perl在目录中使用通配符匹配文件。

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英文:

perl glob files in directory

问题

我正在使用glob来读取某个目录中存在的*_file.log文件,但下面的代码似乎不起作用。

示例路径中有以下几个文件:

/user/home/xpath/logs/
abc_file.log
def_file.log
x.txt

代码:

my $home = "/user/home";

if (glob ("${home}/xpath/logs/*_file.log")){
print "工作\n";
}
else {
print "有些问题\n";
}
英文:

I am using glob to read *_file.log exist in certain directory but below code seems not working.

Example path having these few files:

/user/home/xpath/logs/
abc_file.log
def_file.log
x.txt

Code:

my $home = "/user/home";

if (glob ("${home}/xpath/logs/\*_file.log")){
print "work\n";
}
else {
print "something wrong\n"
}

答案1

得分: 2

如已解释,需要检索来自glob的所有匹配项。鉴于glob是一个具有很长记忆的“非常全球”的东西,最好在列表上下文中使用它,以立即耗尽其返回,并进行调查。执行问题尝试的一种方法如下:

if ( my @entries = glob "$home/xpath/logs/*_file.log" ) {
    print "file: $_\n" for @entries;
}
else {
    print "未找到此类条目\n";
}

我清理了一些不必要的语法元素。

一些建议:

  • 如果您真的要使用主目录,环境变量可以在%ENV哈希中使用,如$ENV{HOME}(或参见File::HomeDir

  • feature say会在打印输出中添加换行符,使其更加美观。例如,我们可以这样写:

    say for @files;
    

    需要通过use feature qw(say);启用,或者通过use Perl 版本5.10或更新版本,或者通过use一些启用它的包/框架

  • 一旦您使用glob,还可以查看File::Glob,它提供了一个良好处理名称中的空格的可替代方法。

英文:

As explained, all matches from the glob need be retrieved. Given that glob is a "very" global creature with long memory better use it in list context to exhaust its return right away, and then investigate it. One way to do what the question tries

if ( my @entries = glob "$home/xpath/logs/*_file.log" ) {
    print "file: $_\n" for @entries;
}
else {
    print "No such entries found\n"
}

I cleaned up some of unneeded syntax elements.

A few comments

  • If you really mean to use the home directory, the environment variable is available in the %ENV hash, as $ENV{HOME} (or see File::HomeDir)

  • The feature say adds a newline to prints making them far nicer. For example, we can say

    say for @files;
    

    It need be enabled by use feature qw(say);, or by use-ing a Perl version 5.10 or newer, or by use-ing some of a number of packages/frameworks that enable it

  • Once you reach for glob also have a look at File::Glob, which provides a drop-in replacement that handles spaces in names nicely.

答案2

得分: 1

使用 `if glob` 是错误的。

```none
$ ls
a.log
b.log

$ perl -Mv5.14 -e'
   sub test { say "$_[0]: ", glob( $_[0] ) ? "至少有一个匹配" : "没有匹配" }
   test( "*.log" );
   test( "*.txt" );
   test( "*.log" );
'
*.log: 至少有一个匹配      # 正确
*.txt: 至少有一个匹配      # 错误
*.log: 没有匹配           # 错误且矛盾

glob 在标量上下文中充当迭代器。

  • 第一次调用时,它返回第一个匹配项。
  • 第二次调用时,它返回第二个匹配项(不管参数如何)。
  • 当在返回所有结果后调用时,它返回 undef

如果你要使用 glob,你需要获取所有结果,而不仅仅是第一个。

例如,以下使用 scalar( () = ... ) 技巧 在列表上下文中调用 glob(获取所有结果)并计算其返回的项目数。

$ perl -Mv5.14 -e'
   sub test { say "$_[0]: ", ( () = glob( $_[0] ) ) ? "至少有一个匹配" : "没有匹配" }
   test( "*.log" );
   test( "*.txt" );
   test( "*.log" );
'
*.log: 至少有一个匹配
*.txt: 没有匹配
*.log: 至少有一个匹配
英文:

Using if glob is wrong.

$ ls
a.log
b.log

$ perl -Mv5.14 -e'
   sub test { say "$_[0]: ", glob( $_[0] ) ? "at least one match" : "no matches" }
   test( "*.log" );
   test( "*.txt" );
   test( "*.log" );
'
*.log: at least one match      # Correct
*.txt: at least one match      # Incorrect
*.log: no matches              # Incorrect and a contradiction

glob in scalar context acts as an iterator.

  • The first time it's called, it returns the first match.
  • The second time it's called, it returns the second match (regardless of the argument).
  • When it's called after all results have been returned, it returns undef.

If you're going to use glob, you're going to have to get all the results, not just the first.

For example, the following uses the scalar( () = ... ) trick to call glob in list context (getting all the results) and count the number of items it returns.

$ perl -Mv5.14 -e'
   sub test { say "$_[0]: ", ( () = glob( $_[0] ) ) ? "at least one match" : "no matches" }
   test( "*.log" );
   test( "*.txt" );
   test( "*.log" );
'
*.log: at least one match
*.txt: no matches
*.log: at least one match

huangapple
  • 本文由 发表于 2023年3月3日 21:11:13
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