英文:
Telegram through telethon timeouts on my server. FloodWaitError keeps multiplying on a script that works fine on local
问题
应用在我的个人电脑上运行正常，没有超时。当我将其关闭以将其移到服务器上时，首次在使用电话号码、密码和登录代码登录会话后，出现了以下错误：
telethon.errors.rpcerrorlist.FloodWaitError: 需要等待 31387 秒（由 ResolveUsernameRequest 引起）
在以下代码行：
client.get_messages(channel_name, ids=141)
我等待的时间远远超过了约 8 小时。
我的个人电脑上的程序一直正常运行。我再次停止它并在服务器上运行相同的脚本。
现在等待时间加倍：
telethon.errors.rpcerrorlist.FloodWaitError: 需要等待 67203 秒（由 ResolveUsernameRequest 引起）
在相同的代码行上。无法使用。
这是我自己的频道，由我登录的帐户拥有，我收到这条消息...
英文:
The application works fine on my PC. No timeouts. When I turned it off to move it to my server, at first after logging into the session with phone number, password, and login code, this error appeared:
telethon.errors.rpcerrorlist.FloodWaitError: A wait of 31387 seconds is required (caused by ResolveUsernameRequest)
on line
client.get_messages(channel_name, ids=141)
I waited way longer than the ~8+ hours.
My PC program was working fine. I again stopped it and opened the same script on my server.
Now the wait is doubled:
telethon.errors.rpcerrorlist.FloodWaitError: A wait of 67203 seconds is required (caused by ResolveUsernameRequest)
on same line. Unusable.
This is MY OWN channel owned by the very account I sign in to that I'm getting the message from...
答案1
得分: 1
你的问题标题提到你“无法登录”，但你的问题正文似乎表明情况并非如此。我将假设你的问题是问题正文中描述的情况。
Telethon将使用.session文件作为缓存，其中包含用户名及其对应的id和access_hash等信息。这两个值都是作为API请求的参数使用时所需的。
如果用户名不在缓存中，库将需要首先获取它。这个获取操作会有一个较长的洪水等待时间，无法绕过。
在这种情况下，正确的方法是：
print(await client.get_input_entity(channel_name))
一次，然后在你的脚本中将输出硬编码，如下所示：
from telethon import types
CHANNEL = types.InputPeerChannel(channel_id=..., access_hash=...)
（你可以使用不同的机制来持久存储它。硬编码只是最简单的方法。）
然后你可以使用CHANNEL代替channel_name。
英文:
Your question title mentions you "can't login", but your question body seems to indicate otherwise. I will assume your problem is what's described in the question's body.
Telethon will use the .session file as a cache, containing, among other things, usernames and their corresponding id and access_hash. Both of these values are required to use a chat as a parameter for the API requests.
If the username is not in cache, the library will need to fetch it first. This fetching has a high flood wait, and there's no way to bypass that.
The correct approach here would be to:
print(await client.get_input_entity(channel_name))
once, and then hardcode the output in your script, like so:
from telethon import types
CHANNEL = types.InputPeerChannel(channel_id=..., access_hash=...)
(You can use a different mechanism to store it persistently. Hardcoding it is just the simplest way to do it.)
And then you can use CHANNEL instead of channel_name.
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