问题

Here's the translation of the code portion:

A = [(3, 4, 5, "s2", "s2"), (2, 4, 5, "s1", "s2"), (3, 4, 6, "s2", "s2"), (1, 4, 6, "s2", "s3"), (1, 3, 6, "s3", "s3")]

# Filter tuples where fourth and fifth elements are the same
same_forth_and_fifth = filter(x -> x[4] == x[5], A)

# Group them based on the fourth element
grouped_same = Dict{String, Vector{Tuple{Int, Int, Int, String, String}}}()
for tup in same_forth_and_fifth
    key = tup[4]
    if haskey(grouped_same, key)
        push!(grouped_same[key], tup)
    else
        grouped_same[key] = [tup]
    end
end

# Filter tuples where fourth and fifth elements are different
different_forth_and_fifth = filter(x -> x[4] != x[5], A)

# Group them based on the fourth element
grouped_different = Dict{String, Vector{Tuple{Int, Int, Int, String, String}}}()
for tup in different_forth_and_fifth
    key = tup[4]
    if haskey(grouped_different, key)
        push!(grouped_different[key], tup)
    else
        grouped_different[key] = [tup]
    end
end

# Print the results
println("This is for when fourth and fifth are the same:")
for (key, value) in grouped_same
    println("$key │ $value")
end

println("\nThis is for when fourth and fifth are different:")
for (key, value) in grouped_different
    println("$key │ $value")
end

Please note that this code assumes you have a list of tuples A, and it filters and groups them based on whether the fourth and fifth elements are the same or different, and then prints the results.

"s1" │ []
"s2" │ [(3, 4, 5, "s2", "s2"), (3, 4, 6, "s2", "s2")]
"s3" │ [(1, 3, 6, "s3", "s3")]

答案1

得分: 2

以下是翻译好的内容：

可能的一种方式是：
```julia
foldl((r,e)->(e[4]==e[5] && push!(r[e[4]],e); r),A ;
  init=Dict(k=>eltype(A)[] for k in 
    Base.Fix2(nth,4).(A) |> unique |> sort))

给出以下输出：

julia> A = [(3, 4, 5, "s2", "s2") , (2, 4, 5, "s1", "s2"), (3, 4, 6, "s2", "s2"),(1, 4, 6, "s2", "s3"),(1, 3, 6, "s3", "s3")];

julia> foldl((r,e)->(e[4]==e[5] && push!(r[e[4]],e); r),A ;init=Dict(k=>eltype(A)[] for k in Base.Fix2(nth,4).(A) |> unique |> sort))
Dict{String, Vector{Tuple{Int64, Int64, Int64, String, String}}} with 3 entries:
  "s1" => []
  "s2" => [(3, 4, 5, "s2", "s2"), (3, 4, 6, "s2", "s2")]
  "s3" => [(1, 3, 6, "s3", "s3")]

使用了一些 Julia 的基本特性：

• 带有 init 参数的 foldl。
• 使用 Base.Fix2 创建了一个部分计算的 nth。
• 使用 && 短路操作符来实现 if 逻辑。
• 使用 |> 管道操作符。
• 使用生成器（类似于推导式）初始化了字典。

foldl((r,e)->(e[4]==e[5] && push!(r[e[4]],e); r),A ;
  init=Dict(k=>eltype(A)[] for k in 
    Base.Fix2(nth,4).(A) |> unique |> sort))

julia> A = [(3, 4, 5, "s2", "s2") , (2, 4, 5, "s1", "s2"), (3, 4, 6, "s2", "s2"),(1, 4, 6, "s2", "s3"),(1, 3, 6, "s3", "s3")];

julia> foldl((r,e)->(e[4]==e[5] && push!(r[e[4]],e); r),A ;init=Dict(k=>eltype(A)[] for k in Base.Fix2(nth,4).(A) |> unique |> sort))
Dict{String, Vector{Tuple{Int64, Int64, Int64, String, String}}} with 3 entries:
  "s1" => []
  "s2" => [(3, 4, 5, "s2", "s2"), (3, 4, 6, "s2", "s2")]
  "s3" => [(1, 3, 6, "s3", "s3")]