如何改进返回true/false或抛出异常的switch case?

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英文:

How to improve switch case that returns true/false or throw an exception?

问题

给定以下代码:

private boolean isBlahTrue(final BigDecimal status) {

    switch (status.intValue()) {

        case 1:
        case 2:
        case 3:
            return true;

        case 5:
        case 6:
        case 7:
            return false;

        default:
            throw new MyAppRuntimeException("状态未知!");
    }
}

我的问题是:这种做法是好的还是坏的?

逻辑是:

1, 2, 3  --> true
5, 6, 7  --> false

但是,有人可能认为使用简单的IF语句也可以完成,比如

if (1,2,3) {true}, else {false}

但是,这样的话我就无法检查状态是否为4(这必须引发异常)。

我尝试过一些解决方案,比如使用contains,但是代码没有改善。

有什么想法可以尝试吗?

英文:

Given the following code:

private boolean isBlahTrue(final BigDecimal status) {

		switch (status.intValue()) {

			case 1:
			case 2:
			case 3:
				return true;

			case 5:
			case 6:
			case 7:
				return false;

			default:
				throw new MyAppRuntimeException("Status unknown!");
		}
	}

My question is: Is this good or bad practice?

Logic is:

1, 2, 3  --> true
5, 6, 7  --> false

But anyway one could think about that a simple IF would do the stuff too, like

if (1,2,3) {true}, else {false}

.

But then I would not check if the status is e.g. 4 (which must lead to an exception).

I tried some solutions, like contains, but the code doesn't improve.

Any ideas that I could try?

答案1

得分: 0

我建议在这种情况下使用一个 Map。

类似于

Map<Integer, Boolean> statusChecker = new HashMap<>();
statusChecker.put(1, true);
statusChecker.put(2, true);
// ...
statusChecker.put(5, false);
// ...

现在你可以进行检查

if (!statusChecker.containsKey(status)) {
    throw new RuntimeException("无效状态");
} else {
    return statusChecker.get(status);
}
英文:

I would suggest using a Map in this case.

something like

Map&lt;Integer, Boolean&gt; statusChecker = new HashMap&lt;&gt;();
statusChecker.put(1, true);
statusChecker.put(2, true);
... 
statusChecker.put(5, false);
...

Now you can do the checking

if(!statusChecker.contains(status)) {
   throw RuntimeException(&quot;invalid status&quot;);
} else {
   return statusChecker.get(status);
} 

答案2

得分: 0

已有的部分没有问题。但是,如果您正在使用Java 12或更高版本,您可以利用Java 12引入的开关表达式:

private boolean isBlahTrue(final BigDecimal status) {
    return switch (status.intValue()){
        case 1, 2, 3 -> true;
        case 5, 6, 7 -> false;
        default -> throw new MyAppRuntimeException("状态未知!");
    };
}
英文:

There is nothing wrong with what you already have. But if you are using Java12 or higher you can make use of the switch expressions introduced in Java 12:

private boolean isBlahTrue(final BigDecimal status) {
    return switch (status.intValue()){
        case 1, 2, 3 -&gt; true;
        case 5, 6, 7 -&gt; false;
        default -&gt; throw new MyAppRuntimeException(&quot;Status unknown!&quot;);
    };
}

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  • 本文由 发表于 2023年3月3日 19:33:00
  • 转载请务必保留本文链接:https://go.coder-hub.com/75626559.html
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