英文:
How to qualify name of a field when using generated types
问题
怎样在这样的函数中给字段命名合格：
let sortedIssues :: [Issue] = sortOn updatedAt issues
我的 issues 表中有一个 updated_at 列。然而，我还有另一个表格，其中也有一个 updated_at 列，所以编译器不知道我在上面的函数中指的是哪一个。
尝试将上述内容标识为 Issue.updatedAt 不起作用，因为没有 Issue 模块。由于 IHP 生成的类型都在同一个模块中，导入 Generated.Types 也没有帮助。
英文:
How do you qualify the name of a field within a function like this:
let sortedIssues :: [Issue] = sortOn updatedAt issues
I have an issues table with an updated_at column. However, I also have another table with an updated_at column so the compiler does not know which one I am referring to in the above function.
Trying to qualify the above as Issue.updatedAt does not work since there is no Issue module. The IHP-generated types are all within just one module as well, so importing Generated.Types does not help.
答案1
得分: 2
最好在这里使用点表示法以避免此问题：
let sortedIssues :: [Issue] = sortOn (.updatedAt) issues
这种简写形式是以下代码的缩写：
let sortedIssues :: [Issue] = sortOn (\issue -> issue.updatedAt) issues
英文:
It's best to use dot notation here to avoid this problem:
let sortedIssues :: [Issue] = sortOn (.updatedAt) issues
This short form notation is a shorthand for this:
let sortedIssues :: [Issue] = sortOn (\issue -> issue.updatedAt) issues
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