英文:
Can not reshape 2 dimensional array to 3 dimensional array for RNN in python
问题
我无法将数组重塑为三维数组。以下是示例数据集：
import pandas as pdimport numpy as npdf = {"a": [0.06, 0.07, 0.45, 0.98, 0.97],"b": [12, 45, 65, 56, 34],"c": [2, 5, 5, 5, 3],"d": [23, 55, 25, 15, 34],"e": [0.0005, 0.55555, 0.383825, 0.4747477415, 0.348344334],"f": [0.0236, 0.3407, 0.4545, 0.9658, 0.4597],"g": [70, 90, 123, 154, 99],}# 加载到数据帧（DataFrame）：df = pd.DataFrame(df)print(df)
df.shapeX = df[['a', 'b', 'c', 'd', 'e', 'f']].to_numpy()y = df['g'].to_numpy()X
这是我从一个stackoverflow帖子中找到的可能解决方案：
# 将X数据重塑为3DX = X.reshape(5, 7, -1)
但对我没有起作用。我理解矩阵有其规则，但是否可能将它转换为三维数组？如果你知道的话，能帮我吗？非常感谢！
我想要得到类似于（5,7,3）的数组，最后一维的大小是3。
英文:
I can not reshape the array into 3-dimensional one. Here is the example dataset:
import pandas as pdimport numpy as npdf = {"a": [0.06 , 0.07, 0.45, 0.98, 0.97 ],"b": [12,45,65, 56, 34],"c": [2,5,5, 5, 3],"d": [23,55,25, 15, 34],"e": [0.0005,0.55555,0.383825, 0.4747477415, 0.348344334],"f": [0.0236 , 0.3407, 0.4545, 0.9658, 0.4597 ],"g": [70 , 90, 123, 154, 99 ],}#load into df:df = pd.DataFrame(df)print(df)
df.shapeX = df[['a', 'b', 'c','d','e','f']].to_numpy()y = df['g'].to_numpy()X
This is what I found as a possible solution from one of the stackoverflow posts
# Reshaping the X data to be 3DX = X.reshape(5, 7, -1)
But it did not work for me. I understand that matrix has its rules, however, is it possible to convert it into three dimensional array? Could you help me if you know? Thank you very much!
I want to get something like (5,7,3). The array that end with the 3.
答案1
得分: 0
我认为你需要执行以下操作：
X = df[['a', 'b', 'c', 'd', 'e', 'f']].to_numpy()y = df['g'].to_numpy()
X的形状是(5, 6)
df[['a', 'b', 'c', 'd', 'e', 'f']].to_numpy().reshape(5, 6, -1)
由于你已经将 'g' 移到了 y 中，所以可以这样重塑X：
X = X.reshape(5, 6, -1)
其他变体包括：
X = X.reshape(2, 5, 3)X = X.reshape(5, 2, 3)X = X.reshape(10, 1, 3)X = X.reshape(1, 10, 3)
实际上，这些数字的乘积应该等于形状的乘积。因此，在这种情况下，(5, 6) 的乘积是 30。
现在，你想要一个末尾为 3 的三维数组，所以我们需要从前两个维度获取 10。
英文:
I think you have to do:
X = df[['a', 'b', 'c','d','e','f']].to_numpy()y = df['g'].to_numpy()
X.shape is (5, 6)
df[['a', 'b', 'c','d','e','f']].to_numpy().reshape(5,6,-1)
Since you have moved 'g' out to y
X = X.reshape(5, 6, -1)
Other variants are:
X=X.reshape(2, 5, 3)X=X.reshape(5, 2, 3)X=X.reshape(10, 1, 3)X=X.reshape(1, 10, 3)
How we get them, actually the product of these numbers should be the product of shape. So, in this case product of (5,6) is 30.
Now, you want a 3D array with 3 at the end, so we need 10 from the first 2 dimensions.
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