英文:
How to merge multiple dataframes with different rows using dplyr
问题
以下是代码部分的翻译：
我在R中有以下数据框，它们都具有不同数量的行和不同的日期。data1 <- structure(list(Date = structure(c(18628, 18629, 18630, 18631), class = "Date"),Value1 = c(1, 2, 3, 4)), row.names = c(NA, -4L), class = c("tbl_df","tbl", "data.frame"))data2 <- structure(list(Date = structure(c(18628, 18632, 18633), class = "Date"),Value2 = c(1, 2, 3)), row.names = c(NA, -3L), class = c("tbl_df","tbl", "data.frame"))data3 <- structure(list(Date = structure(c(18626, 18629, 18633, 18634,18635), class = "Date"), Value3 = c(1, 2, 3, 4, 5)), row.names = c(NA,-5L), class = c("tbl_df", "tbl", "data.frame"))
我想将它们全部合并成一个数据框。通常情况下，我会使用full_join，但这仅适用于两个数据框，如下所示：
library(tidyverse)data <- full_join(data1, data2, by = 'Date') %>%arrange(Date)
是否有一种简单的方法可以将超过2个数据框合并成一个数据框？
英文:
I have the following dataframes in R, which all have a different number of rows and different dates in them as well.
data1 <- structure(list(Date = structure(c(18628, 18629, 18630, 18631), class = "Date"),Value1 = c(1, 2, 3, 4)), row.names = c(NA, -4L), class = c("tbl_df","tbl", "data.frame"))data2 <- structure(list(Date = structure(c(18628, 18632, 18633), class = "Date"),Value2 = c(1, 2, 3)), row.names = c(NA, -3L), class = c("tbl_df","tbl", "data.frame"))data3 <- structure(list(Date = structure(c(18626, 18629, 18633, 18634,18635), class = "Date"), Value3 = c(1, 2, 3, 4, 5)), row.names = c(NA,-5L), class = c("tbl_df", "tbl", "data.frame"))
I would like to combine all three of them into one dataframe. Usually, I would use full_join for this but that's only possible for two dataframes, like this
library(tidyverse)data <- full_join(data1, data2, by = 'Date') %>%arrange(Date)
Is there a simple way in which I can merge more than 2 dataframes into one dataframe?
答案1
得分: 2
将你的数据框收集到一个列表中并使用reduce函数：
mget(ls(pattern = "^data")) %>%reduce(full_join, by = "Date")
一个数据表：9行 × 4列
日期 值1 值2 值3
1 2021-01-01 1 1 NA
2 2021-01-02 2 NA 2
3 2021-01-03 3 NA NA
4 2021-01-04 4 NA NA
5 2021-01-05 NA 2 NA
6 2021-01-06 NA 3 3
7 2020-12-30 NA NA 1
8 2021-01-07 NA NA 4
9 2021-01-08 NA NA 5
<details><summary>英文:</summary>Collect your data frames in a list and use `reduce`:```rmget(ls(pattern = "^data")) %>%reduce(full_join, by = "Date")# A tibble: 9 × 4Date Value1 Value2 Value3<date> <dbl> <dbl> <dbl>1 2021-01-01 1 1 NA2 2021-01-02 2 NA 23 2021-01-03 3 NA NA4 2021-01-04 4 NA NA5 2021-01-05 NA 2 NA6 2021-01-06 NA 3 37 2020-12-30 NA NA 18 2021-01-07 NA NA 49 2021-01-08 NA NA 5
答案2
得分: 1
使用 base R
Reduce(function(...) merge(..., all = TRUE), mget(ls(pattern = "^data\\d+$")))
-输出
Date Value1 Value2 Value31 2020-12-30 NA NA 12 2021-01-01 1 1 NA3 2021-01-02 2 NA 24 2021-01-03 3 NA NA5 2021-01-04 4 NA NA6 2021-01-05 NA 2 NA7 2021-01-06 NA 3 38 2021-01-07 NA NA 49 2021-01-08 NA NA 5
或者使用 plyr::join_all
plyr::join_all(mget(ls(pattern = "^data\\d+$")), type = "full")Date Value1 Value2 Value31 2021-01-01 1 1 NA2 2021-01-02 2 NA 23 2021-01-03 3 NA NA4 2021-01-04 4 NA NA5 2021-01-05 NA 2 NA6 2021-01-06 NA 3 37 2020-12-30 NA NA 18 2021-01-07 NA NA 49 2021-01-08 NA NA 5
英文:
Using base R
Reduce(function(...) merge(..., all = TRUE), mget(ls(pattern = "^data\\d+$")))
-output
Date Value1 Value2 Value31 2020-12-30 NA NA 12 2021-01-01 1 1 NA3 2021-01-02 2 NA 24 2021-01-03 3 NA NA5 2021-01-04 4 NA NA6 2021-01-05 NA 2 NA7 2021-01-06 NA 3 38 2021-01-07 NA NA 49 2021-01-08 NA NA 5
Or with plyr::join_all
plyr::join_all(mget(ls(pattern = "^data\\d+$")), type = "full")Date Value1 Value2 Value31 2021-01-01 1 1 NA2 2021-01-02 2 NA 23 2021-01-03 3 NA NA4 2021-01-04 4 NA NA5 2021-01-05 NA 2 NA6 2021-01-06 NA 3 37 2020-12-30 NA NA 18 2021-01-07 NA NA 49 2021-01-08 NA NA 5
答案3
得分: 0
你可以很简单地在基本的 R 中完成它：
group_data <- rbind.data.frame(data1, data2, data3)group_data
英文:
You can do it in base R quite simply:
group_data<-rbind.data.frame(data1,data2,data3)group_data
答案4
得分: 0
full_join(data1, data2) %>%full_join(., data3)Joining, by = "Date"# A tibble: 9 × 4Date Value1 Value2 Value3<date> <dbl> <dbl> <dbl>1 2021-01-01 1 1 NA2 2021-01-02 2 NA 23 2021-01-03 3 NA NA4 2021-01-04 4 NA NA5 2021-01-05 NA 2 NA6 2021-01-06 NA 3 37 2020-12-30 NA NA 18 2021-01-07 NA NA 49 2021-01-08 NA NA 5
英文:
full_join(data1, data2) %>%full_join(., data3)Joining, by = "Date"# A tibble: 9 × 4Date Value1 Value2 Value3<date> <dbl> <dbl> <dbl>1 2021-01-01 1 1 NA2 2021-01-02 2 NA 23 2021-01-03 3 NA NA4 2021-01-04 4 NA NA5 2021-01-05 NA 2 NA6 2021-01-06 NA 3 37 2020-12-30 NA NA 18 2021-01-07 NA NA 49 2021-01-08 NA NA 5
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