英文:
Service not found a repository bean in my Springboot project
问题
I see that you have provided a detailed description of your issue related to a Spring Boot project. It seems like you're facing a problem with the bean configuration. To resolve this, you should:
- Ensure that your
UserRepository
andUserService
are in the correct packages. - Make sure that the package containing your
ServerApplication
class is at or above the package containing yourUserRepository
andUserService
so that Spring can scan and find these components. - Check if your
ServerApplication
class is in the correct package or update the@ComponentScan
annotation accordingly. - Verify that your application's main class (the one annotated with
@SpringBootApplication
) is in the root package or configure the@SpringBootApplication
annotation'sscanBasePackages
attribute to include your components' packages.
If you've already tried these steps and are still encountering issues, please provide more specific error messages or logs so that I can assist you further.
英文:
First of all, I want to give many thanks to everyone who read my question and want to help me solve it so, I have a problem which about not found bean in my project. I have a repository named "UserRepository" and in my service is "UserService" has @Autowired that repository, its not found my repository although I added repository annotation. "UserService" not found the repository bean
This is my problem:
> ***************************
> APPLICATION FAILED TO START
> ***************************
>
> Description:
>
> Parameter 0 of constructor in com.baothien.server.User.UserService required a bean of type 'com.baothien.server.User.UserRepository' that could not be found.
>
>
> Action:
>
> Consider defining a bean of type 'com.baothien.server.User.UserRepository' in your configuration.
>
>
> Process finished with exit code 0
My Project Structure:
My project structure
UserRepository.java
package com.baothien.server.User;
import org.springframework.data.jpa.repository.JpaRepository;
import org.springframework.data.jpa.repository.Query;
import org.springframework.stereotype.Repository;
import java.util.List;
@Repository
public interface UserRepository extends JpaRepository<User, Long> {
@Query("SELECT * FROM Users")
List<User> getAllUsers();
}
UserService.java
package com.baothien.server.User;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.stereotype.Service;
import java.util.List;
@Service
public class UserService {
@Autowired
private final UserRepository userRepository;
public UserService(UserRepository userRepository) {
this.userRepository = userRepository;
}
public List<User> getAllUsers() {
return userRepository.getAllUsers();
}
}
UserController.java
package com.baothien.server.User;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.web.bind.annotation.GetMapping;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RestController;
import java.util.List;
@RestController
@RequestMapping("/api/v1")
public class UserController {
@Autowired
private final UserService userService;
public UserController(UserService userService) {
this.userService = userService;
}
@GetMapping("/test")
public String test() {
return "GET User API succesfully!";
}
@GetMapping("/get-users")
public List<User> getUsers() {
return userService.getAllUsers();
}
}
User.java
package com.baothien.server.User;
import jakarta.persistence.*;
import lombok.Data;
import lombok.NoArgsConstructor;
import org.springframework.data.annotation.Id;
@Entity
@Table
@Data
@NoArgsConstructor
public class User {
@Id
@SequenceGenerator(
name = "user_sequence",
sequenceName = "user_sequence",
allocationSize = 1
)
@GeneratedValue(
strategy = GenerationType.SEQUENCE,
generator = "user_sequence"
)
private Long id;
private String email;
private String fullName;
private String role;
private String password;
}
Main method
package com.baothien.server;
import com.baothien.server.User.UserController;
import com.baothien.server.User.UserRepository;
import org.springframework.boot.SpringApplication;
import org.springframework.boot.autoconfigure.SpringBootApplication;
import org.springframework.boot.autoconfigure.domain.EntityScan;
import org.springframework.boot.autoconfigure.jdbc.DataSourceAutoConfiguration;
import org.springframework.context.annotation.ComponentScan;
import org.springframework.data.jpa.repository.config.EnableJpaRepositories;
@SpringBootApplication
@EntityScan(basePackages = {"com.baothien.server.User.*"})
@EnableJpaRepositories(basePackages = {"com.baothien.server.User.*"})
public class ServerApplication {
public static void main(String[] args) {
SpringApplication.run(ServerApplication.class, args);
}
}
I tried my best but this problem was not solved, I really need a solution.
Thanks for reading my question, see you.
UPDATE: I use @ComponentScan:
@ComponentScan(basePackages = "com.baothien.server.User.*")
It run but when I test on Postman, it has White Label Error, not found page (http://localhost:8080/api/v1/test). As you see, my controller has /test path, I don't understand why it have this error.
I tried find the solution on many forum but cannot solve that problem
答案1
得分: 1
- 你不需要
@EntityScan
。 - 你不需要
@EnableJpaRepositories
。 - 在Spring Data存储库接口上的
@Repository
不起作用。 JpaRepository
或者更确切地说是CrudRepository
已经有一个findAll
方法来检索所有实体。放弃你的getAllUsers
方法。- 你正在使用错误的
@Id
,你正在使用Spring Data的@Id
,而你需要使用jakarta.persistence
的@Id
。
第4和第5点实际上是你的问题,因为你写的查询是错误的,应该是SELECT u FROM User u
。这是JPQL查询,而不是SQL查询。但是正如我所说,你不需要它,因为已经有一个findAll
方法。对于JPA实体来说,需要一个@Id
,所以这也会导致失败。
英文:
You are trying to hard.
- You don't need
@EntityScan
- You don't need
@EnableJpaRepositories
@Repository
on a Spring Data repository interface doesn't do anythingJpaRepository
or ratherCrudRepository
already has afindAll
to retrieve all entities. Ditch yourgetAllUsers
method.- You are using the wrong
@Id
you are using the Spring Data one whereas you need thejakarta.persistence
one.
Point 4 and 5 are actually your issues as the query you have written is wrong it should read SELECT u FROM User u
. It is a JPQL and not a SQL query. However as stated you don't need it as there is already a findAll
method. An @Id
for JPA entities is required, so that makes it fail as well.
答案2
得分: 0
Your basePackages is too narrow. Try
EntityScan(basePackages = {"com.baothien.server"})
英文:
Your basePackages is too narrow. Try
EntityScan(basePackages = {"com.baothien.server"})
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