英文:
json query for python sqlite3 in Conda env and python.org release env
问题
在m_mail_info表中，列froms，tos，ccs，bccs是TEXT类型，格式如'{"a":"123"}'或'[{"a":"123"}]'。
当我使用conda环境运行脚本时：
> python=3.8.10 32位，Windows
它会打印：
[(21,), (22,), (23,), (29,), (36,), (38,), (39,), (41,), (43,), (44,), (53,), (55,), (56,), (57,), (58,), (59,), (60,), (61,), (62,), (63,), (66,), (67,), (, (9072,), (73,), (78,), (81,), (115,), (120,), (129,), (158,), (162,), (163,), (164,), (167,), (168,), (171,), (173,), (186,), (190,), (768,), (779,), (818,), ( (108901,), (906,), (948,), (1034,), (1035,), (1036,), (1037,), (1041,), (1043,), (1050,), (1052,), (1053,), (1054,), (1055,), (1056,), (1060,), (1062,), (1071,), (11, (1076,), (1080,), (1082,), (1084,), (1086,), (1087,), (1089,), (1090,), (1093,), (1095,), (1096,), (1097,), (1098,), (1100,), (1102,), (1108,), (1109,), (1114,), (1115,), (1117,), (1119,), (1121,), (1122,), (1126,), (1129,), (1131,), (1133,), (1139,), (1147,), (1149,), (1152,), (1153,), (1154,), (1158,), (1160,), (1169,)]
无论如何，它都可以打印结果。
而如果我使用由python.org安装的python官方发行版3.8.10 32位运行脚本，
它会打印错误：
Traceback (most recent call last):
File "test.py", line 68, in <module>
test()
File "test.py", line 43, in test
t.execute('''SELECT m_mail_info.id
sqlite3.OperationalError: no such table: json_tree
我尝试在SQLiteStudio上使用原始SQL，它返回与Conda环境中相同的结果
[![进入图片描述][1]][1]
[1]: https://i.stack.imgur.com/j8EIi.png
我不知道如何找到conda环境和python官方发行版环境之间的区别。
如果你想复现这个问题，你可以创建一个只有一列的表，在查询语句中你必须使用```json_each```或```json_tree```。
英文:
import os
import sqlite3
g_rdb_path = 'mails.db'
def test():
c = sqlite3.connect(g_rdb_path)
t = c.cursor()
t.execute('''SELECT m_mail_info.id
FROM m_mail_info, json_each(m_mail_info.froms)
WHERE json_each.value LIKE '%{0}%'
UNION
SELECT m_mail_info.id
FROM m_mail_info, json_tree(m_mail_info.tos)
WHERE json_tree.value LIKE '%{0}%' and json_tree.type ="text"
UNION
SELECT m_mail_info.id
FROM m_mail_info, json_tree(m_mail_info.ccs)
WHERE json_tree.value LIKE '%{0}%' and json_tree.type ="text"
UNION
SELECT m_mail_info.id
FROM m_mail_info, json_tree(m_mail_info.bccs)
WHERE json_tree.value LIKE '%{0}%' and json_tree.type ="text"
union
SELECT m_mail_info.id
FROM m_mail_info
WHERE m_mail_info.subject like '%{0}%' or m_mail_info.plainContent like '%{0}%'
'''.format('name'))
print([i for i in t.fetchall()])
t.close()
c.close()
if __name__ == '__main__':
test()
in the m_mail_info table, column froms, tos, ccs, bccs are of TEXT type, in the format like '{"a":"123"}' or '[{"a":"123"}]'.
when I run the script with conda env:
> python=3.8.10 32bit, windows
it prints:
[(21,), (22,), (23,), (29,), (36,), (38,), (39,), (41,), (43,), (44,), (53,), (55,), (56,), (57,), (58,), (59,), (60,), (61,), (62,), (63,), (66,), (67,), (, (9072,), (73,), (78,), (81,), (115,), (120,), (129,), (158,), (162,), (163,), (164,), (167,), (168,), (171,), (173,), (186,), (190,), (768,), (779,), (818,), ( (108901,), (906,), (948,), (1034,), (1035,), (1036,), (1037,), (1041,), (1043,), (1050,), (1052,), (1053,), (1054,), (1055,), (1056,), (1060,), (1062,), (1071,), (11, (1076,), (1080,), (1082,), (1084,), (1086,), (1087,), (1089,), (1090,), (1093,), (1095,), (1096,), (1097,), (1098,), (1100,), (1102,), (1108,), (1109,), (1114,), (1115,), (1117,), (1119,), (1121,), (1122,), (1126,), (1129,), (1131,), (1133,), (1139,), (1147,), (1149,), (1152,), (1153,), (1154,), (1158,), (1160,), (1169,)]
whatever it is, it can print the result.
while if I run the script with the python env installed by python.org 3.8.10 32bit release,
it prints Error:
Traceback (most recent call last):
File "test.py", line 68, in <module>
test()
File "test.py", line 43, in test
t.execute('''SELECT m_mail_info.id
sqlite3.OperationalError: no such table: json_tree
And I've tried with raw sql on SQLiteStudio, it returns the same result as in Conda env
I don't know how to find the difference between conda env and python official release env.
If you want to reproduce the issue, you may create a table with only one column, and in the query statement you must make use of json_each or json_tree .
答案1
得分: 1
以下是翻译好的部分：
"json_each" 和 "json_tree" 函数仅在 SQLite 的默认版本中从 3.38 版本（2022-02-22）开始包含。
Python 3.8 版本较旧，因此使用的是不包含它们的旧版本。
您可以通过以下方式确认：
import sqlite3
print(sqlite3.sqlite_version)
这篇Stack Overflow 帖子建议直接替换 Python 树中的 sqlite3.dll 模块...
英文:
The json_each and json_tree functions are only included by default in SQLite from version 3.38 (2022-02-22).
Python 3.8 is much older, and because of that uses an older version that does not include them.
You can confirm it with:
import sqlite3
print(sqlite3.sqlite_version)
This other SO post suggests that
it is possible to replace the sqlite3.dll module directly in the Python tree...
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