英文:
How to convert Struct to Series in Polars?
问题
I have Dataframe with stuct inside after used pl.cumfold(). How struct convert to normal series based column?
我有一个包含结构的DataFrame，在使用了`pl.cumfold()`后。如何将结构转换为基于列的普通Series？
Is it possible with polars expression or some kind of util method? I find the only way is convert to Python and then back to DF.
是否可以使用Polars表达式或某种实用方法来实现？我发现唯一的方法是将其转换为Python，然后再转换回DF。
(Note: The code part you provided is not translated as per your request.)
英文:
I have Dataframe with stuct inside after used pl.cumfold().
How struct convert to normal series based column?
┌───────────────────────────────────┐
│ price │
│ --- │
│ struct[2000] │
╞═══════════════════════════════════╡
│ {null,null,null,null,30302.67187… │
└───────────────────────────────────┘
Is it possible with polars expression or some kind of util method?
I find the only way is convert to Python and then back to DF.
df=pl.DataFrame(pl.Series('price', df[0, 0].values()))
答案1
得分: 1
这是transpose一旦结构被unnest后的操作。这可能会相对较慢，但我认为没有其他方法：
df = pl.DataFrame({"price": {'test0': None, 'test1': 1, 'test2': 2}})
df.unnest('price').transpose(column_names=['price'])
形状: (3, 1)
┌───────┐
│ price │
│ --- │
│ f64 │
╞═══════╡
│ null │
│ 1.0 │
│ 2.0 │
└───────┘
英文:
There is transpose once the struct is unnested. This will be relatively slow but I don't think there is any other way:
df = pl.DataFrame( {"price": {'test0' : None, 'test1' : 1, 'test2' : 2}})
df.unnest('price').transpose(column_names=['price'])
shape: (3, 1)
┌───────┐
│ price │
│ --- │
│ f64 │
╞═══════╡
│ null │
│ 1.0 │
│ 2.0 │
└───────┘
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