英文:
How to update dictionary with indexes
问题
我有一个列表和字典
我需要根据列表更新我的字典
如果字典中有与列表中相同名称的键，则我需要获取列表项的索引，并将其设置为相同字典项的键
list_1 = ['item 0', 'item 1', 'item 2', 'item 3', 'item 4', 'item 5', 'item 6']
dic_1 = {'item 3': 'val 3', 'item 1': 'val 1', 'item 5': 'val 5'}
我尝试使用以下代码部分，但无法获得我期望的结果
for index, column in enumerate(list_1):
if column in list(dic_1.keys()):
print(f"header : {index} - {column} | align : {list(dic_1).index(column)} - {dic_1[column]}")
dic_1[column[0]] = dic_1.pop(list(dic_1.keys())[0])
else:
pass
我期望的结果是：
dic_1 = {3: 'val 3', 1: 'val 1', 5: 'val 5'}
请帮助我实现这个。
英文:
I have a list and dictionary
I need to update my dictionary depend on the list
If dictionary has key existing on list on same name, so then I need to get the index of the list item
and set it as a key of the same dictionary item
list_1 = ['item 0', 'item 1', 'item 2', 'item 3', 'item 4', 'item 5', 'item 6']
dic_1 = {'item 3': 'val 3', 'item 1': 'val 1', 'item 5': 'val 5'}
I tried it with this coding part but couldn't get which I expected result
for index, column in enumerate(list_1):
if column in list(dic_1.keys()):
print(f"header : {index} - {column} | align : {list(dic_1).index(column)} - {dic_1[column]}")
dic_1[column[0]] = dic_1.pop(list(dic_1.keys())[0])
else:
pass
I expected result:
dic_1 = {3: 'val 3', 1: 'val 1', 5: 'val 5'}
Please help me to do this
答案1
得分: 7
你不能以那种方式编辑一个字典。使用：
new_dic = {list_1.index(x):y for x, y in dic_1.items()}
将得到：
{3: 'val 3', 1: 'val 1', 5: 'val 5'}
英文:
You can't edit a dictionary in that way. Use:
new_dic = {list_1.index(x):y for x, y in dic_1.items()}
which gives:
{3: 'val 3', 1: 'val 1', 5: 'val 5'}
答案2
得分: 3
你可以这样做。
result = {}
for key, value in dic_1.items():
if key in list_1:
result[list_1.index(key)] = value
英文:
You can do it like this.
result = {}
for key,value in dic_1.items():
if key in list_1:
result[list_1.index(key)]=value
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