How can I make a function with a dictionary of occurrences from list I set later?

huangapple
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英文:

How can I make a function with a dictionary of occurrences from list I set later?

问题

这是我的实际代码：

  1. def uniqueOccurrence(item1, item2, item3):
  2.     d = {}
  3.     for i in d:
  4.         if i in d:
  5.             d[i] = d[i] + 1
  6.         else:
  7.             d[i] = 1
  8.     return d
  9.     
  10. def main():
  11.     list1 = [1]
  12.     list2 = [1,2]
  13.     list3 = [1,2,3]
  14.     
  15.     print(uniqueOccurrence(list1, list2, list3))
  16.     
  17. if __name__ == "__main__":
  18.     main()

应该返回类似这样的结果：
{1: 3, 2: 2, 3: 1}

但实际上返回一个空字典：
{}

英文:

I have a set of functions that are meant to set a dictionary with the key being the character that occurs in the lists and the items being the number of occurrences but when I run the code the dictionary is empty.

This is my actual code

  1. def uniqueOccurrence(item1, item2, item3):
  2.     d = {}
  3.     for i in d:
  4.         if i in d:
  5.             d[i] = d[i] + 1
  6.         else:
  7.             d[i] = 1
  8.     return d
  9.     
  10. def main():
  11.     list1 = [1]
  12.     list2 = [1,2]
  13.     list3 = [1,2,3]
  14.     
  15.     print(uniqueOccurrence(list1, list2, list3))
  16.     
  17. if __name__ == "__main__":
  18.     main()

It is supposed to return something like this
{1: 3, 2: 2, 3: 1}

but is returning an empty dictionary
{}

答案1

得分: 1

以下是翻译好的部分：

  1. 你不在函数中使用你的输入参数，你可以这样做：
  3. def count_elements(*lists):
  4.     element_count = {}
  5.     for lst in lists:
  6.         for element in lst:
  7.             if element in element_count:
  8.                 element_count[element] += 1
  9.             else:
  10.                 element_count[element] = 1
  11.     return element_count
  13. count_elements(list1, list2, list3)
  16. 或者使用 [Counter][1]：
  18. from collections import Counter
  20. def count_elements(*lists):
  21.     element_count = Counter()
  22.     for lst in lists:
  23.         element_count.update(lst)
  24.     return element_count
  26. count_elements(list1, list2, list3)
  28. [1]: https://docs.python.org/3/library/collections.html#collections.Counter
英文:

You do not use your input parameters in the function, you can do it like this:

  1. def count_elements(*lists):
  2.     element_count = {}
  3.     for lst in lists:
  4.         for element in lst:
  5.             if element in element_count:
  6.                 element_count[element] += 1
  7.             else:
  8.                 element_count[element] = 1
  9.     return element_count
  11. count_elements(list1, list2, list3)

Or use a Counter:

  1. from collections import Counter
  3. def count_elements(*lists):
  4.     element_count = Counter()
  5.     for lst in lists:
  6.         element_count.update(lst)
  7.     return element_count
  9. count_elements(list1, list2, list3)

huangapple
  • 本文由 发表于 2023年2月24日 08:43:19
  • 转载请务必保留本文链接：https://go.coder-hub.com/75551673.html
  • dictionary
  • function
  • python
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