英文:
Convert units in a netcdf file efficiently
问题
我有降水单位为kg m-2 s-1的netcdf数据。我想将其转换为毫米（1 kg/m2/s = 86400毫米/天）。我的计划是将数据转换为数据框，然后遍历每个单元格。是否有更简单的方法来实现这一目标？
英文:
I have netcdf data with precipitation units in kg m-2 s-1. I want to convert it to mm. (1 kg/m2/s = 86400 mm/day)
my plan would be to change the data to a dataframe and then go over each cell.
is there an easier way to achieve this?
答案1
得分: 1
考虑使用 terra 软件包。它专门用于处理栅格数据，而且它的大多数例程都是内存安全的，而且速度相当快，因为它是用 C++ 编写的，而不是纯 R。
你可以尝试像这样做：
library(terra)
x <- rast("file.nc")
y <- x * 86400
英文:
Consider using the terra package. It was made to work with raster data and most of its routines are memory safe and quite fast since it is written in C++ instead of pure R.
You can probably do something like this
library(terra)
x <- rast("file.nc")
y <- x * 86400
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