英文:
An undefined letter appears?
问题
我运行以下代码片段。由于某种原因，我无法理解，在指定文件位置时，路径中出现了一个“b”。
# %% 定义
path_root = normpath(r'G:\Dropbox\temp\')
path_start = normpath(r'G:\Dropbox\temp\worklayers\')
path_temp = normpath(r'G:\Dropbox\temp\templayers\')
path_temp2 = normpath(r'G:\Dropbox\temp\temp2layers\')
path_end = normpath(r'G:\Dropbox\temp\resultlayers\')
path_doc = normpath(r'G:\Dropbox\Documents\')
directory = os.fsencode(path_start)
df = pd.read_csv(path_doc+'\\DEM_masterfile.csv')
slope_list = [4, 4.9, 5.9, 7.1, 8.2, 10, 11.8, 13.8, 15.7, 17.9, 20.6, 25]
aspect_list_1 = [[0, 15], [15, 30], [30, 45], [45, 60], [60, 75], [75, 90], [90, 105], [105, 120], [120, 135], [135, 150], [150, 165], [165, 180]]
aspect_list_2 = [[180, 195], [195, 210], [210, 225], [225, 240], [240, 255], [255, 270], [270, 285], [285, 300], [300, 315], [315, 330], [330, 345], [345, 360]]
# %% 从DEM栅格生成坡度和坡向向量文件
for number in os.listdir(directory):
processing.run("native:slope", {'INPUT':path_start+'\\'+str(number),'Z_FACTOR':1,'OUTPUT':path_temp+'\\'+'slope_'+str(number)})
processing.run("native:aspect", {'INPUT':path_start+'\\'+str(number),'Z_FACTOR':1,'OUTPUT':path_temp+'\\'+'aspect_'+str(number)})
当运行时，出现以下错误消息：“无法加载输入的源图层：G:\Dropbox\temp\worklayers\b'hej0.tif' 未找到”。
这个错误消息中的“b”是从哪里来的？G:\Dropbox\temp\worklayers\b'hej0.tif'
英文:
I'm running the following snippet. For some reason, which I don't get, a "b" appears in the path when stating the location of a file.
# %% Definitions
path_root = normpath(r'G:\\Dropbox\\temp\\')
path_start = normpath(r'G:\\Dropbox\\temp\\worklayers\\')
path_temp = normpath(r'G:\\Dropbox\\temp\\templayers\\')
path_temp2 = normpath(r'G:\\Dropbox\\temp\\temp2layers\\')
path_end = normpath(r'G:\\Dropbox\\temp\\resultlayers\\')
path_doc = normpath(r'G:\\Dropbox\\Documents\\')
directory = os.fsencode(path_start)
df = pd.read_csv(path_doc+'\\DEM_masterfile.csv')
slope_list = [4, 4.9, 5.9, 7.1, 8.2, 10, 11.8, 13.8, 15.7, 17.9, 20.6, 25]
aspect_list_1 = [[0, 15], [15,30], [30, 45], [45, 60], [60, 75], [75, 90], [90, 105], [105, 120], [120, 135], [135, 150], [150, 165], [165, 180]]
aspect_list_2 = [[180, 195], [195, 210], [210, 225], [225, 240], [240, 255], [255, 270], [270, 285], [285, 300], [300, 315], [315, 330], [330, 345], [345, 360]]
# %% Generating the slope and aspect vector files from the DEM raster
for number in os.listdir(directory):
processing.run("native:slope", {'INPUT':path_start+'\\'+str(number),'Z_FACTOR':1,'OUTPUT':path_temp+'\\'+'slope_'+str(number)})
processing.run("native:aspect", {'INPUT':path_start+'\\'+str(number),'Z_FACTOR':1,'OUTPUT':path_temp+'\\'+'aspect_'+str(number)})
When running this the following error appears Could not load source layer for INPUT: G:\Dropbox\temp\worklayers\b'hej0.tif' not found
Where is that b in the error message coming from?? G:\Dropbox\temp\worklayers\b'hej0.tif'
答案1
得分: 2
os.fsencode(path_start) 返回一个 bytes 实例。然后 os.listdir(directory) 返回一个 bytes 列表，因为你将 bytes 作为其参数。
b'...' 是在 bytes 实例上调用 str(...) 的结果。我不确定在这段代码中使用 os.fsencode 最初的原因，导致最终得到 bytes。
要将 bytes 转换为字符串，你可以使用 decode() 或 os.fsdecode，它是 os.fsencode 的反向操作。
英文:
os.fsencode(path_start) returns an instance of bytes.
Then os.listdir(directory) returns a list of bytes because you gave bytes as its argument.
The b'...' is the result of calling str(...) on an instance of bytes.
I'm not sure what the reason was for using os.fsencode in this code and ending up with bytes.
To convert a bytes to a string, you could use decode() or os.fsdecode, the reverse of os.fsencode.
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