英文:
The method next() is undefined for the type String
问题
我是新手程序员，我正在尝试从一个方法中调用一个扫描器，并在编译之前收到错误，我在这个论坛或其他地方找不到我能理解的答案。
public class BL {
static double outcome = 0;
private static String input;
private static void main() {
Scanner input = new Scanner(System.in);
}
public static void sort() {
**input = input.next();** // 错误出现在 .next() 下面
}
}
非常感谢！
英文:
I'm new to programming and I'm trying to call a scanner from a method- and receiving the error before compiling, I could not find an answer to this in this forum or outplace, that I could understand
public class BL {
static double outcome = 0;
private static String input;
private static void main() {
Scanner input = new Scanner(System.in);
}
public static void sort() {
**input= input.next();** // the error is under .next()
}
Thanks upfront!
答案1
得分: 1
我猜你想要
public static void sort() {
Scanner in = new Scanner(System.in);
input = in.next(); //或者使用in.nextLine()来获取整行输入
}
Scanner 是用于从键盘读取输入的类。它是拥有 next() 方法的类，该方法获取用户输入（直到找到空格或新行）并将其转换为 String。
英文:
I guess you want
public static void sort() {
Scanner in = new Scanner(System.in);
input = in.next(); //or in.nextLine() for the whole line
}
The Scanner is the class that reads input from the keyboard. It is the class who has the method next(), that retrieves the input of the user (until it finds a space or a new line) converted in a String.
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