}
  51. }
  53. int main (void){
  55. 	char *array = "Hello";
  56. 	unsigned char *ptr = (unsigned char*)array;
  58. 	string_rev(ptr);
  60. 	return 0;
  61. }
  62. '; i++)  //获取字符串的长度
  63. 		length++;
  65. 	for (int i = 0; i < length; i++)     //将endptr放到字符串的末尾
  66. 		endptr++;
  68. 	while (counter < length/2){      //交换从开头到末尾的值，直到字符串的一半
  69. 		char temp = *str;
  70. 		*str = *endptr;
  71. 		*endptr = temp;
  72. 		str++;
  73. 		endptr--;
  74. 		counter++;
  75. 	}
  77. 	for (int i = 0; i<length; i++){
  78. 		printf("%c", *str);
  79. 		str++;
  80. 	}
  82. }
  84. int main (void){
  86. 	char *array = "Hello";
  87. 	unsigned char *ptr = (unsigned char*)array;
  89. 	string_rev(ptr);
  91. 	return 0;
  92. }

我收到的错误是“总线错误10！但我找不到错误。

这可能与unsigned char*有关，但我无法让它工作。有人可以帮忙吗？

FYI -> 我们必须使用unsigned char*！当然要使用指针！

谢谢 使用指针（必须使用unsigned *char）在C中反转一个字符串。

  2. <details>
  3. <summary>英文:</summary>
  5. I am currently working on an assignment for Uni.
  7. The task is to reverse a string in a separate function. The function-name is given like that:
  9. &gt; `void string_rev(unsigned char *str);`
  11. My Solution looks like this:

void string_rev(unsigned char *str){

  1. int length = 0;
  2. int counter = 0;
  3. unsigned char *endptr = str;   
  5. for (int i = 0; str[i] != &#39;
    int length = 0;
  6. int counter = 0;
  7. unsigned char *endptr = str;   
  8. for (int i = 0; str[i] != &#39;\0&#39;; i++)  //getting length of string
  9. length++;
  10. for (int i = 0; i &lt; length; i++)     //putting endptr to end of string
  11. endptr++;
  12. while (counter &lt; length/2){      //switch values from start to end until half of string
  13. char temp = *str;
  14. *str = *endptr;
  15. *endptr = temp;
  16. str++;
  17. endptr--;
  18. counter++;
  19. }
  20. for (int i = 0; i&lt;length; i++){
  21. printf(&quot;%c&quot;, *str);
  22. str++;
  23. }
  24. &#39;; i++)  //getting length of string
  25. 	length++;
  27. for (int i = 0; i &lt; length; i++)     //putting endptr to end of string
  28. 	endptr++;
  30. while (counter &lt; length/2){      //switch values from start to end until half of string
  31. 	char temp = *str;
  32. 	*str = *endptr;
  33. 	*endptr = temp;
  34. 	str++;
  35. 	endptr--;
  36. 	counter++;
  37. }
  40. for (int i = 0; i&lt;length; i++){
  41. 	printf(&quot;%c&quot;, *str);
  42. 	str++;
  43. }

}

int main (void){

  1. char *array = &quot;Hello&quot;;
  2. unsigned char *ptr = (unsigned char*)array;
  5. string_rev(ptr);
  8. return 0;

}

  2. The Error I get is Bus Error 10! But I can&#39;t find the mistake.
  4. It may has to do with the unsigned char* but I don&#39;t get it to work. Can someone please help?
  6. FYI -&gt; We have to use unsigned char*! And of course pointers!
  8. Thank you :)
  13. </details>
  16. # 答案1
  17. **得分**: 5
  19. 请用以下方式替换：
  21. ```cpp
  22. char array[] = "Hello";
英文:

You are trying to modify a string constant. Replace

  1. char *array = &quot;Hello&quot;;   // Not an array.

with

  1. char array[] = &quot;Hello&quot;;

huangapple
  • 本文由 发表于 2020年1月4日 00:50:37
  • 转载请务必保留本文链接：https://go.coder-hub.com/59582311.html
  • c
  • pointers
  • string
  • unsigned-char
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