英文:
Get twodimensional array positions out of integer
问题
我正在从图像中加载像素。
对于每个像素，我检查颜色并创建图像，现在我想将此图像添加到二维数组中。
int MAPWIDTH = 64; // 像素
int MAPHEIGHT = 16; // 像素
PImage[][] forGroundMap;
PImage file = loadImage(path);
file.loadPixels();
int size = file.width * file.height;
for (int i = 0; i < size; i++) {
int x = i % MAPWIDTH;
int y = i / MAPWIDTH;
// forGroundMap[y][x] == 在这里写入相应的内容
}
供参考：这些图像的高度始终为64，宽度为32。
为了获取位置，我尝试通过当前迭代除以宽度，以知道我当前所在的行。
int divideBy(int number, int timesIn) {
int count = 0;
while (number >= timesIn) {
number = number - timesIn;
count++;
println(number);
}
return count;
}
然而，这不能给我当前行内的列，并且我不确定这是否会起作用，以及如何继续前进。
英文:
I am loading pixels out of an image.
for every pixel I check the color and create an image, I now want to add this image inside of an two dimensional array.
int MAPWIDTH = 64; // in pixels
int MAPHEIGHT = 16; // in pixel
PImage[][] forGroundMap;
PImage file = loadImage(path);
file.loadPixels();
int size = file.width * file.height;
for (int i = 0; i < size; i++) {
int y = divideBy(i, MAPWIDTH);
//forGroundMap[y][x] == something what is x and y here
}
For reference: The images are always 64 in height and 32 in width.
To get the position I have tried to divide the current iteration by the width to know what row I am currently at.
int divideBy(int number, int timesIn) {
int count = 0;
while (number >= timesIn) {
number = number - timesIn;
count++;
println(number);
}
return count;
}
This however doesn't give me back the column inside my row And I am not sure if this will work at all and how to continue forward.
答案1
得分: 1
以下是翻译好的内容：
你似乎想要的是简单的除法数学运算。
int y = 1 / 64;
System.out.println(y);
y = 65 / 64;
System.out.println(y);
编辑
要同时获取 x 值，可以使用取余运算。
int x = 1 / 64;
int y = 1 % 64;
System.out.printf("你在位置 [%d,%d]%n", x, y);
x = 65 / 64;
y = 65 % 64;
System.out.printf("你在位置 [%d,%d]%n", x, y);
英文:
What you appears to be wanting is simple division math.
int y = 1 / 64;
System.out.println (y);
y = 65 / 64;
System.out.println (y);
edit
To get the x value as well use modulo
int x = 1 / 64;
int y = 1 % 64;
System.out.printf ("you are at [%d,%d]%n", x,y);
x = 65 / 64;
y = 65 % 64;
System.out.printf ("you are at [%d,%d]%n", x,y);
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