如何在按键时更改PShape的颜色？

huangapple
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英文:

How to change the color of a PShape on key press?

问题

我正在尝试在按下键时更改PShape的颜色，以作为按下该键的标记。是否有一种方法可以在不使用beginShape()和endShape()以及新的填充重新定义PShape的情况下实现这一点？

以下是我尝试的示例：

  1. PShape s;
  3. void setup() {
  4.   size(100, 100);
  5.   s = createShape(RECT, 25, 25, 50, 50);
  6.   s.setFill(color(75, 183, 19));
  8.   shape(s);
  9. }
  11. void draw() {
  12.   if (keyPressed == true) {
  13.     if (key == 'w') {
  14.       s.setFill(color(217, 93, 47));
  15.     }
  16.   }
  17. }

setFill()函数在将形状放入窗口之前起作用，但在draw()函数中不起作用。我还尝试使用fill()。

我还尝试在声明形状并在重新绘制形状之前更改填充时使用disableStyle()：

  1. PShape s;
  3. void setup() {
  4.   size(100, 100);
  5.   shape();
  6.   fill(75, 183, 19);
  8.   shape(s);
  9. }
  11. void draw() {
  12.   if (keyPressed == true) {
  13.     if (key == 'w') {
  14.       fill(217, 93, 47);
  15.       shape();
  16.     }
  17.   }
  18. }
  20. void shape() {
  21.   s = createShape(RECT, 25, 25, 50, 50);
  22.   s.disableStyle();
  23. }

这也不起作用，形状仍然保持为第一种颜色。我是否遗漏了任何函数可以帮助我实现这一点？

英文:

I am trying to change the color of a PShape when I press a key, as a marker that that key is pressed. Is there a way that I can do this without redefining the PShape using beginShape() and endShape() with a new fill every time?

Here is an example of what I am attempting to do:

  1. PShape s;
  3. void setup() {
  4.   size(100,100);
  5.   s = createShape(RECT,25,25,50,50);
  6.   s.setFill(color(75,183,19));
  7.   
  8.   shape(s);
  9. }
  11. void draw() {
  12.   if(keyPressed == true) {
  13.     if(key == 'w') {
  14.       s.setFill(color(217,93,47));
  15.     }
  16.   }
  17. }

the setFill() function works before I actually put the shape into the window, but it won't in the draw() function. I have also tried using fill().

I have also tried using disableStyle() when declaring the shape and changing the fill before redrawing the shape:

  1. PShape s;
  3. void setup() {
  4.   size(100,100);
  5.   shape();
  6.   fill(75,183,19);
  7.   
  8.   shape(s);
  9. }
  11. void draw() {
  12.   if(keyPressed == true) {
  13.     if(key == 'w') {
  14.       fill(217,93,47);
  15.       shape();
  16.     }
  17.   }
  18. }
  20. void shape() {
  21.   s = createShape(RECT,25,25,50,50);
  22.   s.disableStyle();
  23. }

This also doesn't work, the shape just stays as the first color. Is there any function I am missing which will help me to achieve this?

答案1

得分: 0

以下是代码的翻译部分：

  1. PShape s;
  2. color chosenColor;
  4. void setup() {
  5.   size(100,100);
  6.   chosenColor = color(random(255), random(255), random(255));
  7. }
  9. void draw() {
  10.   myShape();
  11. }
  13. void myShape() {
  14.   s = createShape(RECT,25,25,50,50);
  15.   s.setFill(chosenColor);
  16.   shape(s);
  17. }
  19. void keyPressed() {
  20.   if (key == 'w') {
  21.     chosenColor = color(random(255), random(255), random(255));
  22.   }
  23. }
英文:

The following code will change the color of a PShape square each time a designated key is pressed:

  1. PShape s;
  2. color chosenColor;
  4. void setup() {
  5.   size(100,100);
  6.   chosenColor = color(random(255), random(255), random(255));
  7. }
  9. void draw() {
  10.   myShape();
  11. }
  13. void myShape() {
  14.   s = createShape(RECT,25,25,50,50);
  15.   s.setFill(chosenColor);
  16.   shape(s);
  17. }
  19. void keyPressed() {
  20.   if (key == 'w') {
  21.     chosenColor = color(random(255), random(255), random(255));
  22.   }
  23. }

huangapple
  • 本文由 发表于 2023年3月31日 22:20:27
  • 转载请务必保留本文链接：https://go.coder-hub.com/75899619.html
  • colors
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