英文:
What's the best way to validate an XML file against local XML file?
问题
我正在开发一些测试框架。我打算使用本地数据来验证极其复杂的XML响应。
我考虑将本地数据保存为CSV格式，并实现了一些验证，但我发现这些框架的局限性，即无法验证复杂的数据，例如：
<?xml version='1.0' encoding='UTF-8'?>
<!DOCTYPE ResourceObject PUBLIC "abc_corp.dtd" "abc_corp.dtd">
<ResourceObject displayName="abcd" identity="pqr" objectType="account" uuid="123456">
<Attributes>
<Map>
<entry key="memberOf"/>
<entry key="objectClass">
<value>
<List>
<String>top</String>
<String>person</String>
<String>organizationalPerson</String>
<String>user</String>
</List>
</value>
</entry>
<entry key="objectSid" value="S-1-5"/>
<entry key="objectType" value="user"/>
<value>
<List>
<Permission rights="allow:elasticmapreduce:Describe*" target="*"/>
<Permission rights="allow:elasticmapreduce:List*" target="*"/>
<Permission rights="allow:elasticmapreduce:ViewEventsFromAllClustersInConsole" target="*"/>
<Permission rights="allow:s3:GetObject" target="*"/>
<Permission rights="allow:s3:ListAllMyBuckets" target="*"/>
<Permission rights="allow:s3:ListBucket" target="*"/>
<Permission rights="allow:sdb:Select" target="*"/>
<Permission rights="allow:cloudwatch:GetMetricStatistics" target="*"/>
</List>
</value>
</entry>
</Map>
</Attributes>
</ResourceObject>
在上述XML对象中，以下的entry在CSV格式中很难表示：
<entry key="objectType" value="user"/>
<value>
<List>
<Permission rights="allow:elasticmapreduce:Describe*" target="*"/>
<Permission rights="allow:elasticmapreduce:List*" target="*"/>
<Permission rights="allow:elasticmapreduce:ViewEventsFromAllClustersInConsole" target="*"/>
<Permission rights="allow:s3:GetObject" target="*"/>
<Permission rights="allow:s3:ListAllMyBuckets" target="*"/>
<Permission rights="allow:s3:ListBucket" target="*"/>
<Permission rights="allow:sdb:Select" target="*"/>
<Permission rights="allow:cloudwatch:GetMetricStatistics" target="*"/>
</List>
</value>
</entry>
或者包含列表等的XML数据。
是否有任何可用的框架或库可以验证这种复杂的XML数据？
英文:
I'm developing some test framework. I suppose to validate the extremely complex XML responses with local data.
I thought to have local data in the CSV format and achieved some validation but I found the limitation of this frameworks that I can't validate complex data e.g.
<?xml version='1.0' encoding='UTF-8'?>
<!DOCTYPE ResourceObject PUBLIC "abc_corp.dtd" "abc_corp.dtd">
<ResourceObject displayName="abcd" identity="pqr" objectType="account" uuid="123456">
<Attributes>
<Map>
<entry key="memberOf"/>
<entry key="objectClass">
<value>
<List>
<String>top</String>
<String>person</String>
<String>organizationalPerson</String>
<String>user</String>
</List>
</value>
</entry>
<entry key="objectSid" value="S-1-5"/>
<entry key="objectType" value="user"/>
<value>
<List>
<Permission rights="allow:elasticmapreduce:Describe*" target="*"/>
<Permission rights="allow:elasticmapreduce:List*" target="*"/>
<Permission rights="allow:elasticmapreduce:ViewEventsFromAllClustersInConsole" target="*"/>
<Permission rights="allow:s3:GetObject" target="*"/>
<Permission rights="allow:s3:ListAllMyBuckets" target="*"/>
<Permission rights="allow:s3:ListBucket" target="*"/>
<Permission rights="allow:sdb:Select" target="*"/>
<Permission rights="allow:cloudwatch:GetMetricStatistics" target="*"/>
</List>
</value>
</entry>
</Map>
</Attributes>
</ResourceObject>
Out of above XML object below entry is something hard to represent in the CSV format
<entry key="objectType" value="user"/>
<value>
<List>
<Permission rights="allow:elasticmapreduce:Describe*" target="*"/>
<Permission rights="allow:elasticmapreduce:List*" target="*"/>
<Permission rights="allow:elasticmapreduce:ViewEventsFromAllClustersInConsole" target="*"/>
<Permission rights="allow:s3:GetObject" target="*"/>
<Permission rights="allow:s3:ListAllMyBuckets" target="*"/>
<Permission rights="allow:s3:ListBucket" target="*"/>
<Permission rights="allow:sdb:Select" target="*"/>
<Permission rights="allow:cloudwatch:GetMetricStatistics" target="*"/>
</List>
</value>
</entry>
Or XML data which hold list of maps etc.
Is there any framework, library available which could validate such a complex XML data?
答案1
得分: 1
以下是翻译好的内容：
-
参考以下链接：
-
创建一个Diff实例来比较两个XML文件：
Diff xmlDiff = new Diff(source, target);
- 获取两个XML文件之间的详细差异：
DetailedDiff detailXmlDiff = new DetailedDiff(xmlDiff);
希望这有所帮助。
英文:
Have a look at these for reference..
- https://javarevisited.blogspot.com/2017/04/how-to-compare-two-xml-files-in-java.htm
- https://stackoverflow.com/questions/141993/best-way-to-compare-2-xml-documents-in-java
//creating Diff instance to compare two XML files
Diff xmlDiff = new Diff(source, target);
//for getting detailed differences between two xml files
DetailedDiff detailXmlDiff = new DetailedDiff(xmlDiff);
Hope this helps.
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