英文:
(APL) About the power and circle functions
问题
*○0j1为什么输出-1，但*(○0j1)不输出？(¯1j1e¯16)
它们之间有什么区别？
预期*(○0j1)输出与*○0j1相同。
英文:
Why does *○0j1 outputs -1 but *(○0j1) doesn’t? (¯1j1e¯16)
What is the difference between them?
Expected *(○0j1) to output the same thing as *○0j1
答案1
得分: 2
假设这是Dyalog APL，那么这是因为*○0j1被识别为一个习语，精确的期望结果被返回，而不是计算为*(○0j1)。
Dyalog的习语列表在这里。
英文:
Assuming this is Dyalog APL, then it's because *○0j1 is recognised as an idiom and the exact expected result is returned rather than being calculated as *(○0j1) is.
Dyalog's idiom list is here
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